如何在 Java 中验证 Azure AD JWT 令牌?

How can I validate an Azure AD JWT Token in Java?

提问人:vcima 提问时间:3/27/2020 最后编辑:Zoe is on strikevcima 更新时间:9/20/2021 访问量:15065

问:

我有一个使用 Msal 库获取的 Azure AD JWT 令牌,但当我尝试验证此令牌时,会出现以下问题:

客户端:SharePoint Web 部件

 const config = {
     auth: {
         clientId: "xxxxx",
         authority: "https://login.microsoftonline.com/yyyyyy"
     }
 };

 const myMSALObj = new UserAgentApplication(config);

 let accessTokenRequest = {
     scopes: ["user.read"],
     loginHint: this.context.pageContext.user.loginName,
     extraQueryParameters: {domain_hint: 'organizations'}
 }

 myMSALObj.acquireTokenSilent(accessTokenRequest).then(
  function(accessTokenResponse) { 
  // Acquire token silent success 
  let accessToken = accessTokenResponse.accessToken;

我正在尝试从以下位置检索公钥:https://login.microsoftonline.com/tenant-id/.well-known/openid-configuration 但是使用此公钥,我永远无法重定向到:https://login.microsoftonline.com/common/discovery/keys

在这种情况下,有没有其他方法可以获取公钥?

服务器:验证

public PublicKey getPublicKeyFromParams(String e, String n){

    byte[] modulusBytes = Base64.getUrlDecoder().decode(n);

    BigInteger modulusInt = new BigInteger(1, modulusBytes);

    byte[] exponentBytes = Base64.getUrlDecoder().decode(e);

    BigInteger exponentInt = new BigInteger(1, exponentBytes);

    KeyFactory keyFactory;

    RSAPublicKeySpec publicSpec = new RSAPublicKeySpec(modulusInt, exponentInt);

        try {

            keyFactory = KeyFactory.getInstance("RSA");

            return keyFactory.generatePublic(publicSpec);

        } catch (NoSuchAlgorithmException | InvalidKeySpecException ex) {

            ex.printStackTrace();

        }

    return null;

}

@Test

public void name() throws Exception {

    String jwt = "xxxxxxx";

    KeyPair keyPair = Keys.keyPairFor(SignatureAlgorithm.RS256);

    String e = Base64.getUrlEncoder().encodeToString((((RSAPublicKeyImpl) keyPair.getPublic()).getPublicExponent()).toByteArray());

    String n = Base64.getUrlEncoder().encodeToString((((RSAPublicKeyImpl) keyPair.getPublic()).getModulus()).toByteArray());

    System.out.println("Public Key: " + Base64.getUrlEncoder().encodeToString(keyPair.getPublic().getEncoded()));

    System.out.println("Public Key Exponent: " + e);

    System.out.println("Public Key Modulus: " + n);

    String jws = Jwts.builder().setSubject("pepe").signWith(keyPair.getPrivate()).compact();

    System.out.println("Generated JWS:" + jws);

    PublicKey publicKey = getPublicKeyFromParams(e, n);

    Jwt parsedJWs = Jwts.parserBuilder().setSigningKey(publicKey).build().parse(jws);

    System.out.println("Parsed JWS: " + parsedJWs);

    publicKey = getPublicKeyFromParams(eValue, nValue);

    System.out.println("Azure PublicKey fron n-e: " + publicKey);

    CertificateFactory factory = CertificateFactory.getInstance("X.509");

    Certificate cert = factory.generateCertificate(new ByteArrayInputStream(

    DatatypeConverter.parseBase64Binary("cccccccccccccccccc")));

    publicKey = cert.getPublicKey();

    System.out.println("Azure PublicKey from x5c: " + publicKey);

    Jwt jwtParsed = Jwts.parserBuilder().setSigningKey(publicKey).build().parse(jwt);

    System.out.println(jwtParsed);

}

public static PublicKey getPublicKey(String key){

    try{

        byte[] byteKey = Base64.getDecoder().decode(key);

        X509EncodedKeySpec X509publicKey = new X509EncodedKeySpec(byteKey);

        KeyFactory kf = KeyFactory.getInstance("RSA");

        return kf.generatePublic(X509publicKey);

    }

    catch(Exception e){

        e.printStackTrace();

    }

    return null;

}
Azure Azure-active-Directory

评论

0赞 Jim Xu 3/30/2020
你能提供你的代码吗?
0赞 vcima 3/30/2020
嗨,@JimXu。感谢您的回复。我已经添加了我的代码。

答:

6赞 Jim Xu 3/31/2020 #1

如果要验证 Azure AD 访问令牌,我们可以尝试使用 SDK 并实现它。java-jwtjwks-rsa

例如

  1. 通过 maven 安装 SDK
 <dependency>
      <groupId>com.microsoft.azure</groupId>
      <artifactId>azure-storage</artifactId>
      <version>8.6.2</version>
    </dependency>

    <dependency>
      <groupId>com.auth0</groupId>
      <artifactId>jwks-rsa</artifactId>
      <version>0.11.0</version>
    </dependency>
  1. 法典

    A. 验证签名

     String token="<your AD token>";
      DecodedJWT jwt = JWT.decode(token);
      System.out.println(jwt.getKeyId());
    
      JwkProvider provider = null;
      Jwk jwk =null;
      Algorithm algorithm=null;
    
      try {
          provider = new UrlJwkProvider(new URL("https://login.microsoftonline.com/common/discovery/keys"));
          jwk = provider.get(jwt.getKeyId());
          algorithm = Algorithm.RSA256((RSAPublicKey) jwk.getPublicKey(), null);
          algorithm.verify(jwt);// if the token signature is invalid, the method will throw SignatureVerificationException
      } catch (MalformedURLException e) {
          e.printStackTrace();
      } catch (JwkException e) {
          e.printStackTrace();
      }catch(SignatureVerificationException e){
    
         System.out.println(e.getMessage());
    
      }
    

评论

0赞 vcima 3/31/2020
嗨,JIm!。感谢您的回复。使用您的代码,我遇到了同样的问题:我已通过以下命令获取令牌: myMSALObj.acquireTokenSilent(accessTokenRequest).then(function(accessTokenResponse) { // 获取令牌 silent success // 使用 token 调用 API let accessToken = accessTokenResponse.accessToken;
1赞 vcima 3/31/2020
您的示例的验证错误是这样的:使用算法验证时,令牌的签名无效:SHA256withRSA 你有什么想法吗?
0赞 Jim Xu 3/31/2020
@vcima 是你用sdk来需要令牌吗?msal.js
0赞 vcima 3/31/2020
嗨@Jim XU,是的,我正在 Sharepoint WebPart 中使用 Msal 库并导入:import {UserAgentApplication} from “msal”;。这有问题吗?
0赞 vcima 3/31/2020
const config = { auth: { clientId: “xxxxx”, authority: “login.microsoftonline.com/yyyyyy” } };const myMSALObj = new UserAgentApplication(config);let accessTokenRequest = { scopes: [“user.read”], loginHint: this.context.pageContext.user.loginName, extraQueryParameters: {domain_hint: 'organizations'} } myMSALObj.acquireTokenSilent(accessTokenRequest).then( function(accessTokenResponse) { // 获取令牌 silent success let accessToken = accessTokenResponse.accessToken;
5赞 vcima 4/1/2020 #2

通过此更改,验证工作正常。

let accessTokenRequest = {
    scopes:["clientId/.default"],
    loginHint: this.context.pageContext.user.loginName,
    extraQueryParameters: {domain_hint: 'organizations'}
}

评论

0赞 phil294 6/25/2021
谢谢 vcima,你刚刚在无数个小时后救了我。似乎从 msal 生成的access_token在使用 时实际上是无效的,而在 时有效,可以通过 jwt.io 验证。另请参阅此处scopes:['user.read']['your client id/.default']
0赞 atGuz 5/25/2021 #3

您需要使用 Microsoft 的新密钥才能使上述代码正常工作。改变:

provider = new UrlJwkProvider(new URL(“https://login.microsoftonline.com/common/discovery/keys”));

provider = new UrlJwkProvider(new URL(“https://login.microsoftonline.com/common/discovery/v2.0/keys”));

对于上面的示例,缺少一些依赖项,正确的示例应该是:

<dependency>
        <groupId>com.microsoft.azure</groupId>
        <artifactId>azure-storage</artifactId>
        <version>8.6.2</version>
    </dependency>

    <!-- https://mvnrepository.com/artifact/com.auth0/java-jwt -->
    <dependency>
        <groupId>com.auth0</groupId>
        <artifactId>java-jwt</artifactId>
        <version>3.16.0</version>
    </dependency>

    <!-- https://mvnrepository.com/artifact/com.auth0/jwks-rsa -->
    <dependency>
        <groupId>com.auth0</groupId>
        <artifactId>jwks-rsa</artifactId>
        <version>0.18.0</version>
    </dependency>

和代码:

String token="YOUR JWT";
        DecodedJWT jwt = JWT.decode(token);
        System.out.println(jwt.getKeyId());

        JwkProvider provider = null;
        Jwk jwk =null;
        Algorithm algorithm=null;

        try {
            provider = new UrlJwkProvider(new URL("https://login.microsoftonline.com/common/discovery/v2.0/keys"));
            jwk = provider.get(jwt.getKeyId());
            algorithm = Algorithm.RSA256((RSAPublicKey) jwk.getPublicKey(), null);
            algorithm.verify(jwt);// if the token signature is invalid, the method will throw SignatureVerificationException
        } catch (MalformedURLException e) {
            e.printStackTrace();
        } catch (JwkException e) {
            e.printStackTrace();
        }catch(SignatureVerificationException e){

            System.out.println(e.getMessage());

        }

评论

0赞 Java Backend Developer 5/27/2021
当我尝试此代码时,我在以下行出现 sslhand shake 异常。jwk = provider.get(jwt.getKeyId());我们是否需要在 JKS 中添加任何公共证书?
0赞 Paramesh Korrakuti 9/26/2021
这甚至可以验证过期的令牌。有没有办法自定义验证选项以包括到期时间、颁发者等?