提问人:Kucen 提问时间:11/6/2023 最后编辑:Kucen 更新时间:11/6/2023 访问量:77
AJAX 不请求 url 页面以获得成功响应
AJAX does not request to url page to get success response
问:
我遇到了一个问题,即 AJAX 不要求delete_data.php以获得成功响应。为什么会这样?AJAX 甚至不去 delete_data.php 执行代码。当我单击“删除数据”按钮时,它会弹出删除确认,但是当我单击“确认删除”按钮时,没有任何反应。我认为它没有执行删除数据.php中的代码。任何人都可以检查我的AJAX上的问题吗?
索引.php
<!DOCTYPE html>
<html>
<head>
<!-- Add Bootstrap CSS -->
<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/4.5.2/css/bootstrap.min.css">
</head>
<body>
<div class="container">
<!-- Button to trigger the deletion and show the modal -->
<button class="btn btn-danger" data-toggle="modal" data-target="#deleteModal">Delete Data</button>
</div>
<!-- Bootstrap Modal for the alert -->
<div class="modal fade" id="deleteModal" tabindex="-1" role="dialog" aria-labelledby="deleteModalLabel" aria-hidden="true">
<div class="modal-dialog" role="document">
<div class="modal-content">
<div class="modal-header">
<h5 class="modal-title" id="deleteModalLabel">Delete Confirmation</h5>
<button type="button" class="close" data-dismiss="modal" aria-label="Close">
<span aria-hidden="true">×</span>
</button>
</div>
<div class="modal-body">
Are you sure you want to delete the data?
</div>
<div class="modal-footer">
<button type="button" class="btn btn-secondary" data-dismiss="modal">Close</button>
<button type="button" class="btn btn-danger" id="confirmDelete">Delete</button>
</div>
</div>
</div>
</div>
<!-- Bootstrap Success Modal -->
<div class="modal fade" id="successModal" tabindex="-1" role="dialog" aria-labelledby="successModalLabel" aria-hidden="true">
<div class="modal-dialog" role="document">
<div class="modal-content">
<div class="modal-header">
<h5 class="modal-title" id="successModalLabel">Success</h5>
<button type="button" class="close" data-dismiss="modal" aria-label="Close">
<span aria-hidden="true">×</span>
</button>
</div>
<div class="modal-body">
Data has been successfully deleted.
</div>
<div class="modal-footer">
<button type="button" class="btn btn-secondary" data-dismiss="modal">Close</button>
</div>
</div>
</div>
</div>
<!-- Bootstrap Error Modal -->
<div class="modal fade" id="errorModal" tabindex="-1" role="dialog" aria-labelledby="errorModalLabel" aria-hidden="true">
<div class="modal-dialog" role="document">
<div class="modal-content">
<div class="modal-header">
<h5 class="modal-title" id="errorModalLabel">Error</h5>
<button type="button" class="close" data-dismiss="modal" aria-label="Close">
<span aria-hidden="true">×</span>
</button>
</div>
<div class="modal-body">
An error occurred while deleting the data.
</div>
<div class="modal-footer">
<button type="button" class="btn btn-secondary" data-dismiss="modal">Close</button>
</div>
</div>
</div>
</div>
<!-- Add Bootstrap JS and jQuery -->
<script src="https://code.jquery.com/jquery-3.5.1.slim.min.js"></script>
<script src="https://cdn.jsdelivr.net/npm/[email protected]/dist/js/bootstrap.bundle.min.js"></script>
<!-- Your JavaScript code -->
<script>
$(document).ready(function() {
$("#confirmDelete").click(function() {
// Make an AJAX request to your server to delete data from the database
// Upon successful deletion, show a success modal
// Otherwise, show an error modal
$.ajax({
type: "POST",
url: "delete_data.php", // Replace with your server-side script URL
success: function(response) {
if (response === "success") {
$('#deleteModal').modal('hide'); // Close the confirmation modal
$('#successModal').modal('show'); // Show a success modal
} else {
$('#deleteModal').modal('hide'); // Close the confirmation modal
$('#errorModal').modal('show'); // Show an error modal
}
}
});
});
});
</script>
</body>
</html>
delete_data.php
<?php
// Your database connection code here
//header('Content-Type: application/json');
if ($_SERVER['REQUEST_METHOD'] === 'POST') {
// Perform the data deletion operation in your database
// Replace this with your actual deletion code
// Example deletion code
$deleted = true; // Assume the data was successfully deleted
if ($deleted) {
echo "success";
} else {
echo "error";
}
/*if ($deleted) {
echo json_encode(array("status" => "success"));
} else {
echo json_encode(array("status" => "error"));
}*/
}
?>
答:
2赞
Vel
11/6/2023
#1
这里的答案都没有帮助我。问题是:我使用的是jQuery的精简版本,它删除了一些东西,ajax就是其中之一。
解决方案:只需在此处下载jQuery的常规(压缩或未压缩)版本,并将其包含在您的项目中即可。
@Gus TypeError: $.ajax(...) 不是函数?
评论
0赞
Vel
11/6/2023
use 代替<script src="https://code.jquery.com/jquery-3.7.1.min.js"></script>
<script src="https://code.jquery.com/jquery-3.5.1.slim.min.js"></script>
0赞
Kucen
11/6/2023
非常感谢先生!你真的是我的救命恩人!:“D我现在很开心。谢谢你,谢谢你,先生。我已经包含了这个脚本,但没有任何反应<script src=“code.jquery.com/jquery-3.7.1.min.js”></script> 。好吧,也许我包括 2 个 jquery,这就是它无法读取的原因?
0赞
Vel
11/6/2023
您应该只包含一次 jquery 库。不是 2 次。
1赞
Kucen
11/6/2023
哈哈,我还在学习,我现在明白了。非常感谢先生!:D
1赞
Vel
11/7/2023
将此按钮类型更改为submit
button
<button class="btn btn-primary" id="btnTambahNotis" type="button" name="submit">Tambah Notis</button>
评论