Js 从 json 中提取信息

问：

我有以下非常复杂和详细的json。

只有当 包含以下文本并且包含以下 props （） 时，我才需要从 json 推断信息（文本）。resource-id"com.shazam.android:id/"["title", "subtitle", "datetime"]

如果最后一个元素不包含 则不插入 THEN。datetimeresorceIdFinal

下面是我想得到的 json 示例。

在这里你可以找到我使用的json，由于字符空间，我无法在这里插入它。

友情链接： https://pastebin.com/raw/hFLmP2T8

const check = (obj, keys) => !keys.some((el) => !obj.hasOwnProperty(el));

const isObjectEmpty = (objectName) => {
  return (
    objectName &&
    Object.keys(objectName).length === 0 &&
    objectName.constructor === Object
  );
};

const getChildren = (el, replaceText, props, resorceIdFinal) => {
  var arr = [];

  el.forEach((el) => {
    let resorceId = getResorceId(el.attributes, replaceText, props, resorceIdFinal);
    if(!isObjectEmpty(resorceId)) arr.push(resorceId);   
    //console.log(arr);
    getChildren(el.children, replaceText, props, resorceIdFinal);
  });
  
  return arr;
};


const getResorceId = (el, replaceText, props, resorceIdFinal) => {
  var o = {};
  if (el["resource-id"] !== undefined) {
    var resorceId = el["resource-id"].replace(replaceText, "");
    if (props.includes(resorceId)) {
      o = { [resorceId]: el.text };
    }
  }
  return o;
};

function readPro(json, replaceText, props, filterA, resorceIdFinal) {
  var arr = [];

  json.forEach((el) => {
    arr.push(getChildren(el.children, replaceText, props, resorceIdFinal));
  });
  
  console.log(arr)

  filtered = arr.filter(
    ((s) => (o) =>
      ((k) => !s.has(k) && s.add(k))(filterA.map((k) => o[k]).join("|")))(
        new Set()
      )
  );

  return filtered;
}


var res = readPro(
  a.children,
  "com.shazam.android:id/",
  ["title", "subtitle", "datetime"],
  ["title", "subtitle"],
  "datetime"
);

console.log(res);

我想得到的 Json 结果：

[
   {
        "title": "Believe",
        "subtitle": "Chuther",
        "datetime": "12 giu, 16:42"
   },
   {
        "title": "시작 (Inst.)",
        "subtitle": "Gaho",
        "datetime": "12 giu, 16:42"
   },
   {
        "title": "Give It Up",
        "subtitle": "KC and the Sunshine Band",
        "datetime": "12 giu, 16:41"
   },
   {
        "title": "GRAVITY",
        "subtitle": "Jong Ho",
        "datetime": "12 giu, 16:41"
    }
]

你能帮我一把吗？

编辑：

const isObjectEmpty = (objectName) =>
(
  objectName &&
  Object.keys(objectName).length === 0 &&
  objectName.constructor === Object
);


const getResorceId = (el, replaceText, props, value) => {
  if (el["resource-id"] !== undefined) {
    var resorceId = el["resource-id"].replace(replaceText, "");
    if (props.includes(resorceId)) {
      return { [resorceId]: el[value] };
    }
  }
  return {};
};

const getChildren = (el, replaceText, props, value) => {
  var arr = [];
  el.forEach((el) => {
    let resorceId = getResorceId(el.attributes, replaceText, props, value);
    var o = {}
    if (!isObjectEmpty(resorceId)) {
      arr.push(resorceId);
      for (const [_, value] of Object.entries(arr)) {
        for (const [key, value2] of Object.entries(value))
          o[key] = value2
      }
      arr = [o]
    }

    arr.push(...getChildren(el.children, replaceText, props, value));
  });

  //console.log(arr.length, arr)
  //if(arr.length === 1 && !Object.hasOwn(...arr, resorceIdFinal)) arr = []

  return arr
};

function readPro(json, replaceText, props, filterA, value) {
  var arr = [];
  json.forEach((el) => {
    arr.push(...getChildren(el.children, replaceText, props, value));
  });

  filtered = arr.filter(
    ((s) => (o) =>
      ((k) => !s.has(k) && s.add(k))(filterA.map((k) => o[k]).join("|")))(
        new Set()
      )
  );

  return filtered;
}

var rA = readPro(
  a.children,
  "com.shazam.android:id/",
  ["title", "subtitle", "datetime"],
  ["title", "subtitle"],
  "text"
);