提问人：Muc 提问时间：9/8/2023 更新时间：9/8/2023 访问量：30
我怎样才能让 gmock 对象返回一个固定的 std：：forward_list
How can I have a gmock object return a fixed std::forward_list
问：
我正在尝试编写此测试：
TEST(AccountServiceShould, print_a_statement_containing_all_transactions) {
auto transactionRepository = new TransactionRepositoryMock;
std::forward_list<model::Transaction *> transactionList;
auto statementPrinter = new StatementPrinterMock;
transactionList.assign({transaction("22/12/2019", 1000)});
ON_CALL(
*transactionRepository,
all()
)
.WillByDefault(Return(transactionList));
Clock *myClock = new Clock;
auto accountService = new AccountService(transactionRepository, myClock);
EXPECT_CALL(*statementPrinter, print(Eq(transactionList)));
accountService->printStatement();
delete accountService;
delete transactionRepository;
delete myClock;
delete statementPrinter;
}
我在编译时遇到错误：
No viable conversion from 'internal::ReturnAction<forward_list<Transaction *, allocator<Transaction *>>>' to 'const Action<std::forward_list<model::Transaction, std::allocator<model::Transaction>> ()>' candidate template ignored: requirement 'internal::disjunction<std::is_constructible<std::function<std::forward_list<model::Transaction, std::allocator<model::Transaction>> ()>, testing::internal::ReturnAction<std::forward_list<model::T... candidate template ignored: could not match 'Action' against 'ReturnAction' explicit constructor is not a candidate candidate template ignored: could not match 'OnceAction' against 'Action' candidate template ignored: requirement 'conjunction<testing::internal::negation<std::is_same<void, std::forward_list<model::Transaction, std::allocator<model::Transaction>>>>, testing::internal::negation<std::is_reference<std::forward_... passing argument to parameter 'action' here
我不明白问题出在哪里。我试图更改 的类型，使用动态对象，甚至创建了自己的MATCHER_P但我无法弄清楚这一点。transactionList
我不是C++专家，恰恰相反。
谢谢！
答：
1赞
pptaszni
9/8/2023
#1
它应该是一个评论，但字符有点太多了。
没有可行的转换
forward_list<Transaction *, allocator<Transaction *>>
自
std::forward_list<model::Transaction, std::allocator<model::Transaction>>
所以，我有 90% （因为您没有在问题中包含相关信息）确定您有错别字，因为您的模拟返回并且您尝试返回.std::forward_list<Transaction>std::forward_list<Transation*>
这可以毫无问题地编译：
struct Transaction {};
class TransactionRepositoryMock {
public:
MOCK_METHOD(std::forward_list<Transaction*>, all, ());
};
TEST(AccountServiceShould, print_a_statement_containing_all_transactions) {
auto transactionRepository = new TransactionRepositoryMock;
std::forward_list<Transaction*> transactionList;
transactionList.assign({new Transaction});
ON_CALL(*transactionRepository, all()).WillByDefault(Return(transactionList));
}
评论
1赞
Muc
9/9/2023
嘿，谢谢你的帮助，如果我错过了一些重要信息，我很抱歉。正如我所提到的，我不是一个重度C++用户，所以可能我不知道什么样的信息是相关的。无论如何，我解决了我的问题，再次感谢！
评论
std::forward_list