Python popen 命令。等到命令完成

你要找的是等待方法。

根据您希望如何处理脚本，您有两种选择。如果您希望命令在执行时阻塞并且不执行任何操作，则可以使用 .subprocess.call

#start and block until done
subprocess.call([data["om_points"], ">", diz['d']+"/points.xml"])

如果要在执行时执行操作或将操作馈入，则可以在调用后使用。stdincommunicatepopen

#start and process things, then wait
p = subprocess.Popen([data["om_points"], ">", diz['d']+"/points.xml"])
print "Happens while running"
p.communicate() #now wait plus that you can send commands to process

如文档中所述，可能会死锁，因此建议进行沟通。wait

你可以用它来实现这一点。subprocess

import subprocess

#This command could have multiple commands separated by a new line \n
some_command = "export PATH=$PATH://server.sample.mo/app/bin \n customupload abc.txt"

p = subprocess.Popen(some_command, stdout=subprocess.PIPE, shell=True)

(output, err) = p.communicate()  

#This makes the wait possible
p_status = p.wait()

#This will give you the output of the command being executed
print "Command output: " + output

让尝试传递的命令成为

os.system('x')

然后你把它隐藏成一个声明

t = os.system('x')

现在，Python将等待命令行的输出，以便将其分配给变量。t

wait（） 对我来说效果很好。子进程 p1、p2 和 p3 同时执行。因此，所有过程都在 3 秒后完成。

import subprocess

processes = []

p1 = subprocess.Popen("sleep 3", stdout=subprocess.PIPE, shell=True)
p2 = subprocess.Popen("sleep 3", stdout=subprocess.PIPE, shell=True)
p3 = subprocess.Popen("sleep 3", stdout=subprocess.PIPE, shell=True)

processes.append(p1)
processes.append(p2)
processes.append(p3)

for p in processes:
    if p.wait() != 0:
        print("There was an error")

print("all processed finished")

强制在读取所有输出之前不继续：popen

os.popen(command).read()

我认为process.communicate（）适用于小尺寸的输出。对于更大的输出，这不是最好的方法。