高纬度非矩形投影未显示 Cartopy 标签

你只需要设置gl = ax.gridlines(draw_labels=True,crs=ccrs.PlateCarree(),x_inline=False,y_inline=False)

import numpy as np
import cartopy
import matplotlib.pyplot as plt
import cartopy.crs as ccrs
from cartopy.mpl.gridliner import LONGITUDE_FORMATTER, LATITUDE_FORMATTER
import matplotlib.ticker as mticker
import matplotlib.path as mpath
import cartopy.feature as cf

"""
Plot Alaska
"""

# Map View Using Cartopy
fig = plt.figure(figsize=(8,6))

xmin=-163
xmax=-120
ymin=50
ymax=71

proj = ccrs.LambertConformal(central_longitude=(xmin+xmax)/2, central_latitude=(ymin+ymax)/2)
ax = fig.add_subplot(1, 1, 1, projection=proj)
n = 20
aoi = mpath.Path(
    list(zip(np.linspace(xmin,xmax, n), np.full(n,ymax))) + \
    list(zip(np.full(n,xmax), np.linspace(ymax,ymin, n))) + \
    list(zip(np.linspace(xmax,xmin, n), np.full(n,ymin))) + \
    list(zip(np.full(n,xmin), np.linspace(ymin,ymax, n)))
)
ax.set_boundary(aoi, transform=ccrs.PlateCarree())

# Plot Ocean Borders
ocean = cf.NaturalEarthFeature('physical','ocean',scale='50m',edgecolor='k',facecolor='lightblue',lw=1,linestyle='-')
ax.add_feature(ocean)
# Colored Land Background
land = cf.NaturalEarthFeature('physical','land',scale='50m',facecolor='snow',lw=1,linestyle='--')
ax.add_feature(land)

ax.set_extent([xmin,xmax,ymin,ymax],crs=ccrs.PlateCarree())
# Set gridlines to variable so you can manipulate them
gl = ax.gridlines(draw_labels=True,crs=ccrs.PlateCarree(),x_inline=False,y_inline=False)
gl.xlocator = mticker.FixedLocator([-160,-150,-140,-130,-120])
gl.ylocator = mticker.FixedLocator([50,55,60,65,70])
gl.xformatter = LONGITUDE_FORMATTER
gl.yformatter = LATITUDE_FORMATTER

plt.show()

编辑：

多亏了@swatchai，以下代码片段处理了右侧的 y 标签：

# Generate the plot to enable access to the labels' attributes
plt.draw()

# Iterate for the y-labels
# The right labels have x coordinates > 0
# The left labels < 0
for ea in gl.ylabel_artists:
    right_label = ea.get_position()[0] > 0
    # print(ea, ea.get_position()[0], ea.get_visible())
    if right_label:
        ea.set_visible(False)

plt.show()

查看@swatchai的完整答案了解更多详情！