在 include 的 include 上使用 where 子句对查询进行续集

这不是最佳选择。但你可以尝试一下：

const findPlace = (id) => {
    return new Promise(resolve => {
        db.Place.findOne({
            where: {
                id: id
            }
        }).then(place => {
            db.Manefestation.findAll({
                include: [{
                    model: db.Event,
                    where: {
                        placeId: id
                    }
                }]

            }).then(manifestations => {
                const out = Object.assign({}, {
                    id: place.id,
                    name: place.name,
                    address: place.address,
                    latitude: place.latitude,
                    longitude: place.longitude,
                    manifestations: manifestations.reduce((res, manifestation) => {
                        if (manifestation.placeId === place.id || manifestation.Event.length > 0) {
                            res.push({
                                id: manifestation.id,
                                title: manifestation.id,
                                placeId: manifestation.placeId,
                                events: manifestation.Event
                            })
                        }
                        return res;
                    }, [])
                })
            })
            resolve(out);
        })
    })
}

从中，您可以获得分配给放置的所有表现形式，或者具有分配的任何事件。Manefestations 中包含的所有事件都分配给该地点。

编辑：您也可以使用以下方法：

const findPlace = (id) => {
    return new Promise(resolve => {
        db.Place.findOne({
            include: [{
                model: db.Manefestation,
                include: [{
                    model: db.Event,
                    where: {
                        placeId: id
                    }
                }]

            }],
            where: {
                id: id
            }
        }).then(place => {
            db.Manefestation.findAll({
                include: [{
                    model: db.Event,
                    where: {
                        placeId: id
                    }
                }],
                where: {
                    placeId: {
                        $not: id
                    }
                }

            }).then(manifestations => {
                place.Manefestation = place.Manefestation.concat(manifestations.filter(m=>m.Event.length>0))
                resolve(place);// or you can rename, reassign keys here
            })
        })
    })
}

在这里，我只在第一个查询中直接表现。然后，不包括和串联的表现形式。

我不知道你现在是否想通了。但解决方案如下。 使用 Sequelize 进行搜索可能会:)有趣。您必须包含在另一个包含中。如果查询速度变慢，请使用 .separate:true

Place.findAll({
          include: [           
            {
              model: Manifestation,
              attributes: ['id'],
              include: [{ 
              model: Event ,
              attributes: ['id']
               }]
            },
           ],
        })

我试图在单个查询中完成它，但您仍然需要 JavaScript 才能获得所需的输出类型。

（注意：💡您需要与地点无关的表现形式，但如果该地点存在事件，则应包括该表现形式。唯一的 SQL 方法首先在所有表之间执行 CROSS JOIN，然后过滤掉结果，这将是一个非常繁重的查询）

---

我想出了这个代码（尝试并执行），它不需要您执行 2 findAll 来获取您当前使用的所有数据。相反，它只获取 1 个查询中最终输出所需的数据。

const places = await Place.findAll({
    include: [{
        model: Manifestation,
        // attributes: ['id']
        through: {
            attributes: [], // this helps not get keys/data of join table
        },
    }, {
        model: Event,
        include: [{
            model: Manifestation,
            // attributes: ['id']
        }],
    }
    ],
});
console.log('original output places:', JSON.stringify(places, null, 2));

const result = places.map(p => {
    // destructuring to separate out place, manifestation, event object keys
    const {
        manifestations,
        events,
        ...placeData
    } = p.toJSON();

    // building modified manifestation with events array
    const _manifestations = manifestations.map(m => {
        return ({ ...m, events: [] })
    });

    // going through places->events to push them to respective manifestation events array
    // + add manifestation which is not directly associated to place but event is of that manifestation
    events.map(e => {
        const {
            manifestation: e_manifestation, // renaming variable
            ...eventData
        } = e;
        const mIndex = _manifestations.findIndex(m1 => m1.id === e.manifestationId)
        if (mIndex === -1) { // if manifestation not found add it with the events array
            _manifestations.push({ ...e_manifestation, events: [eventData] });
        } else { // if found push it into events array
            _manifestations[mIndex].events.push(eventData);
        }
    });
    // returning a place object with manifestations array that contains events array
    return ({ ...placeData, manifestations: _manifestations });
})
// filter `.filter(p => p.manifestations.length)` as used in your question
console.log('modified places', JSON.stringify(result, null, 2));