C++ 中带有 cout 的指针

问：

我正在学习 C++ 和 SDL，当我尝试打印数组的内容时，我遇到了一些困惑。我有一个数组，其中包含两个值，2 和 3。当我想打印这样的值时：

int* test = myApp.countDivisions(5);
std::cout << "Horizontal: " << *test<< std::endl;
std::cout << "Vertical: " << *(test+1) << std::endl;

我得到：

Horizontal: -858993460
Vertical: -858993460

但是当我写的时候：

int* test = countDivisions(5);
int foo = *(test);
int boo = *(test+1);
std::cout << "Horizontal: " << foo << std::endl;
std::cout << "Vertical: " << boo << std::endl;

我得到：

Horizontal: 2
Vertical: 3

我很困惑为什么会这样。如果有人能解释为什么会发生这种行为，那就太好了！我知道我不应该在 C++ 中使用 C 数组，但我仍然有兴趣了解这里发生了什么！

编辑：我在第一个示例中修改了一个错别字。 我还被问到我的 countDivisions（int） 函数是做什么的，所以这里是整个代码：

#include <iostream>
#include <SDL.h>

class SDLApplication {
private:
    //This is the window of the application:
    SDL_Window* AppWindow;
    //This is the surface displayed by the window:
    SDL_Surface* WindowSurface;
    SDL_Renderer* Renderer;
    //This is the name of the App:
    std::string AppName;
    //These are the dimensions of the window displaying the App
    int WindowWidth;
    int WindowHeight;
public:
    SDLApplication(std::string name) {
        AppWindow = NULL;
        WindowSurface = NULL;
        AppName = name;
        WindowHeight = 0;
        WindowWidth = 0;
        Renderer = NULL;

    }
    int* countDivisions(int divisions) {
        //This helper functions takes as input the number of divisions on the screen and returns an array that tells
        //us how many horizontal and vertical divisions we have, assuming we divide linearly starting from the right corner.
        int horizontal = 0;
        int vertical = 0;
        int i = 0;
        int divTemp = pow(2,i);
        int divCount = divTemp;
        int temp;

        while (divCount < divisions) {
            if (i % 2 == 0) {
                //Our power of two is pair, so we are adding horizontal divisions
                horizontal += divTemp;
            }
            else {
                //Our power of two is odd, so we are adding vertical divisions
                vertical += divTemp;
            }
            ++i;
            divTemp = pow(2,i);
            temp = divCount + divTemp;

            if ( temp> divisions) {
                if (i % 2 == 0) {
                    //Our power of two is pair, so we are adding horizontal divisions
                    horizontal += divisions-divCount;

                }
                else {
                    //Our power of two is odd, so we are adding vertical divisions
                    vertical += divisions-divCount;
                }
            }
            divCount =temp;

        }

        int result[] = { horizontal, vertical };
        return result;
    }
}

int main(int argc, char* argv[])
{
    SDLApplication myApp("SDL_Test");
    int* test = myApp.countDivisions(5);
    std::cout << "Horizontal: " << *test << std::endl;
    std::cout << "Vertical: " << *(test + 1) << std::endl;
    return 0;
}