提问人:user2563039 提问时间:9/10/2016 最后编辑:Communityuser2563039 更新时间:4/6/2023 访问量:137957
在 Swift 3 中正确解析 JSON
Correctly Parsing JSON in Swift 3
问:
我正在尝试获取JSON响应并将结果存储在变量中。在以前的 Swift 版本发布之前,我已经让这个代码的版本工作了,直到 Xcode 8 的 GM 版本发布。我在 StackOverflow 上看了一些类似的帖子: Swift 2 解析 JSON - 无法在 Swift 3 中下标“AnyObject”类型的值和 JSON 解析。
但是,那里传达的想法似乎不适用于这种情况。
如何在 Swift 3 中正确解析 JSON 响应? 在 Swift 3 中读取 JSON 的方式是否发生了一些变化?
下面是有问题的代码(它可以在 playground 中运行):
import Cocoa
let url = "https://api.forecast.io/forecast/apiKey/37.5673776,122.048951"
if let url = NSURL(string: url) {
if let data = try? Data(contentsOf: url as URL) {
do {
let parsedData = try JSONSerialization.jsonObject(with: data as Data, options: .allowFragments)
//Store response in NSDictionary for easy access
let dict = parsedData as? NSDictionary
let currentConditions = "\(dict!["currently"]!)"
//This produces an error, Type 'Any' has no subscript members
let currentTemperatureF = ("\(dict!["currently"]!["temperature"]!!)" as NSString).doubleValue
//Display all current conditions from API
print(currentConditions)
//Output the current temperature in Fahrenheit
print(currentTemperatureF)
}
//else throw an error detailing what went wrong
catch let error as NSError {
print("Details of JSON parsing error:\n \(error)")
}
}
}
编辑:下面是 API 调用的结果示例print(currentConditions)
["icon": partly-cloudy-night, "precipProbability": 0, "pressure": 1015.39, "humidity": 0.75, "precipIntensity": 0, "windSpeed": 6.04, "summary": Partly Cloudy, "ozone": 321.13, "temperature": 49.45, "dewPoint": 41.75, "apparentTemperature": 47, "windBearing": 332, "cloudCover": 0.28, "time": 1480846460]
答:
首先,永远不要从远程 URL 同步加载数据,始终使用异步方法,例如 .URLSession
“Any”没有下标成员
发生是因为编译器不知道中间对象是什么类型(例如,在 中),并且由于您使用的是 Foundation 集合类型,因此编译器根本不知道该类型。currently
["currently"]!["temperature"]
NSDictionary
此外,在 Swift 3 中,它需要通知编译器所有下标对象的类型。
您必须将 JSON 序列化的结果强制转换为实际类型。
此代码仅使用 Swift 本机类型URLSession
let urlString = "https://api.forecast.io/forecast/apiKey/37.5673776,122.048951"
let url = URL(string: urlString)
URLSession.shared.dataTask(with:url!) { (data, response, error) in
if error != nil {
print(error)
} else {
do {
let parsedData = try JSONSerialization.jsonObject(with: data!) as! [String:Any]
let currentConditions = parsedData["currently"] as! [String:Any]
print(currentConditions)
let currentTemperatureF = currentConditions["temperature"] as! Double
print(currentTemperatureF)
} catch let error as NSError {
print(error)
}
}
}.resume()
要打印所有键/值对,你可以写currentConditions
let currentConditions = parsedData["currently"] as! [String:Any]
for (key, value) in currentConditions {
print("\(key) - \(value) ")
}
关于jsonObject的说明(包含数据
:
许多(似乎全部)教程建议或选项在 Swift 中完全是无稽之谈。这两个选项是传统的 Objective-C 选项,用于将结果分配给对象。在 Swift 中,默认情况下,任何 iable 都是可变的,传递这些选项中的任何一个并将结果分配给常量根本没有效果。此外,大多数实现无论如何都不会改变反序列化的 JSON。.mutableContainers
.mutableLeaves
NSMutable...
var
let
在 Swift 中唯一有用的(罕见)选项是必需的,如果 JSON 根对象可以是值类型(、 或 ) 而不是集合类型 ( 或 ) 之一。但通常省略参数,这意味着没有选项。.allowFragments
String
Number
Bool
null
array
dictionary
options
===========================================================================
解析 JSON 的一些一般注意事项
JSON 是一种排列良好的文本格式。读取 JSON 字符串非常容易。仔细阅读字符串。只有六种不同的类型:两种集合类型和四种值类型。
集合类型包括
- 数组 - JSON:方括号中的对象 - Swift:但在大多数情况下
[]
[Any]
[[String:Any]]
- 字典 - JSON:大括号中的对象 - Swift:
{}
[String:Any]
值类型为
- 字符串 - JSON:双引号中的任何值,偶数或 – Swift:
"Foo"
"123"
"false"
String
- 数字 - JSON:数值不在双引号中或 – Swift:或
123
123.0
Int
Double
- 布尔 - JSON:或不在双引号中 – Swift:或
true
false
true
false
- null - JSON: – 斯威夫特:
null
NSNull
根据 JSON 规范,字典中的所有键都必须是 .String
基本上,始终建议使用可选绑定来安全地解包可选
如果根对象是字典 (),则将类型转换为{}
[String:Any]
if let parsedData = try JSONSerialization.jsonObject(with: data!) as? [String:Any] { ...
并使用 ( 是 JSON 集合或值类型,如上所述)按键检索值。OneOfSupportedJSONTypes
if let foo = parsedData["foo"] as? OneOfSupportedJSONTypes {
print(foo)
}
如果根对象是数组 (),则将类型转换为[]
[[String:Any]]
if let parsedData = try JSONSerialization.jsonObject(with: data!) as? [[String:Any]] { ...
并使用
for item in parsedData {
print(item)
}
如果需要特定索引处的项目,还要检查索引是否存在
if let parsedData = try JSONSerialization.jsonObject(with: data!) as? [[String:Any]], parsedData.count > 2,
let item = parsedData[2] as? OneOfSupportedJSONTypes {
print(item)
}
}
在极少数情况下,JSON 只是值类型之一(而不是集合类型),您必须传递选项并将结果转换为适当的值类型,例如.allowFragments
if let parsedData = try JSONSerialization.jsonObject(with: data!, options: .allowFragments) as? String { ...
Apple 在 Swift 博客中发表了一篇综合文章:在 Swift 中使用 JSON
===========================================================================
在 Swift 4+ 中,该协议提供了一种更方便的方式将 JSON 直接解析为结构/类。Codable
例如,问题中给定的 JSON 示例(略有修改)
let jsonString = """
{"icon": "partly-cloudy-night", "precipProbability": 0, "pressure": 1015.39, "humidity": 0.75, "precip_intensity": 0, "wind_speed": 6.04, "summary": "Partly Cloudy", "ozone": 321.13, "temperature": 49.45, "dew_point": 41.75, "apparent_temperature": 47, "wind_bearing": 332, "cloud_cover": 0.28, "time": 1480846460}
"""
可以解码成结构体。Swift 类型与上述相同。还有一些其他选项:Weather
- 表示 的字符串可以直接解码为 。
URL
URL
- 整数可以像使用 .
time
Date
dateDecodingStrategy
.secondsSince1970
- snaked_casedJSON 键可以通过
keyDecodingStrategy
.convertFromSnakeCase
struct Weather: Decodable {
let icon, summary: String
let pressure: Double, humidity, windSpeed : Double
let ozone, temperature, dewPoint, cloudCover: Double
let precipProbability, precipIntensity, apparentTemperature, windBearing : Int
let time: Date
}
let data = Data(jsonString.utf8)
do {
let decoder = JSONDecoder()
decoder.dateDecodingStrategy = .secondsSince1970
decoder.keyDecodingStrategy = .convertFromSnakeCase
let result = try decoder.decode(Weather.self, from: data)
print(result)
} catch {
print(error)
}
其他可编码的来源:
评论
dict!["currently"]!
Swift 3 的 Xcode 8 Beta 6 发生的一个重大变化是 id 现在导入为 而不是 .Any
AnyObject
这意味着它作为最有可能的字典返回,类型为 。如果不使用调试器,我无法确切地告诉您强制转换将执行的操作,但是您看到的错误是因为具有类型parsedData
[Any:Any]
NSDictionary
dict!["currently"]!
Any
那么,如何解决这个问题呢?从你引用它的方式来看,我认为它是一个字典,所以你有很多选择:dict!["currently"]!
首先,你可以做这样的事情:
let currentConditionsDictionary: [String: AnyObject] = dict!["currently"]! as! [String: AnyObject]
这将为您提供一个字典对象,然后您可以查询值,因此您可以像这样获得温度:
let currentTemperatureF = currentConditionsDictionary["temperature"] as! Double
或者,如果您愿意,可以排队进行:
let currentTemperatureF = (dict!["currently"]! as! [String: AnyObject])["temperature"]! as! Double
希望这会有所帮助,恐怕我没有时间编写示例应用程序来测试它。
最后一点:最简单的方法可能是在开始时直接将 JSON 有效负载转换为。[String: AnyObject]
let parsedData = try JSONSerialization.jsonObject(with: data as Data, options: .allowFragments) as! Dictionary<String, AnyObject>
评论
dict!["currently"]! as! [String: String]
会崩溃
[String: String]
根本无法工作,因为有几个数值。它在 Mac Playground 中不起作用
更新了之后,感谢这篇文章。isConnectToNetwork-Function
我为它写了一个额外的方法:
import SystemConfiguration
func loadingJSON(_ link:String, postString:String, completionHandler: @escaping (_ JSONObject: AnyObject) -> ()) {
if(isConnectedToNetwork() == false){
completionHandler("-1" as AnyObject)
return
}
let request = NSMutableURLRequest(url: URL(string: link)!)
request.httpMethod = "POST"
request.httpBody = postString.data(using: String.Encoding.utf8)
let task = URLSession.shared.dataTask(with: request as URLRequest) { data, response, error in
guard error == nil && data != nil else { // check for fundamental networking error
print("error=\(error)")
return
}
if let httpStatus = response as? HTTPURLResponse , httpStatus.statusCode != 200 { // check for http errors
print("statusCode should be 200, but is \(httpStatus.statusCode)")
print("response = \(response)")
}
//JSON successfull
do {
let parseJSON = try JSONSerialization.jsonObject(with: data!, options: .allowFragments)
DispatchQueue.main.async(execute: {
completionHandler(parseJSON as AnyObject)
});
} catch let error as NSError {
print("Failed to load: \(error.localizedDescription)")
}
}
task.resume()
}
func isConnectedToNetwork() -> Bool {
var zeroAddress = sockaddr_in(sin_len: 0, sin_family: 0, sin_port: 0, sin_addr: in_addr(s_addr: 0), sin_zero: (0, 0, 0, 0, 0, 0, 0, 0))
zeroAddress.sin_len = UInt8(MemoryLayout.size(ofValue: zeroAddress))
zeroAddress.sin_family = sa_family_t(AF_INET)
let defaultRouteReachability = withUnsafePointer(to: &zeroAddress) {
$0.withMemoryRebound(to: sockaddr.self, capacity: 1) {zeroSockAddress in
SCNetworkReachabilityCreateWithAddress(nil, zeroSockAddress)
}
}
var flags: SCNetworkReachabilityFlags = SCNetworkReachabilityFlags(rawValue: 0)
if SCNetworkReachabilityGetFlags(defaultRouteReachability!, &flags) == false {
return false
}
let isReachable = (flags.rawValue & UInt32(kSCNetworkFlagsReachable)) != 0
let needsConnection = (flags.rawValue & UInt32(kSCNetworkFlagsConnectionRequired)) != 0
let ret = (isReachable && !needsConnection)
return ret
}
因此,现在您可以轻松地在应用程序中随心所欲地调用它
loadingJSON("yourDomain.com/login.php", postString:"email=\(userEmail!)&password=\(password!)") { parseJSON in
if(String(describing: parseJSON) == "-1"){
print("No Internet")
} else {
if let loginSuccessfull = parseJSON["loginSuccessfull"] as? Bool {
//... do stuff
}
}
评论
let str = "{\"names\": [\"Bob\", \"Tim\", \"Tina\"]}"
let data = str.data(using: String.Encoding.utf8, allowLossyConversion: false)!
do {
let json = try JSONSerialization.jsonObject(with: data, options: []) as! [String: AnyObject]
if let names = json["names"] as? [String]
{
print(names)
}
} catch let error as NSError {
print("Failed to load: \(error.localizedDescription)")
}
我正是为此目的构建了 quicktype。只需粘贴示例 JSON,quicktype 就会为您的 API 数据生成以下类型层次结构:
struct Forecast {
let hourly: Hourly
let daily: Daily
let currently: Currently
let flags: Flags
let longitude: Double
let latitude: Double
let offset: Int
let timezone: String
}
struct Hourly {
let icon: String
let data: [Currently]
let summary: String
}
struct Daily {
let icon: String
let data: [Datum]
let summary: String
}
struct Datum {
let precipIntensityMax: Double
let apparentTemperatureMinTime: Int
let apparentTemperatureLowTime: Int
let apparentTemperatureHighTime: Int
let apparentTemperatureHigh: Double
let apparentTemperatureLow: Double
let apparentTemperatureMaxTime: Int
let apparentTemperatureMax: Double
let apparentTemperatureMin: Double
let icon: String
let dewPoint: Double
let cloudCover: Double
let humidity: Double
let ozone: Double
let moonPhase: Double
let precipIntensity: Double
let temperatureHigh: Double
let pressure: Double
let precipProbability: Double
let precipIntensityMaxTime: Int
let precipType: String?
let sunriseTime: Int
let summary: String
let sunsetTime: Int
let temperatureMax: Double
let time: Int
let temperatureLow: Double
let temperatureHighTime: Int
let temperatureLowTime: Int
let temperatureMin: Double
let temperatureMaxTime: Int
let temperatureMinTime: Int
let uvIndexTime: Int
let windGust: Double
let uvIndex: Int
let windBearing: Int
let windGustTime: Int
let windSpeed: Double
}
struct Currently {
let precipProbability: Double
let humidity: Double
let cloudCover: Double
let apparentTemperature: Double
let dewPoint: Double
let ozone: Double
let icon: String
let precipIntensity: Double
let temperature: Double
let pressure: Double
let precipType: String?
let summary: String
let uvIndex: Int
let windGust: Double
let time: Int
let windBearing: Int
let windSpeed: Double
}
struct Flags {
let sources: [String]
let isdStations: [String]
let units: String
}
它还生成无依赖的封送代码,以将 的返回值哄骗成 ,包括一个采用 JSON 字符串的便捷构造函数,以便您可以快速解析强类型值并访问其字段:JSONSerialization.jsonObject
Forecast
Forecast
let forecast = Forecast.from(json: jsonString)!
print(forecast.daily.data[0].windGustTime)
您可以使用 npm 安装 quicktype,或使用 Web UI 获取完整的生成代码以粘贴到您的 playground 中。npm i -g quicktype
评论
问题出在 API 交互方法上。JSON 解析仅在语法上进行了更改。主要问题在于获取数据的方式。您正在使用的是获取数据的同步方式。这并非在所有情况下都有效。您应该使用的是一种异步方式来获取数据。这样,您必须通过 API 请求数据并等待它以数据响应。您可以通过 URL 会话和第三方库(如 .下面是 URL 会话方法的代码。Alamofire
let urlString = "https://api.forecast.io/forecast/apiKey/37.5673776,122.048951"
let url = URL.init(string: urlString)
URLSession.shared.dataTask(with:url!) { (data, response, error) in
guard error == nil else {
print(error)
}
do {
let Data = try JSONSerialization.jsonObject(with: data!) as! [String:Any]
// Note if your data is coming in Array you should be using [Any]()
//Now your data is parsed in Data variable and you can use it normally
let currentConditions = Data["currently"] as! [String:Any]
print(currentConditions)
let currentTemperatureF = currentConditions["temperature"] as! Double
print(currentTemperatureF)
} catch let error as NSError {
print(error)
}
}.resume()
Swift 具有强大的类型推断功能。让我们去掉 “if let” 或 “guard let” 样板,并使用函数式方法强制展开:
- 这是我们的 JSON。我们可以使用可选的 JSON 或普通的。我在我们的示例中使用可选:
let json: Dictionary<String, Any>? = ["current": ["temperature": 10]]
- 帮助程序函数。我们只需要编写一次,然后与任何字典重用:
/// Curry
public func curry<A, B, C>(_ f: @escaping (A, B) -> C) -> (A) -> (B) -> C {
return { a in
{ f(a, $0) }
}
}
/// Function that takes key and optional dictionary and returns optional value
public func extract<Key, Value>(_ key: Key, _ json: Dictionary<Key, Any>?) -> Value? {
return json.flatMap {
cast($0[key])
}
}
/// Function that takes key and return function that takes optional dictionary and returns optional value
public func extract<Key, Value>(_ key: Key) -> (Dictionary<Key, Any>?) -> Value? {
return curry(extract)(key)
}
/// Precedence group for our operator
precedencegroup RightApplyPrecedence {
associativity: right
higherThan: AssignmentPrecedence
lowerThan: TernaryPrecedence
}
/// Apply. g § f § a === g(f(a))
infix operator § : RightApplyPrecedence
public func §<A, B>(_ f: (A) -> B, _ a: A) -> B {
return f(a)
}
/// Wrapper around operator "as".
public func cast<A, B>(_ a: A) -> B? {
return a as? B
}
- 这就是我们的魔力 - 提取价值:
let temperature = (extract("temperature") § extract("current") § json) ?? NSNotFound
只需一行代码,无需强制展开或手动铸造。此代码可在 playground 中使用,因此您可以复制并检查它。这是 GitHub 上的一个实现。
这是解决问题的另一种方法。因此,请查看以下解决方案。希望对您有所帮助。
let str = "{\"names\": [\"Bob\", \"Tim\", \"Tina\"]}"
let data = str.data(using: String.Encoding.utf8, allowLossyConversion: false)!
do {
let json = try JSONSerialization.jsonObject(with: data, options: []) as! [String: AnyObject]
if let names = json["names"] as? [String] {
print(names)
}
} catch let error as NSError {
print("Failed to load: \(error.localizedDescription)")
}
{
"User":[
{
"FirstUser":{
"name":"John"
},
"Information":"XY",
"SecondUser":{
"name":"Tom"
}
}
]
}
如果我使用以前的json创建模型 使用此链接 [博客]:http://www.jsoncafe.com 生成可编码结构或任何格式
型
import Foundation
struct RootClass : Codable {
let user : [Users]?
enum CodingKeys: String, CodingKey {
case user = "User"
}
init(from decoder: Decoder) throws {
let values = try? decoder.container(keyedBy: CodingKeys.self)
user = try? values?.decodeIfPresent([Users].self, forKey: .user)
}
}
struct Users : Codable {
let firstUser : FirstUser?
let information : String?
let secondUser : SecondUser?
enum CodingKeys: String, CodingKey {
case firstUser = "FirstUser"
case information = "Information"
case secondUser = "SecondUser"
}
init(from decoder: Decoder) throws {
let values = try? decoder.container(keyedBy: CodingKeys.self)
firstUser = try? FirstUser(from: decoder)
information = try? values?.decodeIfPresent(String.self, forKey: .information)
secondUser = try? SecondUser(from: decoder)
}
}
struct SecondUser : Codable {
let name : String?
enum CodingKeys: String, CodingKey {
case name = "name"
}
init(from decoder: Decoder) throws {
let values = try? decoder.container(keyedBy: CodingKeys.self)
name = try? values?.decodeIfPresent(String.self, forKey: .name)
}
}
struct FirstUser : Codable {
let name : String?
enum CodingKeys: String, CodingKey {
case name = "name"
}
init(from decoder: Decoder) throws {
let values = try? decoder.container(keyedBy: CodingKeys.self)
name = try? values?.decodeIfPresent(String.self, forKey: .name)
}
}
解析
do {
let res = try JSONDecoder().decode(RootClass.self, from: data)
print(res?.user?.first?.firstUser?.name ?? "Yours optional value")
} catch {
print(error)
}
斯威夫特 5无法从您的 api 获取数据。
解析 json 的最简单方法是使用协议。或 ()。
例如:Decodable
Codable
Encodable & Decodable
let json = """
{
"dueDate": {
"year": 2021,
"month": 2,
"day": 17
}
}
"""
struct WrapperModel: Codable {
var dueDate: DueDate
}
struct DueDate: Codable {
var year: Int
var month: Int
var day: Int
}
let jsonData = Data(json.utf8)
let decoder = JSONDecoder()
do {
let model = try decoder.decode(WrapperModel.self, from: jsonData)
print(model)
} catch {
print(error.localizedDescription)
}
2023年 |SWIFT 5.1 版本 |结果解决方案
数据示例:
// Codable is important to be able to encode/decode from/to JSON!
struct ConfigCreds: Codable {
// some params
}
解决方案使用示例:
var configCreds = ConfigCreds()
var jsonStr: String = ""
// get JSON from Object
configCreds
.asJson()
.onSuccess { jsonStr = $0 }
.onFailure { _ in // any failure code }
// get object of type "ConfigCreds" from JSON
someJsonString
.decodeFromJson(type: ConfigCreds.self)
.onSuccess { configCreds = $0 }
.onFailure { _ in // any failure code }
后端代码:
@available(macOS 10.15, *)
public extension Encodable {
func asJson() -> Result<String, Error>{
JSONEncoder()
.try(self)
.flatMap{ $0.asString() }
}
}
public extension String {
func decodeFromJson<T>(type: T.Type) -> Result<T, Error> where T: Decodable {
self.asData()
.flatMap { JSONDecoder().try(type, from: $0) }
}
}
///////////////////////////////
/// HELPERS
//////////////////////////////
@available(macOS 10.15, *)
fileprivate extension JSONEncoder {
func `try`<T : Encodable>(_ value: T) -> Result<Output, Error> {
do {
return .success(try self.encode(value))
} catch {
return .failure(error)
}
}
}
fileprivate extension JSONDecoder {
func `try`<T: Decodable>(_ t: T.Type, from data: Data) -> Result<T,Error> {
do {
return .success(try self.decode(t, from: data))
} catch {
return .failure(error)
}
}
}
fileprivate extension String {
func asData() -> Result<Data, Error> {
if let data = self.data(using: .utf8) {
return .success(data)
} else {
return .failure(WTF("can't convert string to data: \(self)"))
}
}
}
fileprivate extension Data {
func asString() -> Result<String, Error> {
if let str = String(data: self, encoding: .utf8) {
return .success(str)
} else {
return .failure(WTF("can't convert Data to string"))
}
}
}
fileprivate func WTF(_ msg: String, code: Int = 0) -> Error {
NSError(code: code, message: msg)
}
internal extension NSError {
convenience init(code: Int, message: String) {
let userInfo: [String: String] = [NSLocalizedDescriptionKey:message]
self.init(domain: "FTW", code: code, userInfo: userInfo)
}
}
评论