提问人:hudsonhooper 提问时间:5/21/2020 更新时间:5/22/2020 访问量:79
将数据传递回上一个视图控制器(实例成员不能在类型错误时使用)
Passing data back to previous view controller (Instance member cannot be used on type error)
问:
我有 2 个值,用于跟踪用户可以在应用内购买的权益类型的当前值。我想在purchaseViewController中更新它们,并在关闭purchaseViewController后在上一个视图控制器中使用它们。我尝试使用协议/委托和回调来执行此操作。但是,我得到的错误基本上相同,两者都说“实例成员'委托/回调'不能用于类型'purchasesViewController'”。这是我第一次尝试传回数据,我主要只是按照教程进行操作,并且可能在此过程中错过了一步,但我认为这两种方法都会出现相同类型的错误,这很奇怪。
父视图控制器上的代码:
func sendBack(staticIncreases: Int, percentIncreases: Int) { //Protocol function
self.avalibleIncreases = staticIncreases
self.currentPercentIncreases = percentIncreases
}
override func prepare(for segue: UIStoryboardSegue, sender: Any?) {
if segue.identifier == "improveFromOpen"{
let next = segue.destination as! purchasesViewController
next.currentPercentIncreases = currentPercentIncreases
next.username = username
next.avalibleIncreases = avalibleIncreases
purchasesViewController.delegate = self //Error "Instance member 'delegate' cannot be used on type 'purchasesViewController'"
purchasesViewController.callback = { result in //Error "Instance member 'delegate' cannot be used on type 'purchasesViewController'"
self.avalibleIncreases = result[0]
self.currentPercentIncreases = result[1]
}
}
purchaseViewController 上的代码:
protocol updateBoosts {
func sendBack(staticIncreases: Int, percentIncreases: Int)
}
class purchasesViewController: UIViewController {
var delegate: updateBoosts? = nil
var callback : (([Int])->())?
var username: String!
var currentPercentIncreases: Int!
var avalibleIncreases: Int!
func sendBackVals(){
if self.delegate != nil {
self.delegate?.sendBack(staticIncreases: avalibleIncreases, percentIncreases: currentPercentIncreases)
}
let out = [avalibleIncreases!, currentPercentIncreases] as [Int]
callback?(out)
}
override func viewWillDisappear(_ animated: Bool) {
sendBackVals()
}
知道我的错误在哪里吗?
答:
0赞
Mohammad Kamar Shad
5/21/2020
#1
您的代码存在一些设计问题。
您应该一次使用其中之一,因为两者都用于相同的目的。否则,同样的事情将被执行两次。delegate
closure
如果您使用委托,则必须更改协议,如下所述。此外,您必须确认协议。
override func prepare(for segue: UIStoryboardSegue, sender: Any?) {
if segue.identifier == "improveFromOpen"{
let next = segue.destination as! purchasesViewController
next.currentPercentIncreases = currentPercentIncreases
next.username = username
next.avalibleIncreases = avalibleIncreases
next.delegate = self
}
}
确认协议
假设您要获取回调的当前视图控制器是HomeViewController
// Confirming the protocol
extension HomeViewController: UpdateBoostsDelegate {
func sendBack(staticIncreases: Int, percentIncreases: Int) {
// write code here for handling the callback
}
}
如果要使用闭包,请删除委托。
override func prepare(for segue: UIStoryboardSegue, sender: Any?) {
if segue.identifier == "improveFromOpen"{
let next = segue.destination as! purchasesViewController
next.currentPercentIncreases = currentPercentIncreases
next.username = username
next.avalibleIncreases = avalibleIncreases
next.callback = { result in
self.avalibleIncreases = result[0]
self.currentPercentIncreases = result[1]
}
}
// Would be good if you add the semantic to protocol name
protocol UpdateBoostsDelegate: class {
func sendBack(staticIncreases: Int, percentIncreases: Int)
}
在PurchaseViewController
class purchasesViewController: UIViewController {
// Make it weak so that no retain cycle is formed
weak var delegate: UpdateBoostsDelegate?
// rest code will follow ....
建议
- 对于 Classes、struct、enum、protocol,每个单词的第一个字符应始终为大写字母。
- 该协议应该具有语义,即如果创建它是为了通知事件,则添加 Delegate 后缀,或者如果创建它是为了满足数据需求,则在协议名称中添加数据源后缀。
评论
0赞
hudsonhooper
5/21/2020
我尝试实现您建议的更改,当我从准备 segue 中删除委托时,我收到与之前相同的关于关闭的错误。我还实现了你们所有人对委托/协议流程的建议,然后摆脱了闭包,但再次具有相同的“实例成员'委托'不能用于类型'purchasesViewController';你是不是想改用这种类型的值?“错误,与之前相同。另外,不确定它是否应该,但是当我输入它时,它绝不会像大多数其他事情那样自动建议委托purchasesViewController.delegate
0赞
Mohammad Kamar Shad
5/22/2020
@hudsonhooper 让我们在这里讨论 chat.stackoverflow.com/rooms/214353/ios-basic-discussion
0赞
Mohammad Kamar Shad
5/22/2020
再次检查代码,您将不得不使用哪个实例,您应该设置委托或闭包,例如或next
purchasesViewController
next.delegate
next.callback = { result in self.avalibleIncreases = result[0] self.currentPercentIncreases = result[1] }
0赞
Mohammad Kamar Shad
5/22/2020
欢迎您:)那么你应该接受答案@hudsonhooper
评论
protocol NAME: class { }
delegate
weak
sendBackVals()