提问人:mattsmith5 提问时间:3/25/2021 最后编辑:mattsmith5 更新时间:4/30/2021 访问量:769
Python 使用 JsonPickle 序列化类并更改属性大小写
Python serialize a class and change property casing using JsonPickle
问:
使用 Python 和 JsonPickle,如何使用特定大小写序列化对象,例如 Camel Case、Pascal 等?下面的答案是手动完成的,但是寻找特定的 Jsonpickle 解决方案,因为它可以处理复杂的对象类型。
https://stackoverflow.com/a/8614096/15435022
class HardwareSystem:
def __init__(self, vm_size):
self.vm_size = vm_size
self.some_other_thing = 42
self.a = 'a'
def snake_to_camel(s):
a = s.split('_')
a[0] = a[0].lower()
if len(a) > 1:
a[1:] = [u.title() for u in a[1:]]
return ''.join(a)
def serialise(obj):
return {snake_to_camel(k): v for k, v in obj.__dict__.items()}
hp = HardwareSystem('Large')
print(json.dumps(serialise(hp), indent=4, default=serialise))
答:
2赞
Niloct
4/30/2021
#1
这是我的尝试。
from importlib import import_module
import inspect
import json
import jsonpickle
import re
def snake_to_camel(s):
a = s.split('_')
a[0] = a[0].lower()
if len(a) > 1:
a[1:] = [u.title() for u in a[1:]]
return ''.join(a)
def camel_to_snake(s):
snake = []
snake_len = len(s)
for idx, char in enumerate(s):
snake.append(char.lower())
if idx < snake_len - 1:
if char.islower() and s[idx+1].isupper():
snake.append('_')
return ''.join(snake)
def debug_output(obj):
output = '{}({})'
attrs = [attr + '=' + repr(getattr(obj, attr)) for attr in vars(obj)]
return output.format(obj.__class__.__name__, ', '.join(attrs))
class SoftwareSystem:
def __init__(self):
self.software_rating = 'Awesome!'
# Making debug output friendly
def __repr__(self):
return debug_output(self)
class HardwareSystem:
def __init__(self, vm_size):
self.vm_size = vm_size
self.some_other_thing = 42
self.a = 'a'
# Making debug output friendly
def __repr__(self):
return debug_output(self)
@jsonpickle.handlers.register(HardwareSystem, base=True)
@jsonpickle.handlers.register(SoftwareSystem, base=True)
class SystemHandler(jsonpickle.handlers.BaseHandler):
def flatten(self, obj, data):
for k, v in obj.__dict__.items():
data[snake_to_camel(k)] = jsonpickle.encode(v)
return data
def restore(self, obj):
# Gets reference to class
# https://stackoverflow.com/a/55559852/152016
module_path, class_name = obj['py/object'].rsplit('.', 1)
module = import_module(module_path)
class_ = getattr(module, class_name)
# Dealing with __init__ params (except first)
params = inspect.getargs(class_.__init__.__code__)
params = params.args[1:]
# Preparing dict keys
l_obj = {}
for k, v in obj.items():
l_obj[camel_to_snake(k)] = v
# Instantiating constructor params
data = {}
for k, v in l_obj.items():
if k in params:
data[k] = v
result = class_(**data)
# Setting other jsonpickled object attributes
for k, v in l_obj.items():
if not k in params:
setattr(result, k, v)
return result
hw = HardwareSystem(100)
sw = SoftwareSystem()
hw.software_instance = sw
json_str = jsonpickle.encode(hw)
print(json_str)
decoded = jsonpickle.decode(json_str)
print(hw)
这有一些假设:
- 按照你原来的函数,我提出了一个解码,它假设只有小写字母后面的第一个大写字母才会在字符前面加上(所以会翻译成 ,因此如果你再次翻译它,它将是错误的
awesomeAbc
snake_to_camel
camel_to_snake
_
awesomeABC
awesome_abc
) - 上面的代码对之后添加的属性进行编码/解码(参见上面的示例)。
__init__
hw.software_instance
- 您可以嵌套对象。我只尝试过嵌套的单个对象。
- 我添加了辅助/功能,您可以扔掉这些(或自定义:))
debug_output
__repr__
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