线程“main”java.util.NoSuchElementException中的异常：未找到行 Project Java Eclipse IDE

问：

我正在使用 Eclipse IDE 开发 Java 程序，并遇到“线程 'main' java.util.NoSuchElementException： No line found”错误的问题。此错误发生在我的控制台输出中

Exception in thread "main" java.util.NoSuchElementException: No line found
at java.base/java.util.Scanner.nextLine(Scanner.java:1651)
at Controller.Client_Controller.menu(Client_Controller.java:94)
at Controller.Main_Controller.menu(Main_Controller.java:38)
at Controller.EShop2023.main(EShop2023.java:17)

该错误专门链接到以下代码行：sc.nextLine（）;
行后：System.out.println（“无效输入。请输入一个有效的号码。

以下是菜单处理代码的相关部分：

package Controller;

import java.util.ArrayList;
import java.util.Scanner;


import Model.Client;

public class Client_Controller {
    
    private ArrayList<Client> clientList = new ArrayList<>();
    private int i_Current;  // indice element en cours
    private int i_First;    // indice premier element affichable
    private int i_Last;     // indice dernier element affichable
    private int i_Aff;      // valeur elements affichables
    
    public static void main(String[] args) {
        Client_Controller controller = new Client_Controller();
        controller.menu();
    }
    
    public void menu() {
        int i_Choice = 0;
        Scanner sc = new Scanner(System.in);

        do {
            if (i_Aff != 0) {
                do {
                    C_CheckList();
                    System.out.println("\nClient's Menu");
                    System.out.println("***************");
                    System.out.println("1. Create");
                    System.out.println("2. Update");
                    System.out.println("3. Delete");
                    System.out.println("4. Next");
                    System.out.println("5. Previous");
                    System.out.println("6. Last");
                    System.out.println("7. First");
                    System.out.println("8. Select Client");
                    System.out.println("9. Exit");
                    System.out.print("Your choice ? : ");

                    if (sc.hasNextInt()) {
                        i_Choice = sc.nextInt();
                        sc.nextLine();

                        switch (i_Choice) {
                            case 1:
                                if (Client.getI_Pk() > 99) {
                                    System.out.println("Limit reached");
                                } else {
                                    C_Create(sc);
                                }
                                break;
                            case 2:
                                C_Update(sc);
                                break;
                            case 3:
                                clientList.get(i_Current).setB_Is_Deleted(true);
                                i_Aff--;
                                C_CheckList();
                                i_Current = i_Last;
                                break;
                            case 4:
                                C_Next_Client();
                                break;
                            case 5:
                                C_Previous_Client();
                                break;
                            case 6:
                                i_Current = i_Last;
                                break;
                            case 7:
                                i_Current = i_First;
                                break;
                            case 8:
                                C_Select();
                                break;
                            case 9:
                                System.out.println("Back to main menu...");
                                break;
                            default:
                                System.out.println("Wrong Choice, please select a new number");
                        }
                    } else {
                        System.out.println("Invalid input. Please enter a valid number.");
                        sc.nextLine();


                    }
                } while (i_Choice < 0 || i_Choice > 9);
            } else {
                do {
                    System.out.println("\nEmpty list");
                    System.out.println("Customer's Menu");
                    System.out.println("***************");
                    System.out.println("1. Create");
                    System.out.println("9. Exit");
                    System.out.print("Your choice ? : ");

                    if (sc.hasNextInt()) {
                        i_Choice = sc.nextInt();
                        sc.nextLine();

                        switch (i_Choice) {
                            case 1:
                                C_Create(sc);
                                break;
                            case 9:
                                System.out.println("Back to main menu...");
                                break;
                            default:
                                System.out.println("Wrong Choice, please select a new number");
                        }
                    } else {
                        System.out.println("Invalid input. Please enter a valid number.");
                        sc.nextLine();
                    }
                } while (i_Aff == 0);
            }
        } while (i_Choice != 9);
    }

我把System.out.println（“无效的输入。请输入一个有效的号码。因为否则控制台中的菜单会变得“疯狂”并不断上下移动而无法执行任何操作。 把这句话放在控制台发疯的时候：

if (sc.hasNextInt()) {
i_Choice = sc.nextInt();
sc.nextLine();

提前感谢您提供任何可能的建议来帮助我解决这个问题。