提问人:Vasil Gramatov 提问时间:9/13/2023 最后编辑:Wernfried DomscheitVasil Gramatov 更新时间:9/13/2023 访问量:14
Oracle XML 多个节点
Oracle XML many nodes
问:
我在表 TEST_XML 中有以下 XML,其中一列“XMLTEXT”类型为 CLOB。
我希望在最后收到以下类似表格的结果:
User_Identity Product_offer_ID Keyword
[email protected] 11990 34861
[email protected] 11990 35357
[email protected] 11990 34841
XML 内容:
<MakeOfferEDRs>
<EDRs>
<MakeOffer status="6" bonusRuleID="119621" rewardActionID="191032" rewardTime="2023-09- 07T14:19:56" brandID="1" accountID="11712960353450032">
<Parameter name="[LOOPBACK_RECOMMENDED_OFFER]">1</Parameter>
<Products>
<Product keyword="34861" id="22146"/>
<Product keyword="35357" id="23146"/>
<Product keyword="34841" id="22140"/>
</Products>
<RecommendationParameters>
<ProductsNumber max="5"/>
<Strategies>
<Strategy name="5 RetSS 1 chain version_all MF Bands" id="16384"/>
</Strategies>
</RecommendationParameters>
<ProductOfferingID>11990</ProductOfferingID>
<UserIdentities>
<UserIdentity triggered="1" type="EMAIL">[email protected]</UserIdentity>
</UserIdentities>
<UseCaseRunId>20662</UseCaseRunId>
<UseCaseTypeId>5</UseCaseTypeId>
<ScheduledCampaignID>62179</ScheduledCampaignID>
</MakeOffer>
</EDRs>
基于这个查询,我尝试了几个查询,您会看到我可以在一行中获取原始值(列“关键字”结果)或将所有三个结果合并为一个值(列“关键字2”结果“348613535734841”):<Product id="22146" keyword="34861"/><Product id="23146" keyword="35357"/><Product id="22140" keyword="34841"/>
select x.* from VGRAMATOV.TEST_XML t, xmltable (
'MakeOfferEDRs/EDRs'
passing xmltype(t.xmltext)
columns
User_Identity XMLTYPE path './MakeOffer/UserIdentities/UserIdentity',
Product_Offering_ID XMLTYPE path './MakeOffer/ProductOfferingID',
Keyword XMLTYPE path './MakeOffer/Products/Product',
Keyword2 XMLTYPE path './MakeOffer/Products/Product/@keyword'
) as x
答:
0赞
MT0
9/13/2023
#1
下降到获取每个关键字,然后返回层次结构以获取其他值:Products/Product
SELECT x.*
FROM TEST_XML t
CROSS APPLY XMLTABLE(
'/MakeOfferEDRs/EDRs/MakeOffer/Products/Product'
PASSING XMLTYPE(t.xmltext)
COLUMNS
User_Identity VARCHAR2(200) path './../../UserIdentities/UserIdentity',
Product_Offering_ID NUMBER path './../../ProductOfferingID',
Keyword NUMBER path '@keyword'
) x
其中,对于示例数据:
CREATE TABLE test_xml (xmltext) AS
SELECT '<MakeOfferEDRs>
<EDRs>
<MakeOffer status="6" bonusRuleID="119621" rewardActionID="191032" rewardTime="2023-09- 07T14:19:56" brandID="1" accountID="11712960353450032">
<Parameter name="[LOOPBACK_RECOMMENDED_OFFER]">1</Parameter>
<Products>
<Product keyword="34861" id="22146"/>
<Product keyword="35357" id="23146"/>
<Product keyword="34841" id="22140"/>
</Products>
<RecommendationParameters>
<ProductsNumber max="5"/>
<Strategies>
<Strategy name="5 RetSS 1 chain version_all MF Bands" id="16384"/>
</Strategies>
</RecommendationParameters>
<ProductOfferingID>11990</ProductOfferingID>
<UserIdentities>
<UserIdentity triggered="1" type="EMAIL">[email protected]</UserIdentity>
</UserIdentities>
<UseCaseRunId>20662</UseCaseRunId>
<UseCaseTypeId>5</UseCaseTypeId>
<ScheduledCampaignID>62179</ScheduledCampaignID>
</MakeOffer>
</EDRs>
</MakeOfferEDRs>' FROM DUAL;
输出:
USER_IDENTITY | PRODUCT_OFFERING_ID | 关键词 |
---|---|---|
[电子邮件保护] | 11990 | 34861 |
[电子邮件保护] | 11990 | 35357 |
[电子邮件保护] | 11990 | 34841 |
评论
0赞
Vasil Gramatov
9/13/2023
谢谢!赞赏!
评论