在接收进一步输入之前继续循环迭代

问：

我对使用C++很陌生，所以我遇到了一些问题——>

我敢肯定，我可以用另一种方式来做到这一点，只需使用一个函数来检查老师是否要添加另一个学生。但是，我相信这种方式应该有效。我遇到了一个错误。循环继续迭代，打印“您想添加另一个学生：y/n？我认为这可能是由于剩余的输入通过 cin >> instructorChoice 传递的。

但如果是这样的话，它不应该停在其他 cin（s） 上吗？因为它会在某一时刻再次遇到他们。

我还有另一个问题，我不确定如何打印对象属性（我相信这就是你引用它们的方式？），例如 person.name（）。虽然我敢肯定我以后会弄清楚的，但没什么大问题。 -->头文件中的打印功能。

我有一个主文件和一个班级的头文件。我不确定这是否是最好的方法。我知道这是一个小程序，但我想尝试在编程时养成更好的文件管理习惯。

我将不胜感激。提前致谢。

/*
    Simple "Class" Project 1:

    This program allows a teacher to add a student to a list of student,
    once she/he is done. The program prints all the students in the list
    along with their grades. I'm testing the use of header files by defining
    my class and its methods there.

    - Me
*/

#include <vector>
#include  "student.h" //include files for student class
                      //includes <iostream>, <string>, namespace


int main() {
    //var declarations
    string studentName;
    int studentGrade;
    char instructorChoice;
    int i;

    //delcare student vector
    vector<Student> studentList;

    //take the initial input
    cout << "Would you like to add a new student: y/n?" << endl;
    cin >> instructorChoice;

    //run until no more students need to be addded
    while (instructorChoice == 'y') { 
        
        Student student; //create new student info

        //prompt for user info
        cout << "Student Name: ";
        cin >> studentName;

        cout << "Student Grade: ";
        cin >> studentGrade;

        student.SetName(studentName); //setName
        student.SetGrade(studentGrade); //setGrade
        studentList.push_back(student); //append to list of students

        //notify teacher!
        cout << student.GetName() << " has successfully been added!" << endl;

        //ask if they would like to add another student
        cout << "Would you like to add another student: y/n?" << endl;
        cin >> instructorChoice;

    }

    //print all 
    for (i = 0; i < studentList.size(); ++i) { //iterate through object vector
        studentList[i].PrintStudents();
    }
    
    return 0;
}

/*
    Student Class Declaration
*/
#include <iostream>
#include <string>
using namespace std;

class Student {
    public:
        //set
        void SetName(string studentName);
        void SetGrade(char studentGrade);

        //get
        string GetName();
        int GetGrade();
        
        //print
        void PrintStudents();

    private:
        string name;
        char grade;

};


// public function definitions

//set
void Student::SetName(string studentName) { //Set new student name
    name = studentName;
}

void Student::SetGrade(char studentGrade) { //Set new student grade
    grade = studentGrade;
}


//get
string Student::GetName() { //return the student name
    return name;
}

int Student::GetGrade() { //return the student grade
    return grade;
}

//print
void Student::PrintStudents() { //Print student name and grade
    cout << "Student: " << name << " Grade: " << grade << endl;
}

我尝试使用 cin.ignore（）;

和cout<<齐平;

我能找到的几乎任何东西来清除任何剩余的缓冲区/输入。没用。

不确定问题到底是什么。