未定义的索引和无效的 foreach() 参数 php

undefined index and invalid foreach() argument php

提问人:Darren Burgess 提问时间:4/26/2012 最后编辑:pb2qDarren Burgess 更新时间:5/22/2012 访问量:740

问:

我有一个页面,其中显示了用户已保存到MYSQL数据库的项目,并将其与复选框一起回显出来。我希望当用户单击此复选框并单击保存按钮时,记录将被删除,但我在标题中遇到了错误。

显示假期表单。

        <form action="deleteProcess.php">
<?php
        foreach($db->query($sql) as $row)
        {
            echo "<p>" . $row['title'] . "<br \>" . 
                         $row['description'] . "<br \>" . 
                         $row['link'] . "<br \>" .
                         $row['pubDate'] . 
                         "<input type='checkbox' name='del[]' value='$row/['title'/]'/>" . 
                         "</p>";    
        }
?>
        <input type="submit" name="delete" value="submit" />
        </form>

删除进程 .php

foreach($_POST['del'] as $check_value)
        {
            //takes session value and assigns it to a variable so that when a holiday is saved it can be distinguished by user
            $user = $_SESSION['name'];
            //assign the value of previous checkbox to $check
            $check = $check_value;
            //assign xpath query to variable $fav
            $fav = "channel/item [title = \"$check\"]";
            //loads instance of xml file as $holidayDoc
            $holidayDoc = simplexml_load_file('holidays.xml');
            //executes xpath search within holidays.xml and results stored in $favourites
            $favourites = $holidayDoc->xpath($fav);

        //for each element of the associative array $favourites, key will be referred to as $currentFav. 
        foreach($favourites as $currentFav)
        {
            echo "{$currentFav->link}". "<br \>";
            echo "{$currentFav->title}". "<br \>";
            echo "{$currentFav->description}". "<br \>";
            echo "{$currentFav->pubDate} ". "<br \>";
            //sql statement that states which values will be inserted into which column
            $sql = "DELETE FROM `saved_holidays` (`subscriberID`, `link`, `pubDate`, `title`, `description`) 
        VALUES ('$user', '$currentFav->link', '$currentFav->pubDate', '$currentFav->title', '$currentFav->description')";

            //connect to database then execute the sql statement.
            $db->exec($sql);
            //close connection to the database
            $db = null;

错误显示在行上,我不明白为什么它不起作用,任何帮助将不胜感激。foreach($_POST['del'] as $check_value)

注意:未定义索引:del in /var/www/vhosts/numyspace.co.uk/web_users/home/~unn_w11026991/public_html/Ass/deleteProcess.php 上线 14

警告:为 foreach() 提供的参数无效 /var/www/vhosts/numyspace.co.uk/web_users/home/~unn_w11026991/public_html/Ass/deleteProcess.php 上线 14

PHP 表单 undefined-index

评论

0赞 Ahatius 4/26/2012
您是否尝试过 _POST 美元的var_dump?有数据吗?看起来,$_POST 的 del 索引没有设置,这将导致无效的 foreach。

答:

1赞 RolandLovelock 4/26/2012 #1

您应该首先检查是否设置了 $_POST['del'],因为如果没有选中任何复选框,则不会设置。

if(isset($_POST['del'])){
    foreach($_POST['del'] as $del){}
}
3赞 Nadh 4/26/2012 #2

您的复选框根本没有从表单中发布。您需要添加到表单中。delmethod="post"

<form action="deleteProcess.php" method="post">

1赞 Stefan Pöltl 4/26/2012 #3

您可以通过 $_POST 访问复选框值,但您的 Form-Tag 没有定义方法! 你必须设置 ,否则你必须使用<form method="POST">$_GET['del']

1赞 codaddict 4/26/2012 #4

method="post"中缺少 。<form action

此外,用于删除的 SQL 语法不正确。从数据库中删除记录时,无需指定列。删除整个记录。

删除语法为:

DELETE FROM table_name WHERE condition
0赞 DonCallisto 4/26/2012 #5

这个错误非常清楚。

$_POST['del']

不存在,因为不是已发布表单中的有效字段。del

如果是复选框的名称,则首先必须通过添加到表单中来检索它们delpost action

1赞 Darren Burgess 4/26/2012 #6

您的表格中缺少您,因此没有发布任何内容,这是您的问题。method="post"