提问人:Bruno Duarte 提问时间:11/17/2023 最后编辑:Ted LyngmoBruno Duarte 更新时间:11/17/2023 访问量:40
我用 C 语言编写,为什么我的代码没有运行?我在 ss 上画了错误
i'm writing in c, why is my code not running? I drawn on the ss the error
问:
我不明白为什么我的终端会出现这条消息:
请输入要计算不带任何空格的百分比的第一个变量: 莫兰戈斯 PS C:\Users\TechnoStoreReparacoe\Desktop>
这是完整的代码:
#include <stdio.h>
#include <string.h>
int main (){
char name1[25] ;
char name2[25] ;
char name3[25];
char name4[25];
char name5[25];
int value1 ;
int value2 ;
int value3 ;
int value4 ;
int value5 ;
printf ("Hello mortal, this program allows you to calculate percentages of five parts that are the only components of the whole.\n");
printf ("\nPlease enter your 1st variable that you want to calculate the percentage of without any spaces:\n");
fgets (name1, 25, stdin);
printf ("\nPlease enter the value of %s:\n", name1[25]);
scanf ("%i", &value1);
printf ("\nPlease enter your 2nd variable that you want to calculate the percentage of without any spaces:\n");
fgets (name2, 25, stdin);
printf ("\nPlease enter the value of %s:\n", name2[25]);
scanf ("%i", &value1);
printf ("\nPlease enter your 3rd variable that you want to calculate the percentage of without any spaces:\n");
fgets (name3, 25, stdin);
printf ("\nPlease enter the value of %s:\n", name3[25]);
scanf ("%i", &value1);
printf ("\nPlease enter your 4th variable that you want to calculate the percentage of without any spaces:\n");
fgets (name4, 25, stdin);
printf ("\nPlease enter the value of %s:\n", name4[25]);
scanf ("%i", &value1);
printf ("\nPlease enter your 5th variable that you want to calculate the percentage of without any spaces:\n");
fgets (name5, 25, stdin);
printf ("\nPlease enter the value of %s:\n", name5[25]);
scanf ("%i", &value1);
return 0;
}
我正在制作一个概率查找程序,非常简单。 用户输入变量名称和相应的数值。 这是我的第一个程序,我不明白为什么代码运行不好
答:
0赞
chux - Reinstate Monica
#1
printf()
需要一个 char *,而不是一个 char
name1[25]
中是数组的第 25 个(从 0 开始)元素。这是在数组之外,无法读取。printf()
name1[]
char
name[]
"%s"
需要匹配的指针,即 .char *
char name1[25] ;
// printf ("\nPlease enter the value of %s:\n", name1[25]);
printf ("\nPlease enter the value of %s:\n", name1);
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