传递多个参数：“run bash -c ...'

问：

在尝试使用一个名为 的函数时，我在传递超过 1 个参数时遇到了一些困难。assert_failuresome_function

load 'libs/bats-support/load'
load 'libs/bats-assert/load'
# https://github.com/bats-core/bats-file#Index-of-all-functions
load 'libs/bats-file/load'
# https://github.com/bats-core/bats-assert#usage
load 'assert_utils'

@test "Perform some test." {
  variable_one="one"
  variable_two="two"
  variable_three="three"
  variable_four="four"
  run bash -c 'source src/some_script.sh && some_function 
  "$variable_one" "$variable_two" "$variable_three"'
  assert_failure
  assert_output "$expected_error_message"
}

其中，函数包括：

some_function() {
    local variable_one="$1"
    local variable_two="$2"
    local variable_three="$3"
    local variable_four="$4"
    echo "variable_one=$variable_one"
    echo "variable_two=$variable_two"
    echo "variable_three=$variable_three"
    echo "variable_four=$variable_four"
}

输出显示只有第一个变量成功传递，而第二个到第四个变量则未成功传递：

 ✗ Verify an error is thrown, if something.
   (from function `assert_failure' in file test/libs/bats-assert/src/assert.bash, line 140,
    in test file test/test_something.bats, line 89)
     `assert_failure' failed
   
   -- command succeeded, but it was expected to fail --
   output (3 lines):
     variable_one=one
     variable_two=
     variable_three=
     variable_four=
   --
   

如何在函数上运行时将多个/四个变量传递给函数？assert_failure

编辑以响应评论

虽然我感谢卡米尔库克在评论中提供的实际解决方案，但它似乎允许增加具体性。例如，可能是在多个函数中使用的变量，对于对这些函数的不同调用具有不同的值。因此，理想情况下，我不会在每次调用不同的函数时都覆盖“导出”值。相反，我认为最好将特定参数传递给特定函数。variable_one