从对象列表创建嵌套对象-解网

问：

是否可以解析此列表并在“RECORD”之后为每个传感器创建一个新的嵌套对象。

{
    "TIMESTAMP": "2022-10-21 13:55:00",
    "RECORD": "0",
    "Sensor1": "1.654",
    "Sensor2": "1.176",
    "Sensor3": "0.706"
}

结果：

{
    "Sensor1": {
        "TIMESTAMP": "2022-08-21 13:55:00",
        "Value": "1.654"
    },
    "Sensor2": {
        "TIMESTAMP": "2022-08-21 13:55:00",
        "Value": "1.176"
    },
    "Sensor3": {
        "TIMESTAMP": "2022-08-21 13:55:00",
        "Value": "0.706"
    }
}

JavaScript 对象嵌套

const transform = (input) => {
  return Object.keys(input).reduce((accum, inputKey) => {
    if (inputKey === 'TIMESTAMP' || inputKey === 'RECORD') {
      return accum;
    }

    return {
      ...accum,
      [inputKey]: {
        TIMESTAMP: input.TIMESTAMP,
        Value: input[inputKey]
      } 
    };
  }, {})
}

// Example
const exampleObject = {
  "TIMESTAMP": "2022-10-21 13:55:00",
  "RECORD": "0",
  "Sensor1": "1.654",
  "Sensor2": "1.176",
  "Sensor3": "0.706"
};

console.log(transform(exampleObject));

2赞 Sebastian Kaczmarek 11/16/2023 #2

您可以尝试使用 .示例如下：Object.entries(...).reduce(...);

const input = {
    "TIMESTAMP": "2022-10-21 13:55:00",
    "RECORD": "0",
    "Sensor1": "1.654",
    "Sensor2": "1.176",
    "Sensor3": "0.706"
};

const result = Object.entries(input).reduce((res, [key, val]) => {
  if (!key.startsWith("Sensor")) return res;
  
  res[key] = {
    TIMESTAMP: input.TIMESTAMP,
    Value: val
  };
  
  return res;
}, {});

console.log(result);

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