提问人:Bappaditya 提问时间:11/23/2022 更新时间:11/23/2022 访问量:104
如何在 Swift 中解析嵌套 JSON 时传递值
How to pass a value while parsing a nested JSON in Swift
问:
我想将父区域 Id 传递给它的子区域,同时根据附加的响应解析嵌套的 JSON 结构,在这里我想为每个子区域插入“parentId”,它将链接到它的直接父区域,
{
"areas": [
{
"id": "271341877549072423",
"name": "Breeze Office Tower",
"children": [
{
"id": "271341877549072424",
"name": "100 flinders street",
"position": 0,
"children": []
},
{
"id": "271341877549130929",
"name": "100 flinders street",
"position": 1,
"children": []
},
{
"id": "271341877549072425",
"name": "100 Flinder Stree",
"position": 2,
"children": [
{
"id": "271341877549072426",
"name": "Büro",
"position": 0,
"children": [
{
"id": "271341877549072427",
"name": "Dachgeschoß",
"position": 0,
"children": []
}
]
}
]
},
{
"id": "271341877549130931",
"name": "100 Flinder Stree",
"position": 3,
"children": [
{
"id": "271341877549130933",
"name": "Büro",
"position": 0,
"children": [
{
"id": "271341877549130935",
"name": "Dachgeschoß",
"position": 0,
"children": []
}
]
}
]
}
]
}
]
}
我的 JSON Codable 模型结构如下所示,
struct AreaModel: Decodable {
var areas: [NestedAreaModel]?
}
struct NestedAreaModel: Codable {
let areaId: String
let areaName: String
let children: [NestedAreaModel]
let hasChildren: Bool
var areaPosition: Int16?
var parentId: String?
var projectId: String?
enum CodingKeys: String, CodingKey {
case areaId = "id"
case areaName = "name"
case areaPosition = "position"
case children
}
init(from decoder: Decoder) throws {
let values = try decoder.container(keyedBy: CodingKeys.self)
self.areaId = try values.decode(String.self, forKey: .areaId)
self.children = try values.decode([NestedAreaModel].self, forKey: .children)
self.areaName = try values.decode(String.self, forKey: .areaName)
self.projectId = ORAUserDefaults.selectedProjectId()
self.areaPosition = try values.decodeIfPresent(Int16.self, forKey: .areaPosition)
if !self.children.isEmpty {
self.hasChildren = true
self.parentId = self.areaId
} else {
self.hasChildren = false
}
}
}
在这里,我无法设置父 ID,它始终指向自己的 ID。
答:
0赞
burnsi
11/23/2022
#1
正如我在评论中指出的那样,您需要遍历解码的子项并将其各自设置为当前 .parentId
areaId
一种可能的解决方案是:
init(from decoder: Decoder) throws {
let values = try decoder.container(keyedBy: CodingKeys.self)
self.areaId = try values.decode(String.self, forKey: .areaId)
// decode the children to a local var
var children = try values.decode([NestedAreaModel].self, forKey: .children)
self.areaName = try values.decode(String.self, forKey: .areaName)
self.projectId = ORAUserDefaults.selectedProjectId()
self.areaPosition = try values.decodeIfPresent(Int16.self, forKey: .areaPosition)
// if there are children loop over them and assign your id
if !children.isEmpty {
self.hasChildren = true
for (index, _ ) in children.enumerated(){
children[index].parentId = areaId
}
} else {
self.hasChildren = false
}
// assign to self
self.children = children
}
使用给定的 JSON 进行测试:
let decoded = try JSONDecoder().decode(AreaModel.self, from: data)
print(decoded.areas?[0].areaId)
print(decoded.areas?[0].children[0].parentId)
结果:
Optional("271341877549072423")
Optional("271341877549072423")
言论:
关于你对复杂性的评论:无论级别如何,每个孩子只运行一次。所以这个函数是 (O)n。children[index].parentId = areaId
评论
self.parentId = self.areaId
没有意义。难道你不应该遍历孩子并设置他们的 ?parentId
areaId