如何发布 Firebase 远程配置模板？[关闭]

问：

当我尝试使用 Node Js 发布新模板时，我总是遇到问题。如果我通过Firebase控制台（相同的文件）添加，那就没问题了。

我的JSON格式：

{
  "conditions": [
    {
      "name": "For English Android Users",
      "expression": "device.os == 'android' && device.language in ['en']",
      "tagColor": "GREEN"
    }
  ],
  "parameters": {
    "publish": {
      "defaultValue": {
        "value": "Testing publish"
      },
      "conditionalValues": {
        "For English Android Users": {
          "value": "Testing publish"
        }
      }
    }
  },
  "version": {
    "versionNumber": "6",
    "updateTime": "2023-11-16T15:53:30.574106Z",
    "updateUser": {
      "email": "[email protected]"
    },
    "updateOrigin": "ADMIN_SDK_NODE",
    "updateType": "INCREMENTAL_UPDATE"
  }
}

添加 etag 序列号或远程直接版本节点 json 有任何更改吗？我对这个文件应该是什么样子感到非常困惑。

我的控制器在输入路径时调用 POST 请求时调用函数：

function validateTemplate( template ) {
  return new Promise( function( resolve, reject ) {
    config
      .validateTemplate( template )
      .then( function() {
        resolve( true );
      })
      .catch( function( err ) {
        console.error( "Template is invalid and cannot be published" );
        console.error( err );
        resolve( false );
      });
  });
}

function publishTemplate( req, res, next ) {
  var template;

  try {
    upload.single( "publish" )( req, res, function( err ) {
      if ( err ) {
        return next( new Error( "Error uploading file" ));
      }

      if ( !req.file ) {
        throw new Error( "No file uploaded" );
      }

      var fileContent = fs.readFileSync( req.file.path, "UTF8" );
      template = config.createTemplateFromJSON( fileContent );

      validateTemplate( template )
        .then( function( isValid ) {
          if ( !isValid ) {
            throw new Error( "Template is invalid" );
          }
          return config.publishTemplate( template );
        })
        .then( function( publication ) {
          res.status( 200 ).send( "Template has been published" );
        })
        .catch( function( err ) {
          console.error( "Failed to publish template: ", err );
          next( err );
        });
    });
  } 
  catch ( err ) {
    return next( new Error( err ));
  }
}