如何通过一次选择两个并要求某人在它们之间进行选择来缩小 python 中的选项列表？-解网

问：

我想创建一个程序，允许您选择自己喜欢的项目。为此，我想一次向用户提供两个选项。我将从项目列表开始，我需要程序选择前两个，然后将它们呈现给用户。用户将选择一个项目，然后将此项目添加到结果列表中。程序将遍历第一个列表，直到它显示所有选项，然后使用结果列表作为输入。最后，最终列表中应该只有一个项目。

我已经编写了一些代码来向用户显示选项，但我想不出一种方法将结果列表用作同一程序的输入。

list1 = ['1','2','3','4']
dict1 = dict(enumerate(list1,0))
def narrow (dict, listing):
    for k in list(dict.keys()):
        print('dictionary has ' + str(len(list(dict.keys()))) + '  keys')
        if len(list(dict.keys())) == 0:
            break
        elif len(list(dict.keys())) != 0:
            if len(list(dict.keys())) != 3:
                choice = input (dict[k] + ' or ' + dict[k+1] + ' ')
                if choice == 'a':
                    listing.append (dict[k])
                    print(listing)
                    dict.pop(k)
                    dict.pop(k+1)
                    print(dict)
                elif choice == 'b':
                    listing.append (dict[k+1])
                    print(listing)
                    dict.pop(k)
                    dict.pop(k+1)
                    print(dict)
                narrow(dict, listing)
                return(listing)
            elif len(list(dict.keys())) == 3:
                choice = input (dict[k] + ' or ' + dict[k+1] + ' or ' + dict[k+2] + ' ')
                if choice == 'a':
                    listing.append (dict[k])
                    print(listing)
                    dict.pop(k)
                    dict.pop(k+1)
                    dict.pop(k+2)
                    print(dict)
                elif choice == 'b':
                    listing.append (dict[k+1])
                    print(listing)
                    dict.pop(k)
                    dict.pop(k+1)
                    dict.pop(k+2)
                    print(dict)
                elif choice == 'c':
                    listing.append (dict[k+2])
                    print(listing)
                    dict.pop(k)
                    dict.pop(k+1)
                    dict.pop(k+2)
                    print(dict)
                narrow(dict, listing)
                return(listing)
list2 = []
narrow(dict1,list2)

Python 函数循环递归

item_list = [1,2,3,4]

while len(item_list) > 1:
    # unpack current list, grab first two items
    a, b, *item_list = item_list

    # prompt user to pick
    response = input(f"Would you like option (a) '{a}' or option (b) '{b}'?\n")
    if response == 'a':
        item_list.append(a)
    else:
        item_list.append(b)

import random

##-----------------
## Given a list of values, return the favored one.
##-----------------
def narrow(values):
    if not values:
        return None

    values = list(set(values))  ## take a copy and remove duplicates

    while len(values) > 1:
        choices = random.sample(values, 2)
        choice = input(f"Do you prefer \"{choices[0]}\" over \"{choices[1]}\" (y|n)? ")
        item_to_remove = choices[1] if choice == "y" else choices[0]
        values.remove(item_to_remove)

    return values[0]
##-----------------

all_values = ["1","2","3","4"]
favored_value = narrow(all_values)
print(f"Out of all the values in {all_values}, your favorite was '{favored_value}'")

如何通过一次选择两个并要求某人在它们之间进行选择来缩小 python 中的选项列表？

How to narrow down a list of options in python by picking two at a time and asking someone to pick between them?

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