如果找到相同的标记名称，则具有角色的 XSLT 转换pf

问：

我正在进行 XSLT 转换，在实现特定转换逻辑方面需要帮助。以下是详细信息：

目的： 如果不同元素的标签相同，我想将标签中的错误连接起来。<namepf><record><errors>

输入 XML

<root>
    <record msg="File with error." status="ERROR" task="AD_CLT - Hiring/CLT">
        <client>4039</client>
        <company>84046101038328</company>
        <indcnp>1</indcnp>
        <namepf>Peter Santos</namepf>
        <ticket>A4039</ticket>
        <action>Save</action>
        <task>AD_CLT</task>
        <datenv error="Invalid registration." status="ERROR">01/11/2023</datenv>
        <horenv>09:15</horenv>
        <usuenv>34950</usuenv>
        <usubpo error="Invalid registration. 123" status="ERROR">Blenn-WEBSERVICE</usubpo>
        <indide>2</indide>
        <nreqid>HI0111091515290</nreqid>
        <idempr>01062748565</idempr>
        <idglob>69733</idglob>
        <matric error="Invalid registration. Next available number 2569999. ticket: 123 by employee 2569733." status="ERROR">2569733</matric>
        <tpRJor>1</tpRJor>
        <dataso>23/10/2023</dataso>
        <nromed>7749</nromed>
        <ufmed>GO</ufmed>
    </record>
    <record msg="File with error." status="ERROR" task="AD_CLT - Hiring/CLT">
        <client>4039</client>
        <company>84046101038328</company>
        <indcnp>1</indcnp>
        <ticket>A4039</ticket>
        <action>Save</action>
        <namepf>Peter Santos</namepf>
        <horenv>09:15</horenv>
        <usuenv>34950</usuenv>
        <usubpo error="Invalid registration. 123" status="ERROR">Blenn-WEBSERVICE</usubpo>
        <indide>2</indide>
        <nreqid>HI0111091515290</nreqid>
        <idempr error="Invalid registration. 456" status="ERROR">01062748565</idempr>
        <idglob error="Invalid registration. 789" status="ERROR">69733</idglob>
        <tpRJor>1</tpRJor>
        <dataso>23/10/2023</dataso>
        <nromed>7749</nromed>
        <ufmed>GO</ufmed>
    </record>
</root>

所需的输出 XML：

 <emailTitle><![CDATA[<record msg="File with error." status="ERROR" task="AD_CLT - Hiring/CLT">]]></emailTitle>
    <name>namepf: Peter Santos</name>
    <errors>
        <datenv error="Invalid registration." status="ERROR">01/11/2023</datenv>
        <usubpo error="Invalid registration. 123" status="ERROR">Blenn-WEBSERVICE</usubpo>
        <matric error="Invalid registration. Next available number 2569999. ticket: 123 by employee 2569733." status="ERROR">2569733</matric>
        <task error="Invalid registration. 123" status="ERROR">AD_CLT</task>
        <idempr error="Invalid registration. 456" status="ERROR">01062748565</idempr>
        <idglob error="Invalid registration. 789" status="ERROR">69733</idglob>
    </errors>
</root>

我从基本的 XSLT 开始，它对于复制状态属性为“ERROR”的元素很有用。但是，需要提出建议或修改来处理具有相同 . 的记录的错误串联。<namepf>

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
  <xsl:output method="xml" indent="yes"/>

  <!-- Match the root element -->
  <xsl:template match="root">
    <xsl:copy>
      <!-- Apply templates to child elements -->
      <xsl:apply-templates select="record[@status='ERRO']"/>
    </xsl:copy>
  </xsl:template>

  <!-- Match the 'record' element -->
  <xsl:template match="record">
    <xsl:copy>
      <!-- Copy 'record' attributes -->
      <xsl:copy-of select="@*"/>
      <!-- Apply templates to child elements with error status -->
      <xsl:apply-templates select="*[@status='ERRO']"/>
    </xsl:copy>
  </xsl:template>

  <!-- Match elements with error status -->
  <xsl:template match="*[not(self::record) and @status='ERRO']">
    <xsl:copy>
      <!-- Copy element attributes -->
      <xsl:copy-of select="@*"/>
      <!-- Copy element text content -->
      <xsl:copy-of select="text()"/>
    </xsl:copy>
  </xsl:template>
</xsl:stylesheet>