如何使用 for 循环中的每个函数

How to use for each function inside a for loop

提问人:user16881755 提问时间:10/21/2023 最后编辑:Carsten Massmannuser16881755 更新时间:10/21/2023 访问量:79

问:

我创建了一个价目表,并希望根据每个 SKU 值在每个产品下方显示价格。

我有一个数据数组,它被循环,然后被推送到 div 中。

var arr = [
  {
"sku": "552",
"title": "orange",
"price": "1.55",
"per": 1
  },
  {
"sku": "552",
"title": "orange",
"price": "2.00",
"per": 2
  },
  {
"sku": "552",
"title": "orange",
"price": "3.50",
"per": 4
  },
  {
"sku": "551",
"title": "bannana",
"price": "0.95",
"per": 1
  },
  {
"sku": "551",
"title": "bannana",
"price": "2.20",
"per": 3
  },
  {
"sku": "544",
"title": "apple",
"price": "0.70",
"per": 1
  },
  {
"sku": "501",
"title": "pear",
"price": "1.15",
"per": 1
  }
];

            
for(var i=0; i<arr.length; i++){

  var sku = arr[i].sku;
  var title = arr[i].title;
  var price = arr[i].price;
  var per = arr[i].per;

  var html = "<p>" + sku + " - " + title + "</p>";
  html +=   "<p><b>" + per + "</b> - " + price + "</p>";                    

  $("#div_1").append(html);

}
<script src="https://code.jquery.com/jquery-3.7.1.min.js"></script>
<div id="div_1"></div>

我想我需要为每个函数使用...我尝试在for循环中使用jquery foreach函数,但最终得到了奇怪的结果。

for(var i=0; i<arr.length; i++){

  var sku = arr[i].sku;
  var title = arr[i].title;
  var price = arr[i].price;
  var per = arr[i].per;

  var html = "<p>" + sku + " - " + title + "</p>";
  
  $.each(arr, function(key, value) {
  html +=   "<p><b>" + per + "</b> - " + price + "</p>";
});
                        

  $("#div_1").append(html);

}

https://jsfiddle.net/amxkwgy9/

JavaScript jQuery 数组

评论

0赞 XM01 - stands with Palestine 10/21/2023
不要使用 var use let
0赞 Carsten Massmann 10/21/2023
无需创建外部 jsfiddle。事实上,jsfiddle 对于移动设备来说不是很容易访问。您到底希望通过包含调用的第二个脚本实现什么?$.each()

答:

0赞 Prajyot Khandeparkar 10/21/2023 #1

如果你是 Web 开发的新手,我建议你使用一个简单的模板引擎,比如 mustachel,这将使你的生活变得轻松:)链接 https://github.com/janl/mustache.js/

查看您的输入,您似乎需要来自后端 API 共鸣本身的正确数据。

但是,由于您已经有了输入,您应该能够使用 groupby 功能解决问题,在这种情况下,您可以使用 JS reduce by title。https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/Reduce

下面是一个示例:

const result = products.reduce((x, y) => {
  (x[y.title] = x[y.title] || []).push(y);
    return x;
}, {});

https://jsfiddle.net/k1smzcnv/1/

1赞 Hezy Ziv 10/21/2023 #2

首先使用 groupedData 按 SKU 分组,然后迭代 arr 数组并添加每个产品。

https://jsfiddle.net/grsn27hk/

 var groupedData = {};

        // Group the data by SKU
        for (var i = 0; i < arr.length; i++) {
            var sku = arr[i].sku;

            if (!groupedData[sku]) {
                groupedData[sku] = [];
            }

            groupedData[sku].push(arr[i]);
        }

        // Display the grouped data
        for (var sku in groupedData) {
            if (groupedData.hasOwnProperty(sku)) {
                var products = groupedData[sku];
                var skuTitle = products[0].sku + " - " + products[0].title;

                var html = "<p>" + skuTitle + "</p>";

                for (var j = 0; j < products.length; j++) {
                    var product = products[j];
                    html += "<p><b>" + product.per + "</b> - " + product.price + "</p>";
                }

                $("#div_1").append(html);
            }
        }
0赞 Carsten Massmann 10/21/2023 #3

由于您还没有真正使用任何 jQuery 特定功能,因此我冒昧地使用 Vanilla JavaScript 准备了一个替代解决方案:

var arr = [
  {
"sku": "552",
"title": "orange",
"price": "1.55",
"per": 1
  },
  {
"sku": "552",
"title": "orange",
"price": "2.00",
"per": 2
  },
  {
"sku": "552",
"title": "orange",
"price": "3.50",
"per": 4
  },
  {
"sku": "551",
"title": "bannana",
"price": "0.95",
"per": 1
  },
  {
"sku": "551",
"title": "bannana",
"price": "2.20",
"per": 3
  },
  {
"sku": "544",
"title": "apple",
"price": "0.70",
"per": 1
  },
  {
"sku": "501",
"title": "pear",
"price": "1.15",
"per": 1
  }
];

const res=arr.reduce((a,c)=>{ // group according to sku:
(a[c.sku]=a[c.sku]||{title:c.title,prices:[]}).prices.push([c.per,c.price]);
 return a;
},{});
// map over all keys and values of res:
let html=Object.entries(res).map(([sku,c])=>`<p>${sku} - ${c.title}</p><p>prices:<br>${c.prices.map(([per,price])=>`<b>${per}</b> - ${price}`).join("<br>\n")}`).join("</p>\n");                    

// Append the generated HTML to #div_1:
document.getElementById("div_1").insertAdjacentHTML("beforeend",html);
<div id="div_1"></div>