提问人:katamykenji 提问时间:11/16/2023 最后编辑:Bill Hilemankatamykenji 更新时间:11/17/2023 访问量:37
预期为标识符和预期查找“)”错误
Expected an identifier and Expected to find ')' error
问:
我是初学者编码员,我不明白如何解决这个错误
Future<http.Response> fetchData(String query) async {
return http.post(
Uri.parse('https://laravelsyd-fypfinalver.herokuapp.com/getBusService'),
headers: <String, String>{
'Content-Type': 'application/json; charset=UTF-8',
},
body: {
jsonEncode({'bus_stop_id': busCode})
},
if (response.statusCode == 200) {
final List<dynamic> data = json.decode(response.body);
dataList = List<Map<String, dynamic>>.from(data);
setState(() {// Update the state to trigger a rebuild with the fetched data
dataList = List<Map<String, dynamic>>.from(data);
},);
} else {
print (response.statusCode);
}
);
}
错误: 需要标识符。 预计会找到 ')'
我应该把 IF 放在哪里以检查状态代码?我需要创建新课程吗?
我尝试重新排列代码
答:
0赞
Munsif Ali
11/16/2023
#1
试试这段代码,希望这能解决你的问题。
Future<http.Response> fetchData(String query) async {
final response = await http.post(
Uri.parse('https://laravelsyd-fypfinalver.herokuapp.com/getBusService'),
headers: <String, String>{
'Content-Type': 'application/json; charset=UTF-8',
},
body: {
jsonEncode({'bus_stop_id': busCode})
},
);
return response;
}
评论
0赞
katamykenji
11/16/2023
它确实解决了错误,但现在它又出现了另一个错误 - [无效的请求正文“{{”bus_stop_id“:”1076“}}”。
0赞
Rosha buha
11/17/2023
#2
请试试这个代码
Future<http.Response> fetchData(String query) async {
var response = await http.post(
"https://laravelsyd-fypfinalver.herokuapp.com/getBusService",
headers: <String, String>{
'Content-Type': 'application/json; charset=UTF-8',
},
body: jsonEncode({'bus_stop_id': busCode}));
if (response.statusCode == 200) {
final List<dynamic> data = json.decode(response.body);
dataList = List<Map<String, dynamic>>.from(data);
setState(
() {
// Update the state to trigger a rebuild with the fetched data
dataList = List<Map<String, dynamic>>.from(data);
},
);
} else {
print(response.statusCode);
}}
评论