为什么我的半数组测试和奇数组测试不起作用？（我用assert调试）

问：

我的任务是使用一个函数来打印一个完整的数组，也是一个半数组，也是一个只有奇数的数组。我使用 assert 和 print 语句进行调试，但没有成功。

这是我的问题。

#include <stdio.h>
#include <stdlib.h>
#include "pprint.h"

// DO NOT EDIT MAIN
/* Usage: ./mysolution [np] [n]*/

int main(int argc, char *argv[])
{
    int n = atoi(argv[2]);
    int arr[n];
    for (int i = 0; i < n; i++)
    {
        arr[i] = i;
    }

    pprintarr(arr, n, atoi(argv[1]));
    return 0;
}

这是我执行函数的地方

#include "pprint.h"
#include <stdio.h>
#include <assert.h>
#include <stdlib.h>

/*
 * pprintarr
 * AKA Pretty Print Array
 *
 * Input:
 * arr -- ptr to an integer array
 * n -- number of members in the array
 * np -- number of members to print out
 *
 * Constraints:
 * np <= n
 * np > 0
 * n > 0
 *
 * Output:
 * if np == 5, then print:
 *  [a0 a1 a2 ... an-1 an]
 * Note that "..." should be placed in the middle
 * For odd numbers, make the head longer than the tail.
 * if n == np, then "... should not be printed."
 */

void pprintarr(int *arr, int n, int np) {
    // Ensure n and np are within valid constraints
    assert(n > 0 && "The elements in the array have to be more than zero");
    assert(np <= n && "Only able to print the numbers in the array and not beyond");
    assert(np >= 0 && "Print an empty array");
    assert(arr != NULL && "Array pointer is NULL");
    assert(np == 10 && "np should be equal to 10");
   
    // If np is 0, print an empty array and return
    if (np == 0) {
        printf("[]\n");
        return;
    }

    // Begin printing the array
    printf("[");

    if (np < n) {
        int half = np / 2; // Determine the middle point

        for (int i = 0; i < half; i++) {
            printf("%d", arr[i]);

            if (i < half - 1) {
                printf(" "); // Add a space between elements in the first half
            }
        }

        if (np % 2 == 0) {
            printf("... "); // If np is even, add "..." between the two middle elements
        } else {
            printf(" "); // Add a space in the middle for odd numbers
        }

        for (int i = n - half; i < n; i++) {
            printf("%d", arr[i]);

            if (i < n - 1) {
                printf(" "); // Add a space between elements in the second half
            }
        }
    } else {
        // If np is greater than or equal to n, print the entire array
        for (int i = 0; i < n; i++) {
            printf("%d", arr[i]);

            if (i < n - 1) {
                printf(" "); // Add a space between elements except for the last one
            }
        }
    }

    // Close the array and add a newline character
    printf("]\n");
}

这是我的测试结果

Dots Placement - Points: 10
------------------------------------------------------------
  Even (100)
   ['6', '100']
    FAIL ✗ 
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
YOURS stdout: 

b''

~~~~~~~~~~
OURS : 
[0 1 2  ... 97 98 99]

b'[0 1 2  ... 97 98 99]\n' 

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
  Odd (100)
   ['7', '100']
    FAIL ✗ 
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
YOURS stdout: 

b''

~~~~~~~~~~
OURS : 
[0 1 2 3  ... 97 98 99]

b'[0 1 2 3  ... 97 98 99]\n' 

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
 Points per Test: 5.0 pts
 Total Points for Suite: 0.0 / 10 pts

我试过使用

if (np < n) {
    int half = np / 2; // Determine the middle point

    for (int i = 0; i < half; i++) {
        printf("%d ", arr[i]); // Print the first half with spaces
    }

修复半阵列测试，但它没有用。