提问人:VikSil 提问时间:10/31/2023 更新时间:10/31/2023 访问量:29
是否可以从字符串制作 Django urlpatterns?
Is it possible to make Django urlpatterns from a string?
问:
我有一个字符串列表,用于在 Django 布局模板中定义导航窗格。我想对视图函数名称使用相同的列表,并使用循环来相应地在 urls.py 中定义urlpatterns。
例:
menu = ["register", "login", "logout"]
urlpatterns = [path("", views.index, name="index"),]
综上所述,我想到达
urlpatterns = [
path("", views.index, name="index"),
path("/register", views.register, name="register"),
path("/login", views.login, name="login"),
path("/logout", views.logout, name="logout"),
]
我能够将路由作为 str 传递,将 kwargs 作为字典传递,但难以将字符串转换为可调用视图函数的名称。这可能吗?
for i in menu:
url = f'"/{i}"' #works when passed as parameter to path()
rev = {"name": i} #works when passed as parameter to path()
v = f"views.{i}" #this does not work
v = include(f"views.{i}", namespace="myapp") #this does not work either
urlpatterns.append(path(url, v, rev))
答:
2赞
willeM_ Van Onsem
10/31/2023
#1
是的,您可以使用:
menu = ['register', 'login', 'logout']
urlpatterns = [
path('', views.index, name='index'),
*[path(f'{name}/', getattr(views, name), name=name) for name in menu],
]
评论