我需要将我的 HashMap 移动到哪里，以便两个单独的 Switch 语句可以看到它？[复制]

问：

我正在完成我正在学习的 Java 课程的期末项目。该项目的目标是创建一个资产管理工具，用户可以使用它来输入员工及其员工 ID、分配给他们的电子设备和序列号，然后通过搜索他们的姓名或员工 ID 来查找员工拥有的设备。

我有一个 Switch 语句，用于检查用户是否键入了“添加新员工记录”、“搜索员工记录”、“结束程序”或其他任何内容（默认）。我需要创建第二个开关，当用户键入“搜索员工记录”时，该开关将运行。我正在对此进行研究，发现将 Switch 语句嵌套在其他 Switch 语句中不被认为是最佳实践，最好编写一个可以在特定 Switch 案例中调用的方法，该方法将运行另一个 Switch 语句。我已经尝试过，但是我用此方法编写的代码无法看到在主方法开始时创建的 HashMap。我收到的所有错误都与此有关。

问：我需要将我的 HashMap 移动到哪里，以便第一个 Switch（位于 main 类，main 方法）和第二个 Switch（位于 Employee 类，searchForEmployee 方法中）都可以查看并从中收集键/值？

这是我在主类中的代码：

import java.util.*;

class Main {
  public static void main(String[] args) {

    //Creating a Scanner to take input from user
    Scanner input = new Scanner(System.in);

    //Creating a HashMap to take in employee names and ID numbers
    Map<String, Integer> employeeIndex = new HashMap<>();

    //Creating an ArrayList to keep track of employees and allow for easy user searching
    ArrayList<Employee> employees = new ArrayList<Employee>();

    System.out.println("This is an Asset Management Tracking program. This database allows you to add and manage employee-assigned equipment. \n");

    boolean loop = true;
    while (loop) {
    
      System.out.println("\nWould you like to add an employee to the system, or search for an employee record? Please enter your selection below: \n" + "\nAdd New Employee Record \n" + "\nSearch Employee Records \n" + "\nEnd Program \n");

      String answer = input.nextLine().toLowerCase();
    
      switch (answer) {
          
        case "add new employee record": System.out.println("\nPlease enter the employee's name (Last name, First name): \n");
          String employeeName = input.nextLine();
          System.out.println("\nPlease enter their 6-digit employee ID: \n");
          int employeeID = input.nextInt();
          input.nextLine();

          Employee employee1 = new Employee(employeeName, employeeID);
          employeeIndex.put(employeeName, employeeID);
          System.out.println("\nOkay. You have entered:\n\n" + "Name: " + employeeName + "\nID: " + employeeID);
          employees.add(employee1);
          System.out.println(employeeIndex.entrySet());
          break;

        case "search employee records":  System.out.println("\nHow would you like to search? \n" + "\nEmployee Name\n" + "\nEmployee ID\n");
          Employee.searchForEmployee();
          break;

        case "end program":
          System.out.println("\nThank you for using this Asset Management Program!");
          input.close();
          loop = false;
          break;

        default: 
          System.out.println("\nSorry, that is an incorrect response (perhaps you typed it wrong?). Please choose one of the available options. \n");
          break;
      }
    }
  }
}

以及 Employee 类中的 searchForEmployee 方法：

static void searchForEmployee() {

    Scanner input2 = new Scanner(System.in);
    String answer2 = input2.next().toLowerCase();
    
    switch (answer2) {
          
      case "employee name": 
        System.out.println("\nPlease enter the employee's name (Last name, First name): \n");
        String searchEmployeeName = input2.nextLine();
        if (employeeIndex.containsKey(searchEmployeeName) = true) {
          System.out.println(employeeIndex.get(searchEmployeeName));  
        } else {
            System.out.println("\nI'm sorry, that employee does not appear to be in this database yet. Here are the employee records contained so far: \n");
            System.out.println(employeeIndex.keySet());
          }
        break;

      case "employee id":  
        System.out.println("\nPlease enter the employee's ID#: \n");
        int searchEmployeeID = input2.nextInt();
        if (employeeIndex.containsValue(searchEmployeeID) = true) {
          System.out.println(employeeIndex.get());
        } else {
            System.out.println("\nI'm sorry, that employee ID does not appear to be in this database yet. Here are the employee ID numbers contained so far: \n");
            System.out.println(employeeIndex.values());
          }
        break;

      default: 
        System.out.println("\nSorry, that is an incorrect response (perhaps you typed it wrong?). Please choose one of the available options. \n");
        break;
      }
    }

这些是我在运行程序时收到的错误：

Employee.java:26: error: cannot find symbol
        if (employeeIndex.containsKey(searchEmployeeName) = true) {
            ^
  symbol:   variable employeeIndex
  location: class Employee

Employee.java:27: error: cannot find symbol
          System.out.println(employeeIndex.get(searchEmployeeName));  
                             ^
  symbol:   variable employeeIndex
  location: class Employee

Employee.java:30: error: cannot find symbol
            System.out.println(employeeIndex.keySet());
                               ^
  symbol:   variable employeeIndex
  location: class Employee

Employee.java:37: error: cannot find symbol
        if (employeeIndex.containsValue(searchEmployeeID) = true) {
            ^
  symbol:   variable employeeIndex
  location: class Employee

Employee.java:38: error: cannot find symbol
          System.out.println(employeeIndex.get());
                             ^
  symbol:   variable employeeIndex
  location: class Employee

Employee.java:41: error: cannot find symbol
            System.out.println(employeeIndex.values());
                               ^
  symbol:   variable employeeIndex
  location: class Employee

6 errors
exit status 1

再次感谢您的帮助。我仍然处于初学者阶段，这个社区在学习过程中对我非常有帮助。