提问人:Eniedi Monday 提问时间:10/21/2023 更新时间:10/21/2023 访问量:38
如何在 flutter dart 上正确处理嵌套的 json 数据
How to handle nested json data correctly on flutter dart
问:
在我的请求中,我是 flutter 和 dart 语言的新手,我希望能够正确处理嵌套的 json 响应,因为我在下面的 json 中有这些数据
这是我的json数据:
[
{
"name": "John",
"age": 20,
"address": [
{
"street": "103 Main St",
"city": "gghhd"
},
{
"street": "103 Main St",
"city": "Anytown"
},
{
"street": "13 Grog St",
"city": "Anytown"
},
{
"street": "3 delk St",
"city": "upwn"
}
]
}
]
这是我生成的在线 json:
class Autogenerated {
String? name; int? age;
List<Address>? address;
Autogenerated({this.name, this.age, this.address});
Autogenerated.fromJson(Map<String, dynamic> json) {
name = json['name'];
age = json['age'];
if (json['address'] != null) {
address = <Address>[];
json['address'].forEach((v) {
address!.add(new Address.fromJson(v));
});
}
}
Map<String, dynamic> toJson() {
final Map<String, dynamic> data = new Map<String, dynamic>();
data['name'] = this.name;
data['age'] = this.age;
if (this.address != null) {
data['address'] = this.address!.map((v) => v.toJson()).toList();
}
return data;
}
}
class Address {
String? street;
String? city;
Address({this.street, this.city});
Address.fromJson(Map<String, dynamic> json) {
street = json['street'];
city = json['city'];
}
Map<String, dynamic> toJson(){
final Map<String, dynamic> data = new Map<String, dynamic>();
data['street'] = this.street;
data['city'] = this.city;
return data;
}
}
我想要一个函数将我的json数据传递给furture.builder,以便在listview中拥有所有地址。
答:
0赞
Chirag Sondagar
10/21/2023
#1
你可以这样使用
List<Autogenerated> arrUserList = (json.decode(jsonString) as List)
.map((data) => Autogenerated.fromJson(data))
.toList();
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0赞
Eniedi Monday
10/21/2023
我如何获得我的问题的未来构建器列表视图
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