参数化类“ABC”的原始使用

问：

我有以下界面：

public interface AsynchronousJobRunner<T extends AsynchronousJob> extends Runnable {
    public void kill();
    public void addJobExecutionListener(JobExecutionListener listener);
    public void removeJobExecutionListener(JobExecutionListener listener);
    public AsynchronousJobRunner withJob(T job);
}

AsynchronousJob是一个抽象类，可以使用以下抽象方法进行扩展以表示其他作业：

public abstract class AsynchronousJob implements JSONSerializable, HasId {...}

    /**
     * Returns the class of the {@link AsynchronousJobRunner} that runs this type of job.
     * @return The appropriate class of the job runner for this class.
     */
    public abstract Class<? extends AsynchronousJobRunner> jobRunnerClass();

我还有以下内容，它扩展了基类，并具有以下签名和方法：ExportJob

public class ExportJobRunner extends BaseJobRunner<ExportJob> { ...}

    @Override
    public Class<? extends AsynchronousJobRunner> jobRunnerClass() {
        return ExportJobRunner.class;
    }

这两种方法都有警告。jobRunnerClass()Raw use of parameterized class 'AsynchronousJobRunner'

使警告消失的简单解决方案是：

public abstract Class<? extends AsynchronousJobRunner<?>> jobRunnerClass();


@Override
public Class<? extends AsynchronousJobRunner<?> jobRunnerClass() {
    return ExportJobRunner.class;
}

但什么是正确的解决方案，为什么/如何？

编辑：

我最终只是简单地将接口的代码更改为：

public interface AsynchronousJobRunner<T extends AsynchronousJob<T>> extends Runnable {
    void kill();
    void addJobExecutionListener(JobExecutionListener listener);
    void removeJobExecutionListener(JobExecutionListener listener);
    AsynchronousJobRunner<T> withJob(T job);
}

对类的更改：AsynchronousJob

public abstract class AsynchronousJob<T> implements JSONSerializable, HasId { ...
 /**
     * Returns the class of the {@link AsynchronousJobRunner} that runs this type of job.
     * @return The appropriate class of the job runner for this class.
     */
    public abstract Class<? extends AsynchronousJobRunner<? extends AsynchronousJob<T>> jobRunnerClass();

}

ExportJob类：

public public class ExportJob extends AsynchronousJob<ExportJob> {...
    @Override
    public Class<? extends AsynchronousJobRunner<? extends AsynchronousJob<ExportJob>>> jobRunnerClass() {
        return ExportJobRunner.class;
    }
}

班级保持不变。ExportJobRunner

我还忘了提到，由于作业被序列化到数据库，因此发生了一些注入魔术：

    /**
     * Instantiates an {@link AsynchronousJobRunner} instance for the provided job.
     * <p>
     * In order for the creation of the runner to succeed, the {@link AsynchronousJob#jobRunnerClass()}
     * method of the job must specify the appropriate class for its runner.
     *
     * @param job job to create runner for
     * @return job runner configured for the specified {@code job} parameter
     */
    private <T extends AsynchronousJob<T>> AsynchronousJobRunner<T> createJobRunner(T job) {
        return ((AsynchronousJobRunner<T>)injector.getInstance(job.jobRunnerClass())).withJob(job);
    }

我已经接受了 Vershinin @Andrew回答，因为他让我走上了正确的思想轨道。