从 Apache Arrow Parquet CPP 库版本 11.0.0 读取十进制数据类型时出错

问：

我正在尝试读取一个镶木地板文件并将其存储在自定义 C 结构中，以便在我的 C 代码中进一步使用

case arrow::Type::DECIMAL:
{
    const arrow::Decimal128Type* decimal_type = static_cast<const arrow::Decimal128Type*>(arrow_table_->column(i)->type().get());
    int32_t precision = decimal_type->precision();
    int32_t scale = decimal_type->scale();
    pArrowTableDef->columns[i].array->type = DECIMAL_TYPE;
    pArrowTableDef->columns[i].array->length = pArrowTableDef->num_rows;
    pArrowTableDef->columns[i].array->data = new ArrowDecimal[pArrowTableDef->num_rows];
    for (int row_index = 0; row_index < pArrowTableDef->num_rows; ++row_index) {
        std::shared_ptr<arrow::Decimal128Array> decimal_array = std::static_pointer_cast<arrow::Decimal128Array>(chunked_array->chunk(row_index / chunk_length));
        arrow::Decimal128 value = decimal_array->Value(row_index % chunk_length);
        ArrowDecimal& arrow_decimal = static_cast<ArrowDecimal*>(pArrowTableDef->columns[i].array->data)[row_index];
        arrow_decimal.value = value.low_bits();
        arrow_decimal.precision = precision;
        arrow_decimal.scale = scale;
    }
}

获取错误：** 错误：请求从“const uint8_t* {aka const unsigned char*}”转换为非标量类型“arrow：:D ecimal128”**

自定义 C 结构：

typedef struct {
    int64_t value;     // Store the raw integer value of the decimal
    int precision;     // Store the precision of the decimal
    int scale;         // Store the scale of the decimal
} ArrowDecimal;

typedef struct {
    FieldType type;
    void *data;
    int length;
    int precision;
    int scale;
} ArrowArray;
typedef struct {
    char *name;
    ArrowArray *array;
} ArrowColumn;
typedef struct {
    int num_rows;
    int num_cols;
    ArrowColumn *columns;
} ArrowTableDef;

我也尝试使用arrow：：Buffer，但没有用