如何在 Java 中初始化一个类，而我要初始化的类会因变量而异？-解网

问：

我正在尝试制作一个终端程序，该程序将根据用户的输入初始化一个类。有没有办法使用 String 变量初始化特定类，而不会用语句弄乱我的程序？下面是我尝试执行的操作的示例：if

终端：

Which program would you like to run? Please type in lower case.
 - Room designer
 - Etc.

>

法典：

String answer = input.nextLine();
[answer] programToRun = new [answer]();

有没有办法做到这一点？我知道 Python 中有一种方法使用字典，所以我相信有一种方法，只是我无法找到它。Globals

java 对象 oop

interface Factory<T> {
  T createInstance(String param);
}

public class FactoryManager {
  private Map<String,Factory> factories;
  public void registerFactory(String type, Factory f) ... // add the key/pair to the factories map
  public Object createInstance(String s) ... // match the string to a Factory in the factories Map and call createInstance on it
}

如果您对此有任何疑问，请告诉我

--编辑--

例：

public class Car {
  private make = null;
  public Car() {};
  public Car(String make) {
    this.Car();
    this.make = make;
  }
}

public class CarFactory implements Factory<Car> {
  public Car createInstance(String s) {
    return new Car(s);
  }
}

public class Bus {
  private make = null;
  public Bus() {};
  public Bus(String make) {
    this.Bus();
    this.make = make;
  }
}

public class BusFactory implements Factory<Bus> {
  public Car createInstance(String s) {
    return new Bus(s);
  }
}

public class MyFactoryManager extends FactoryManager {
  public MyFactoryManager() {
//All this actually should be in the base class FactoryManager so it doesn't need to be implemented in each FactoryManager.
    factories = new HashMap<String, Factory>(); 
    public Object createInstance(String s) { // This could be expanded with another parameter to be passed to the factory for object initialization.
      return factories.get(s).createInstance();
    }
  }
}

FactoryManager fm = new MyFactoryManager();
fm.reqisterFactory("car", new CarFactory());
fm.reqisterFactory("bar", new BusFactory());
Object car = fm.createInstance("car");
Object bus = fm.createInstance("bus");
System.out.println("Car is a " + car.getClass());
System.out.println("Bus is a " + bus.getClass());

package plugins;

public class ClassName {
    @Override
    public String toString() {
        return "Works as expected!";
    }
}


public class ClassByNameTest {
    @Test
    void createInstance() throws ClassNotFoundException, NoSuchMethodException, InvocationTargetException, InstantiationException, IllegalAccessException {
        String className = "plugins.ClassName";
        Object instance = Class.forName(className).getConstructor().newInstance();

        assert a.getClass().getName().equals(className);
        System.out.println(instance.toString());
    }
}

遵循某种约定，例如实现一个公共接口，你可以调用一个入口点方法来动态运行任意行为。

编辑：尽管这在技术上没有问题，但使用工厂模式的 ControlAltDels 想法是解决这个问题的更好方法，特别是因为它将用户输入与实际类名分离。

0赞 Reilas 9/22/2023 #3

"...有没有办法使用 String 变量初始化特定类，而不会用 if 语句弄乱我的程序？..."

您可以使用反射框架通过 String 值实例化类。

需要提供完全限定的名称。

Class<?> c = Class.forName("java.lang.String");
Object instance = c.getDeclaredConstructor().newInstance();

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如何在 Java 中初始化一个类，而我要初始化的类会因变量而异？

How do I initialize a class in Java, while the class I want to initialize will vary based on a variable?

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