提问人:Sami 提问时间:3/6/2023 最后编辑:Drew DormannSami 更新时间:3/6/2023 访问量:48
关于在 C++ 中正确管理本地类中的引用成员的问题
question on properly managing reference members in a local class in C++
问:
我之所以得到垃圾值是因为以下原因,还是我错了?
作为参数传递给 Inner 构造函数的 Other 对象 o 在创建 Inner 对象之后,但在 get_a_value 成员函数结束之前超出范围。因此,Inner 对象中的引用成员m_o成为悬空引用,引用不再存在的对象。
#include <iostream>
class Other
{
private:
int j = 3;
friend class TEST; //class TEST is a friend of the class Other
};
class TEST
{
private:
int i = 10;
public:
int get_a_value() const //a member function of TEST
{ //member function begins
struct Inner
{
Inner(Other o) : //constructor
/*m_o{ o } it is correct too */ m_o( o )
{
std::cout << "o.j " << o.j << '\n';
std::cout << "m_o.j " << this->m_o.j << '\n';
}
int get_other_value() //other in the name of the member function refers to Other class defined above
{
return this->m_o.j;
}
Other& m_o;
};
Other o; //local variable of member function get_a_value
std::cout << "outside o.j " << o.j << '\n';
Inner i(o); //local variable of member function get_a_value
return i.get_other_value();
}//member function ends
};
int main()
{
TEST t;
std::cout << t.get_a_value() << '\n';
}
上面代码的输出是:
O.J 3 外部
O.J 3
m_o.j 3
623661
答: 暂无答案
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