Awk 多行匹配，打印输出用换行符分隔-解网

问：

我的输入是：

Restaurant: Chik-Fil-A 
City: Columbus
State: GA
Address: 123 Biscayne Blvd
Phone: 911

Restaurant: 5 guys
City: Columbus
State: GA
Address: 123 Peachtree Rd
Phone: 911

Restaurant: KFC
City: NYC
State: NY
Address: 123 Madison Square
Phone: 911

Restaurant: Bahama Breeze
City: Orlando
State: FL
Address: 123 Madison Square
Phone: 911

我想选择哥伦布的所有餐厅：

awk -v name="Columbus" -v RS="" '$0 ~ "City: " name' file.txt

我的输出是这样的：

Restaurant: Chik-Fil-A 
City: Columbus
State: GA
Address: 123 Biscayne Blvd
Phone: 911
Restaurant: 5 guys
City: Columbus
State: GA
Address: 123 Peachtree Rd
Phone: 911

我想要的是这个：

Restaurant: Chik-Fil-A 
City: Columbus
State: GA
Address: 123 Biscayne Blvd
Phone: 911

Restaurant: 5 guys
City: Columbus
State: GA
Address: 123 Peachtree Rd
Phone: 911

我希望每个输出记录都用换行符分隔。我试过玩 FS 和 ORS，但我一直得到相同的结果。我真的很感激任何帮助。

谢谢

AWK 多行

$0 ~ "City: " name如果输入文件中存在 is 和 town of ，则将产生假匹配。您应该改用。如果你关心城镇名称中可能的（或任何其他正则表达式元字符）也会产生错误的匹配，那么添加任何对你有意义的变体。nameLondonLondonderry$0 ~ ("(^|\n)City: " name "(\n|$)").BEGIN{ gsub(/[.]/,"[&]",name) }

答：

3赞 Paolo 8/12/2023 #1

您可以设置为两个换行符以获得所需的输出：ORS

awk -v name="Columbus" -v ORS="\n\n" -v RS="" '$0 ~ "City: " name' file.txt

3赞 RavinderSingh13 8/13/2023 #2

对于使用带有正则表达式的函数的示例，请尝试以下代码。matchawk

awk -v name="Columbus" -v ORS="\n\n" -v RS="" '
match($0,"\nCity: " name"\n")
' Input_file

Awk 多行匹配，打印输出用换行符分隔

Awk multiline match, print output separated by newline

评论

评论