更改引用指针就是更改原始指针地址

问：

已为 S 分配了动态内存。S->name 已被分配到动态内存中。虽然我没有对 s->name 执行任何操作，但 s->name 在 BEFORE 和 AFTER 打印中正在更改

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

typedef struct meta_data
{
    int roll_no;
    int section;
    int age;
}meta_data;
typedef struct student
{
    meta_data mt_data;
    char* name;
}student;
int main(void)
{
    student *s = malloc(sizeof(meta_data) + 10);
    s->name = (char *)s + sizeof(meta_data);
    printf("sizeof(meta_data) = %d \n", sizeof(meta_data));
    printf("-----BEFORE-----\n");
    printf("s               = %d \n", s);
    printf("&(s->meta_data) = %d \n", &(s->mt_data));
    printf("s->name         = %d \n", s->name);
    char* ptr = s->name;
    printf("ptr = %d \n", ptr);
    ptr += 3;
    printf("ptr+3 = %d \n", ptr);
    memcpy(ptr, "sri", 3);
    printf("-----AFTER-----\n");   
    printf("s               = %d \n", s);
    printf("&(s->meta_data) = %d \n", &(s->mt_data));
    printf("s->name         = %d \n", s->name);
    return (0);
}

Output :
sizeof(meta_data) = 12
-----BEFORE-----
s               = 22638608
&(s->meta_data) = 22638608
s->name         = 22638620
ptr = 22638620
ptr+3 = 22638623
-----AFTER-----
s               = 22638608
&(s->meta_data) = 22638608
s->name         = 22636914