如何修复与 BigInteger 和 int 不兼容的操作数

问：

我试图为 collatz 猜想创建一个程序，我需要它来为更大的数字工作。因此，我尝试使用 BigInteger 类，但它似乎遇到了两种类型的错误：bigint 和 int。

我已经查找了 big int 的问题，它似乎适用于加法和乘法。但是，当尝试在除以 2 时获取余数时，它会返回错误。（在运行时开始时）。

import java.math.BigInteger;
import java.math.Bigdecimal;
import java.util.Objects;
import java.util.Scanner;
public class Main {
    /**
     * @param args
     */
    public static void main(String[] args) {
        boolean repeat = true;
        while (repeat){
            int i = 0;
            Scanner intIn = new Scanner(System.in);
            Scanner strIn = new Scanner(System.in);
            System.out.println("Enter number you want solved, Don't type 0. Use this program with caution");
            BigInteger num = intIn.nextBigInteger();
            while (num.equals(new BigInteger("1")) == false){
                if (num.equals(new BigInteger("1"))){
                  // The issue currently is that the remainder function returns an error, but im not sure exactly what is wrong with it.
                } else if (num.remainder(new BigInteger("2")) == 0) {
                    num = num.divide(new BigInteger("2"));
                } else {
                    num = num.multiply(new BigInteger("3"));
                    num = num.add(new BigInteger("1"));
                }
                i += 1;
            }
            System.out.println("It took " + i + " steps to reach 1. Would you like to do another number? (yes/no)");
            String yn = strIn.nextLine();
            if (Objects.equals(yn, "no")){
                repeat = false;
            }
        }
    }
}

在第 21 行中，错误出在 remainder 函数上。（以防您错过了评论）