将方法输出设置为 python 类中另一个方法的参数

问：

class SomeClass(object):
    def __init__(self, something_1, something_2=0):
        self.something_1=something_1
        self.something_2=something_2
        
    def SomeMethod_1(self):
        something_2=readsomefile(self.something_1)
        return something_2
    
    def SomeMethod_2(self, data=None):
        try:
            if data is None:
                data = self.something_2
                df = dosometransformation(data)
                return df
        except Exception as e:
            print("SomeMethod_2 error!: "+str(e))

if __name__ == '__main__':
    SomeClass=SomeClass(something_1)
    SomeClass.SomeMethod_2(SomeMethod_1())

我想将类中方法的输出设置为方法的参数。我不知道我错在哪里，但我的代码不起作用。SomeMethod_2()df_1SomeMethod_1()SomeClass()