将 object 的 String 变回对象 Kotlin

问：

我有一个对象，我把它写到一个文件中，现在我想把我从文件中得到的那个字符串变成一个对象供我使用。

项目等级：

@Serializable
class DrinkItem {
    
    @SerializedName("strAlcoholic")
    val alcoholic: String? = null

    @SerializedName("strIngredient1")
    val ingredient1: String? = null

    @SerializedName("strIngredient10")
    val ingredient10: String? = null

    @SerializedName("strIngredient11")
    val ingredient11: String? = null

    @SerializedName("strIngredient12")
    val ingredient12: String? = null

    @SerializedName("strIngredient13")
    val ingredient13: String? = null

    @SerializedName("strIngredient14")
    val ingredient14: String? = null

    @SerializedName("strIngredient15")
    val ingredient15: String? = null

    @SerializedName("strIngredient2")
    val ingredient2: String? = null

    @SerializedName("strIngredient3")
    val ingredient3: String? = null

    @SerializedName("strIngredient4")
    val ingredient4: String? = null

    @SerializedName("strIngredient5")
    val ingredient5: String? = null

    @SerializedName("strIngredient6")
    val ingredient6: String? = null

    @SerializedName("strIngredient7")
    val ingredient7: String? = null

    @SerializedName("strIngredient8")
    val ingredient8: String? = null

    @SerializedName("strIngredient9")
    val ingredient9: String? = null

    @SerializedName("strInstructions")
    val instructions: String? = null

    @SerializedName("strMeasure1")
    val measurement1: String? = null

    @SerializedName("strMeasure10")
    val measurement10: String? = null

    @SerializedName("strMeasure11")
    val measurement11: String? = null

    @SerializedName("strMeasure12")
    val measurement12: String? = null

    @SerializedName("strMeasure13")
    val measurement13: String? = null

    @SerializedName("strMeasure14")
    val measurement14: String? = null

    @SerializedName("strMeasure15")
    val measurement15: String? = null

    @SerializedName("strMeasure2")
    val measurement2: String? = null

    @SerializedName("strMeasure3")
    val measurement3: String? = null

    @SerializedName("strMeasure4")
    val measurement4: String? = null

    @SerializedName("strMeasure5")
    val measurement5: String? = null

    @SerializedName("strMeasure6")
    val measurement6: String? = null

    @SerializedName("strMeasure7")
    val measurement7: String? = null

    @SerializedName("strMeasure8")
    val measurement8: String? = null

    @SerializedName("strMeasure9")
    val measurement9: String? = null

    @SerializedName("strDrink")
    val name: String? = null

    @SerializedName("strDrinkThumb")
    val thumbnail: String? = null
}

我使用这个函数将对象写入文件：

    private fun writeToFile(fileName: String, byteArray: ByteArray){

        val lineSeparator: String = System.getProperty("line.separator") as String

        // File
        val path = context!!.filesDir
        val directory = File(path, "LET")
        directory.mkdirs()
        val file = File(directory, fileName)

        //append drink to file
        FileOutputStream(file, true).use {
            it.write(byteArray)
            it.write(lineSeparator.toByteArray())
        }
    }

在对对象完成函数后，它将转换为以下字符串：

{"alcoholic":"Alcoholic","ingredient1":"Apricot brandy","ingredient2":"Triple sec","ingredient3":"Lime","ingredient4":"Lime","instructions":"Shake all ingredients (except lime wedge) with ice and strain into a cocktail glass. Add the wedge of lime and serve.","measurement1":"1 oz ","measurement2":"1 oz ","measurement3":"Juice of 1 ","measurement4":"1 ","name":"After Dinner Cocktail","thumbnail":"https://www.thecocktaildb.com/images/media/drink/vtytxq1483387578.jpg"}

有没有一个函数或库可以帮助我将一个对象的字符串变成所述对象？