组合函数转置矩阵中的指针问题

问：

在我的代码中，我尝试使用在汇编中编写的函数转置动态矩阵 （IN64） 似乎我试图从矩阵外部读取，或者我在试图指出我的函数应该从哪里移动并保存字节时犯了一个错误。

请帮助我解决这个问题，因为正确理解我犯了什么错误对我来说很重要

下面是使用函数转置的 c++ 代码

#include <iostream>
#include <windows.h>

extern "C" void transpose(INT64**, INT64);

// Function for displaying the matrix
void printMatrix(INT64** matrix, INT64 n) {
    for (INT64 i = 0; i < n; ++i) {
        for (INT64 j = 0; j < n; ++j) {
            std::cout << matrix[i][j] << " ";
        }
        std::cout << std::endl;
    }
}

int main() {
    INT64 n = 8; // Matrix size

    // Initialization of matrix A
    INT64** A = new INT64 * [n];
    for (INT64 i = 0; i < n; ++i) {
        A[i] = new INT64[n];
        for (INT64 j = 0; j < n; ++j) {
            A[i][j] = i * n + j; // Filling matrix A
        }
    }

    std::cout << "Matrix before transposition:" << std::endl;
    printMatrix(A, n); // Display the matrix before transposition

    // Calling the transpose function
    transpose(A, n);

    std::cout << "Matrix after transposition:" << std::endl;
    printMatrix(A, n); // Display the matrix after transposition

    // Deallocate memory
    for (INT64 i = 0; i < n; ++i) {
        delete[] A[i];
    }
    delete[] A;

    return 0;
}

和 heres 转置函数

.code


transpose PROC
    mov r10, rax ; Store the dimension 8 in r10
    mov r11, rax ; Store the dimension 8 in r11

loopRow:
    mov r8, [rcx + rax]      ; Initialize the row index (i) to 8 (8,7,6,5,4,3,2,1)
    mov r9, [rcx + 8 * rax]      ; Initialize the column index (j) to 8 (56,48,40,32,24,16,8,0)

loopColumn:
    mov rdx, [r9 + rdi * 8] ; Load the element from the matrix (56,48,40,32,24,16,8,0)
    mov rsi, [rcx + rdi * 8] ; Load the element from the matrix (7,6,5,4,3,2,1,0)
    mov [r9 + rdi * 8], rsi ; Assign the element to the transposed location
    mov [rcx + rdi * 8], rdx
    inc rdi        ; Move to the next column
    cmp rdi, r10   ; Check if all columns are finished
    jl loopColumn
    inc r11        ; Move to the next row
    cmp rdi, r11   ; Check if all rows are finished
    jl loopRow

    ret
transpose ENDP

END

我试图以多种方式修复该代码感到失败，但似乎我只是在我的功能不起作用时错过了一些重要的东西

[编辑]

这是我尝试解决它的下一个代码：

.code

transpose PROC
    mov r10, rdx ; matrix size n
    mov r11, rdx ; matrix size n

loopRow:
    mov r10, r11
    mov r12, [rcx + 8 * r10 - 8] ; el.(64) of the matrix
    mov r13, [rcx + 8 * r11 - 8] ; el.(64) of the matrix

loopColumn:
    mov rdx, [rcx + 8 * r10 - 8]
    mov rsi, [rcx + 8 * r11 - 8]
    mov r8, rdx
    mov [rcx + 8 * r10 - 8], rsi
    mov [rcx + 8 * r11 - 8], rdx

    dec r10        ; Move to the next column
    jnz loopColumn
    dec r11        ; Move to the next row
    jnz loopRow

    ret
transpose ENDP
END