在嵌套的 for 循环中计数未更新

Count not updating in nested for-loop

提问人: 提问时间:10/10/2021 最后编辑:chqrlie 更新时间:10/12/2021 访问量:116

问:

我有一个程序,旨在计算星期一在特定范围内发生的天数。我在每次迭代中更新计数时遇到问题。我尝试更改计数方法,甚至将其放入一些 if 循环中,但没有效果。

当前代码

#include <stdio.h>

#define SIZE 1000

#include "printVday.h"

int main() {
    //update date opposite of year so go through all the days first then the year
    //while loop that checks if the date was on a Monday and gets all the Mondays from the month then checks the second last one 
    int d = 15, m = 5, y, day, month, year, yearplus, i = 0;
    char dates[SIZE];

    printf("Enter a year: ");
    scanf("%d", &y);
    
    for (year = y; year <= y + 20; year++) {
        i++;
        for (day = 15; day <= 24; day++) {
            int dow = weekday(day, m, year);
            if (dow == 1) {
                printf("\n%d /%d /%d count = %d\n", day, m, year, i);
                i = 0;
            }
        }
    }
    return 0;
}

int weekday(int d, int m, int y) {

    return (d += m < 3 ? y-- : y - 2, 23 * m / 9 + d + 4 + y / 4 - y / 100 + y / 400) % 7; //Michael Keith and Tom Craver expression to minimise number of keystrokes for conversion of a gregorian date into numerical day of week. Algorithm invented by John H. Conway

}

目前我的计数正在更新,但不正确

电流输入和输出

Enter a year: 2015

18 /5 /2015 count = 1

16 /5 /2016 count = 1

23 /5 /2016 count = 0

15 /5 /2017 count = 1

22 /5 /2017 count = 0

21 /5 /2018 count = 1

20 /5 /2019 count = 1

18 /5 /2020 count = 1

17 /5 /2021 count = 1

24 /5 /2021 count = 0

...一直到2035年

期望输出

18 /5 /2015 count = 1

16 /5 /2016 count = 2

23 /5 /2016 count = 0

15 /5 /2017 count = 2

22 /5 /2017 count = 0

21 /5 /2018 count = 1

20 /5 /2019 count = 1

18 /5 /2020 count = 1

17 /5 /2021 count = 2

24 /5 /2021 count = 0

如果指定范围内只有一天恰好在星期一降落,那么它将计为 1...如果有 2 天碰巧落在指定范围内的星期一,则第一个实例将计为 2,而后者将更新为 0。

C for 循环 计数 printf std

评论


答:

0赞 chqrlie 10/10/2021 #1

您想要的输出非常具体。您希望将第一个匹配的星期一(打印该范围内的星期一总数)与随后打印 的星期一(其计数为 )区分开来。0

这是一个修改后的版本:

#include <stdio.h>

#define SIZE 1000

#include "printVday.h"

int weekday(int d, int m, int y) {
    // Michael Keith and Tom Craver expression to minimise number 
    // of keystrokes for conversion of a Gregorian date into 
    // numerical day of week. Algorithm invented by John H. Conway
    return (d += m < 3 ? y-- : y - 2, 23 * m / 9 + d + 4 + y / 4 - y / 100 + y / 400) % 7;
}

#define MONTH      5
#define START_DAY 15
#define END_DAY   24

int main() {
    // while loop that checks if the date is a Monday and gets all the Mondays
    // from the month then checks the second last one 
    int y, day, m = MONTH, year, i;

    printf("Enter a year: ");
    if (scanf("%d", &y) != 1)
        return 1;
    
    for (year = y; year <= y + 20; year++) {
        i = 1;
        for (day = START_DAY; day <= END_DAY; day++) {
            int dow = weekday(day, m, year);
            if (dow == 1) {
                if (i != 0) {
                    /* on first match, add number of other Mondays in range */
                    i += (END_DAY - day) / 7;
                }
                printf("\n%d /%d /%d count = %d\n", day, m, year, i);
                i = 0;
                day += 6;  // skip other weekdays
            }
        }
    }
    return 0;
}