“dll_file”可能是“0”：这不符合函数“GetProcAddress”的规范-解网

问：

所以我想使用我创建的DLL，我有一个非常奇怪的警告，我没有看到任何人有这个。我检查了是否返回“NULL”，但事实并非如此。LoadLibray

typedef DATA_BLOB(*encryption_decryption)(DATA_BLOB, bool*);
HINSTANCE dll_file = LoadLibrary(L"dllForEncryptionNDecryptionn.dll");
if (dll_file != NULL) {
    cout << "Library loaded!" << endl;
}
else {
    failed();
}
encryption_decryption encryption = (encryption_decryption)GetProcAddress(dll_file,"encryption");
if(encryption != NULL)
{
    cout << "Workded!" << endl;
}
else
{
    failed();
}
void failed() {
    cout << GetLastError() << endl;
    cout << "Faild!" << endl;
}

第 8 行的警告：“'dll_file' 可能是 '0'：这不符合函数 'GetProcAddress' 的规范。

一切正常，当我运行它时它不会写任何错误。

C++ DLL getProcAddress

HINSTANCE dll_file = LoadLibrary(L"dllForEncryptionNDecryptionn.dll");
if (dll_file != NULL) {
    cout << "Library loaded!" << endl;
}
else {
    failed(); // returns even when dll_file is NULL
}

// so, here you don't know if it's NULL or a valid handle which is why you get the warning
encryption_decryption encryption = (encryption_decryption)GetProcAddress(dll_file,"encryption");

如果失败，则不应使用它来调用。LoadLibrarydll_fileGetProcAddress

encryption_decryption encryption = nullptr;
HINSTANCE dll_file = LoadLibrary(L"dllForEncryptionNDecryptionn.dll");

if(dll_file) {
    encryption_decryption encryption = 
        (encryption_decryption)GetProcAddress(dll_file,"encryption");
} else {
    // do NOT call GetProcAddress
}

if(encryption) {
    // function successfully loaded
}

“dll_file”可能是“0”：这不符合函数“GetProcAddress”的规范

'dll_file' could be '0': This does not adhere to the specification for the function 'GetProcAddress'

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