延迟执行 ES6 模板文字

我可以看到三种方法：

• 使用模板字符串，就像它们被设计为使用的那样，没有任何功能：format

  console.log(`Hello, ${"world"}. This is a ${"test"}`);
  // might make more sense with variables:
  var p0 = "world", p1 = "test";
  console.log(`Hello, ${p0}. This is a ${p1}`);
  

  甚至用于实际延迟评估的函数参数：

  const welcome = (p0, p1) => `Hello, ${p0}. This is a ${p1}`;
  console.log(welcome("world", "test"));
  

• 不要使用模板字符串，而应使用纯字符串文字：

  String.prototype.format = function() {
      var args = arguments;
      return this.replace(/\$\{p(\d)\}/g, function(match, id) {
          return args[id];
      });
  };
  console.log("Hello, ${p0}. This is a ${p1}".format("world", "test"));
  

• 使用带标记的模板文本。请注意，替换项仍将在不被处理程序拦截的情况下进行评估，因此您不能在没有名为 so 的变量的情况下使用标识符。如果接受不同的替换正文语法提案，则此行为可能会更改（更新：不是）。p0

  function formatter(literals, ...substitutions) {
      return {
          format: function() {
              var out = [];
              for(var i=0, k=0; i < literals.length; i++) {
                  out[k++] = literals[i];
                  out[k++] = arguments[substitutions[i]];
              }
              out[k] = literals[i];
              return out.join("");
          }
      };
  }
  console.log(formatter`Hello, ${0}. This is a ${1}`.format("world", "test"));
  // Notice the number literals: ^               ^
  

我发布了一个类似问题的答案，该问题给出了两种延迟模板文字执行的方法。当模板文本位于函数中时，仅当调用函数时才计算模板文本，并使用函数的作用域对其进行计算。

https://stackoverflow.com/a/49539260/188963

我也喜欢函数的想法，并且能够明确定义要解析的变量。String.format

这就是我想出的......基本上是一种带有查找的方法。String.replacedeepObject

const isUndefined = o => typeof o === 'undefined'

const nvl = (o, valueIfUndefined) => isUndefined(o) ? valueIfUndefined : o

// gets a deep value from an object, given a 'path'.
const getDeepValue = (obj, path) =>
  path
    .replace(/\[|\]\.?/g, '.')
    .split('.')
    .filter(s => s)
    .reduce((acc, val) => acc && acc[val], obj)

// given a string, resolves all template variables.
const resolveTemplate = (str, variables) => {
  return str.replace(/\$\{([^\}]+)\}/g, (m, g1) =>
            nvl(getDeepValue(variables, g1), m))
}

// add a 'format' method to the String prototype.
String.prototype.format = function(variables) {
  return resolveTemplate(this, variables)
}

// setup variables for resolution...
var variables = {}
variables['top level'] = 'Foo'
variables['deep object'] = {text:'Bar'}
var aGlobalVariable = 'Dog'

// ==> Foo Bar <==
console.log('==> ${top level} ${deep object.text} <=='.format(variables))

// ==> Dog Dog <==
console.log('==> ${aGlobalVariable} ${aGlobalVariable} <=='.format(this))

// ==> ${not an object.text} <==
console.log('==> ${not an object.text} <=='.format(variables))

或者，如果您想要的不仅仅是变量分辨率（例如模板文字的行为），您可以使用以下内容。

注意被认为是“邪恶的”——考虑使用安全评估的替代方案。eval

// evalutes with a provided 'this' context.
const evalWithContext = (string, context) => function(s){
    return eval(s);
  }.call(context, string)

// given a string, resolves all template variables.
const resolveTemplate = function(str, variables) {
  return str.replace(/\$\{([^\}]+)\}/g, (m, g1) => evalWithContext(g1, variables))
}

// add a 'format' method to the String prototype.
String.prototype.format = function(variables) {
  return resolveTemplate(this, variables)
}

// ==> 5Foobar <==
console.log('==> ${1 + 4 + this.someVal} <=='.format({someVal: 'Foobar'}))

扩展@Bergi的答案，当你意识到你可以返回任何东西时，标记模板字符串的力量就会显现出来，而不仅仅是普通的字符串。在他的示例中，标签构造并返回一个具有 closure 和 function 属性的对象。format

在我最喜欢的方法中，我本身返回一个函数值，您可以稍后调用该值并传递新参数来填充模板。喜欢这个：

function fmt([fisrt, ...rest], ...tags) {
  return values => rest.reduce((acc, curr, i) => {
    return acc + values[tags[i]] + curr;
  }, fisrt);
}

或者，对于代码高尔夫球手：

let fmt=([f,...r],...t)=>v=>r.reduce((a,c,i)=>a+v[t[i]]+c,f)

然后，构建模板并推迟替换：

> fmt`Test with ${0}, ${1}, ${2} and ${0} again`(['A', 'B', 'C']);
// 'Test with A, B, C and A again'
> template = fmt`Test with ${'foo'}, ${'bar'}, ${'baz'} and ${'foo'} again`
> template({ foo:'FOO', bar:'BAR' })
// 'Test with FOO, BAR, undefined and FOO again'

另一个选项，更接近你写的，是返回一个从字符串扩展的对象，让鸭子打字开箱即用，并尊重接口。的扩展不起作用，因为您需要关闭模板标记才能稍后解析参数。String.prototype

class FormatString extends String {
  // Some other custom extensions that don't need the template closure
}

function fmt([fisrt, ...rest], ...tags) {
  const str = new FormatString(rest.reduce((acc, curr, i) => `${acc}\${${tags[i]}}${curr}`, fisrt));
  str.format = values => rest.reduce((acc, curr, i) => {
    return acc + values[tags[i]] + curr;
  }, fisrt);
  return str;
}

然后，在呼叫站点中：

> console.log(fmt`Hello, ${0}. This is a ${1}.`.format(["world", "test"]));
// Hello, world. This is a test.
> template = fmt`Hello, ${'foo'}. This is a ${'bar'}.`
> console.log(template)
// { [String: 'Hello, ${foo}. This is a ${bar}.'] format: [Function] }
> console.log(template.format({ foo: true, bar: null }))
// Hello, true. This is a null.

您可以在其他答案中参考更多信息和应用。

AFAIS，有用的功能“字符串模板的延迟执行”仍然不可用。但是，使用 lambda 是一种富有表现力、可读性和简短的解决方案：

var greetingTmpl = (...p)=>`Hello, ${p[0]}. This is a ${p[1]}`;

console.log( greetingTmpl("world","test") );
console.log( greetingTmpl("@CodingIntrigue","try") );

您可以使用以下函数将值注入字符串

let inject = (str, obj) => str.replace(/\${(.*?)}/g, (x,g)=> obj[g]);

let inject = (str, obj) => str.replace(/\${(.*?)}/g, (x,g)=> obj[g]);


// --- Examples ---

// parameters in object
let t1 = 'My name is ${name}, I am ${age}. My brother name is also ${name}.';
let r1 = inject(t1, {name: 'JOHN',age: 23} );
console.log("OBJECT:", r1);


// parameters in array
let t2 = "Today ${0} saw ${2} at shop ${1} times - ${0} was haapy."
let r2 = inject(t2, {...['JOHN', 6, 'SUsAN']} );
console.log("ARRAY :", r2);

虽然这个问题已经回答了，但这里我有一个简单的实现，我在加载配置文件时使用（代码是打字稿，但很容易转换为JS，只需删除键入）：

/**
 * This approach has many limitations:
 *   - it does not accept variable names with numbers or other symbols (relatively easy to fix)
 *   - it does not accept arbitrary expressions (quite difficult to fix)
 */
function deferredTemplateLiteral(template: string, env: { [key: string]: string | undefined }): string {
  const varsMatcher = /\${([a-zA-Z_]+)}/
  const globalVarsmatcher = /\${[a-zA-Z_]+}/g

  const varMatches: string[] = template.match(globalVarsmatcher) ?? []
  const templateVarNames = varMatches.map(v => v.match(varsMatcher)?.[1] ?? '')
  const templateValues: (string | undefined)[] = templateVarNames.map(v => env[v])

  const templateInterpolator = new Function(...[...templateVarNames, `return \`${template}\`;`])

  return templateInterpolator(...templateValues)
}

// Usage:
deferredTemplateLiteral("hello ${thing}", {thing: "world"}) === "hello world"

虽然有可能使这些东西更强大和灵活，但它引入了太多的复杂性和风险，而没有太大的好处。

这里有一个要点的链接：https://gist.github.com/castarco/94c5385539cf4d7104cc4d3513c14f55

（参见上面@Bergi非常相似的答案）

function interpolate(strings, ...positions) {
  var errors = positions.filter(pos=>~~pos!==pos);
  if (errors.length) {
    throw "Invalid Interpolation Positions: " + errors.join(', ');
  }
  return function $(...vals) {
    var output = '';
    for (let i = 0; i < positions.length; i ++) {
      output += (strings[i] || '') + (vals[positions[i] - 1] || '');
    }
    output += strings[strings.length - 1];
    return output;
  };
}

var iString = interpolate`This is ${1}, which is pretty ${2} and ${3}. Just to reiterate, ${1} is ${2}! (nothing ${0} ${100} here)`;
// Sets iString to an interpolation function

console.log(iString('interpolation', 'cool', 'useful', 'extra'));
// Substitutes the values into the iString and returns:
//   'This is interpolation, which is pretty cool and useful.
//   Just to reiterate, interpolation is cool! (nothing  here)'

这与@Bergi的答案之间的主要区别在于如何处理错误（静默与不默）。

将这个想法扩展为接受命名参数的语法应该很容易：

interpolate`This is ${'foo'}, which is pretty ${'bar'}.`({foo: 'interpolation', bar: 'cool'});

https://github.com/spikesagal/es6interpolate/blob/main/src/interpolate.js