在 Python 中将带有默认参数的元组传递给函数？

问：

我必须通过从一大堆元组中传递预定义的参数来调用函数。

所有函数参数都是默认类型，它们会根据 CATEGORY 参数更改其长度和类型（请参阅下面的示例代码以更好地理解我想说的内容）。

LIST_ALL_BETA = [1, 2, 3, 4, 5, 7, 23, 28, 29] # huge list with numbers, all integers
LIST_ALL_FREQ = [1.23, 1.30, 1.35, 2.18, 2.57] # huge list of floats
def MyFunction(idx=None, CATEGORY=None, LOW_LIMIT=None, HIGH_LIMIT=None, ALL_BETA=None, ALL_FREQ=None, NONE=None, LAST_X=None, LST=None):
    if CATEGORY=="COUNTED":
        partial_COUNTED_lst = globals()[f'LIST_COUNTED_LAST_{LAST_X}']
        return [x for x in range(1, 81) if partial_COUNTED_lst[idx][x-1] is not None if LOW_LIMIT <= partial_COUNTED_lst[idx][x-1] <= HIGH_LIMIT]
    elif CATEGORY=="BETA":
        if ALL_BETA==True:
            if NONE == "ignored":
                all_BETA_lst = LIST_ALL_BETA
                return [x for x in range(1, 81) if all_BETA_lst[idx][x-1] is not None if LOW_LIMIT <= all_BETA_lst[idx][x-1] <= HIGH_LIMIT]
            else: # NONE = 0
                all_BETA_lst = LIST_ALL_BETA
                return [x for x in range(1, 81) if LOW_LIMIT <= [y if y is not None else 0 for y in all_BETA_lst[idx]][x-1] <= HIGH_LIMIT]
        else:
            if NONE == "ignored":
                all_BETA_lst = globals()[f'LIST_BETA_LAST_{LAST_X}']
                return [x for x in range(1, 81) if all_BETA_lst[idx][x-1] is not None if LOW_LIMIT <= all_BETA_lst[idx][x-1] <= HIGH_LIMIT]
            else: # NONE = 0
                all_BETA_lst = globals()[f'LIST_BETA_LAST_{LAST_X}']
                return [x for x in range(1, 81) if LOW_LIMIT <= [y if y is not None else 0 for y in all_BETA_lst[idx]][x-1] <= HIGH_LIMIT]
    elif CATEGORY=="FREQUENCY":
        if ALL_FREQ==True:
            all_frequency_lst = LIST_ALL_FREQ
            return  [x for x in range(1, 81) if all_frequency_lst[idx][x-1] is not None if LOW_LIMIT <= all_frequency_lst[idx][x-1] <= HIGH_LIMIT]
        else:
            all_frequency_lst = globals()[f'LIST_FREQ_LAST_{LAST_X}']
            return  [x for x in range(1, 81) if all_frequency_lst[idx][x-1] is not None if LOW_LIMIT <= all_frequency_lst[idx][x-1] <= HIGH_LIMIT]
    elif CATEGORY=="CMB4":
        return LST[idx]

# huge list of parameters:
parametters = [
    (idx=23, CATEGORY="COUNTED", LOW_LIMIT=265, HIGH_LIMIT=269, LAST_X=1000),
    (idx=23, CATEGORY="COUNTED", LOW_LIMIT=241, HIGH_LIMIT=272, LAST_X=1000),
    (idx=23, CATEGORY="COUNTED", LOW_LIMIT=16, HIGH_LIMIT=19, LAST_X=100),
    (idx=23, CATEGORY="BETA", LOW_LIMIT=1.55, HIGH_LIMIT=2.01, ALL_BETA=True, NONE="ignored", LAST_X=0),
    (idx=23, CATEGORY="BETA", LOW_LIMIT=1.55, HIGH_LIMIT=2.01, ALL_BETA=True, NONE="0", LAST_X=0),
    (idx=23, CATEGORY="BETA", LOW_LIMIT=0.0, HIGH_LIMIT=5.3, ALL_BETA=True, NONE="ignored", LAST_X=0),
    (idx=23, CATEGORY="FREQUENCY", LOW_LIMIT=0.2587, HIGH_LIMIT=0.2608, ALL_FREQ=True, LAST_X=0),
    (idx=23, CATEGORY="FREQUENCY", LOW_LIMIT=0.2478, HIGH_LIMIT=0.2607, ALL_FREQ=True, LAST_X=0),
    (idx=23, CATEGORY="FREQUENCY", LOW_LIMIT=0.259, HIGH_LIMIT=0.261, ALL_FREQ=True, LAST_X=0),
    (idx=23, CATEGORY="CMB4", LST = LIST_CMB4_LAST_1000_1),
    (idx=23, CATEGORY="CMB4", LST = LIST_CMB4_LAST_1000_2)
]

问题是我无法创建这种元组，因为它会给我带来“无效的语法错误”。

请问有什么想法吗？

先谢谢你！

PS 我也发现了这个话题，它以某种方式解决了同样的问题，但它对我没有帮助，因为问题是不同的，而且我并不真正了解所涉及的情况，所以我可以使用解决方案来解决我正在问的这个问题。