在 C/C++ 中读取嵌套 lua 脚本的键和值

问：

我有以下 lua 脚本，其中我使用一个 C++ 函数，该函数需要读取嵌套表的键和值：

local scenariolist = {
   scenarios = {
      'scenario1',
      'scenario3',
      'scenario2'
   },
   result = true,
   message = 'test message'
}

my.sendfromscenariolist(scenariolist)

这是我的C++函数，在调用时执行：sendfromscenariolist

int ScenarioFunction(lua_State* L) {
  int nargs = lua_gettop(L);
  if (nargs != 1) {
    return 0;
  }
  int type = lua_type(L, 1);
  if (type != LUA_TTABLE) {
    return 0;
  }
  ParseScenarioTable(L);
  return 0;
}


void ParseScenarioTable(lua_State* L) {

  lua_pushnil(L);
  while (lua_next(L, -2) != 0) {
    if (lua_istable(L, -1)) {
      ParseScenarioTable(L);
      std::cout << "Key: " << "key" << ", Value is table" << std::endl;
    }
    else if (lua_isstring(L, -1)) {
      std::string x = lua_tostring(L, -1);
      std::cout << "Key: " << "key" << ", Value: " << x << std::endl;
      int i = 0;
    }
    else if (lua_isboolean(L, -1)) {
      bool x = lua_toboolean(L, -1);
      int i = 0;
      std::cout << "Key: " << "key" << ", Value: " << x << std::endl;
    }
    lua_pop(L, 1);
  }
}

这个函数只读值，它工作，当我在控制台中运行它时，我得到：

Key: key, Value: 1
Key: key, Value: scenario1
Key: key, Value: scenario3
Key: key, Value: scenario2
Key: key, Value is table
Key: key, Value: test message

问题是我无法读取嵌套表元素的键。我用这个更改了我的代码：

int ScenarioFunction(lua_State* L) {
  int nargs = lua_gettop(L);
  if (nargs != 1) {
    return 0;
  }
  int type = lua_type(L, 1);
  if (type != LUA_TTABLE) {
    return 0;
  }
  ParseScenarioTable(L);
  return 0;
}


void ParseScenarioTable(lua_State* L) {

  lua_pushnil(L);
  while (lua_next(L, -2) != 0) {
    if (lua_istable(L, -1)) {
      std::string key = lua_tostring(L, -2);
      ParseScenarioTable(L);
      std::cout << "Key: " << key << ", Value is table" << std::endl;
    }
    else if (lua_isstring(L, -1)) {
      std::string key = lua_tostring(L, -2);
      std::string x = lua_tostring(L, -1);
      std::cout << "Key: " << key << ", Value: " << x << std::endl;
      int i = 0;
    }
    else if (lua_isboolean(L, -1)) {
      std::string key = lua_tostring(L, -2);
      bool x = lua_toboolean(L, -1);
      int i = 0;
      std::cout << "Key: " << key << ", Value: " << x << std::endl;
    }
    lua_pop(L, 1);
  }
}

但是如果我尝试读取密钥，程序将中断并收到错误： 这是我程序的输出：

Key: result, Value: 1
Key: 1, Value: scenario1
[2023-09-01 16:17:03.391093][error]: Error when running the script. Error is: invalid key to 'next'

其中 是 Lua 的错误字符串。invalid key to 'next'

我做错了什么？如何读取键和值？