提问人:Sepp Hofer 提问时间:8/11/2021 最后编辑:mickmackusaSepp Hofer 更新时间:8/11/2021 访问量:508
从 html 文档中限定的 span 标记中获取类值和文本
Get class value and text from qualifying span tags in html document
问:
请帮助我使用以下模式进行preg_match_all
如何更改我的模式以获得所需的输出?
在字符串中,搜索类名类似于 '' ( OR OR OR 的标签email_
email_
email_p_12
email_22
email_xx
)
获取标签之间的文本<span class=" xx email_xx xx "> THE EMAIL ADDRESS </span>
获取以“email_”开头的类名
这是我的模式:$pattern = '~<span class=\"((.*?)*)*(email_(.*?))?(.*?)\">(.*?)</span>~';
我需要的是这样的数组:
Array
(
[0] => Array
(
[mail] => [email protected]
[class] => email_p_14
)
[1] => Array
(
[mail] => [email protected]
[class] => email_p_22
)
[2] => Array
(
[mail] => [email protected]
[class] => email_
)
[3] => Array
(
[mail] => [email protected]
[class] => email_
)
)
文件:
<?php
$string = '
<p>
Lorem ipsum dolor sit amet,
consectetur adipisicing elit,
sed do eiusmod tempor incididunt ut
<span class=" red email_p_14">[email protected]</span>
dolore magna aliqua. Ut enim ad minim veniam,
quis nostrud exercitation ullamco laboris nisi ut aliquip ex ea consequat.
Duis aute irure in reprehenderit in voluptate velit
<span class="email_p_22">[email protected]</span>
dolore eu fugiat nulla pariatur. Excepteur sint occaecat cupidatat non proident,
sunt in culpa qui officia deserunt mollit
<span class="blue email_ green">[email protected]</span>
laborum. Donec elementum ligula.
Quis nostrud exercitation ullamco
<span class="blue email_ green black">[email protected]</span>
aliquip ex ea consequat.
</p>';
/* Looking for these:
<span class=" red email_p_14">[email protected]</span>
<span class="email_p_22">[email protected]</span>
<span class="blue email_ green">[email protected]</span>
<span class="blue email_ green black">[email protected]</span>
*/
$pattern = '~<span class=\"((.*?)*)*(email_(.*?))?(.*?)\">(.*?)</span>~';
preg_match_all($pattern, $string, $m);
$clean_array = array_filter(array_map('array_filter', $m));
ksort($clean_array);
$output = Array();
foreach($clean_array as $row) {
foreach($row as $key => $val){
$output[$key][]=$val;
}
}
print("<pre>".print_r($output,true)."</pre>");
这是我得到的:
Array
(
[0] => Array
(
[0] => [email protected]
[1] => red email_p_14
[2] => [email protected]
)
[1] => Array
(
[0] => [email protected]
[1] => email_
[2] => p_22
[3] => [email protected]
)
[2] => Array
(
[0] => [email protected]
[1] => blue email_ green
[2] => [email protected]
)
[3] => Array
(
[0] => [email protected]
[1] => blue email_ green black
[2] => [email protected]
)
)
我需要的是这样的数组:
Array
(
[0] => Array
(
[mail] => [email protected]
[class] => email_p_14
)
[1] => Array
(
[mail] => [email protected]
[class] => email_p_22
)
[2] => Array
(
[mail] => [email protected]
[class] => email_
)
[3] => Array
(
[mail] => l[email protected]
[class] => email_
)
)
*/
答:
1赞
The fourth bird
8/11/2021
#1
对于类值,您可以使用此模式,该模式使用重复捕获组的组合,其中 all 实际上是可选的。((.*?)*)*(email_(.*?))?(.*?)
对于您使用的电子邮件地址,它与任何字符 non greedy 匹配并且与类似电子邮件的模式不匹配。(.*?)
您可以使用命名捕获组来获取密钥,并且:mail
class
<span[^<>]*\bclass="[^"]*(?<class>email_[^\s"]*)[^"]*">\h*(?<mail>[^\s@]+@[^\s@]+)\h*<\/span>
在结果中,删除数字键:
$re = '`<span[^<>]*\bclass="[^"]*(?<class>email_[^\s"]*)[^"]*">\h*(?<mail>[^\s@]+@[^\s@]+)\h*<\/span>`';
$str = '<span class=" xx email_p_14 xx "> [email protected] </span>';
preg_match_all($re, $str, $matches, PREG_SET_ORDER, 0);
print_r(array_filter($matches[0], function ($k) { return !is_numeric($k); }, ARRAY_FILTER_USE_KEY));
输出
Array
(
[class] => email_p_14
[mail] => [email protected]
)
您还可以做的是查看 DOMDocument,找到类名以 email_ 开头的跨度,然后匹配电子邮件地址的跨度值,例如模式。
然后,您可以使用键和值构建数组。
例如
$str = '<span class=" xx email_p_14 xx "> [email protected] </span>';
$dom = new DomDocument();
$dom->loadHTML($str, LIBXML_HTML_NOIMPLIED | LIBXML_HTML_NODEFDTD);
$doc = new DOMXPath($dom);
$items = $doc->query("//span[contains(@class, 'email_')]");
foreach ($items as $item) {
$class = array_filter(explode(' ', $item->getAttribute('class')), function($x) {
return substr( $x, 0, 6 ) === "email_";
});
print_r($class);
echo $item->nodeValue;
}
输出
Array
(
[2] => email_p_14
)
[email protected]
2赞
mickmackusa
8/11/2021
#2
使用 DOMDocument 和 XPath 解析 html。定位到适当的节点后,挖掘并提取数据,然后将新的子数组推送到结果中。
代码:(演示)
$dom = new DOMDocument;
libxml_use_internal_errors(true);
$dom->loadHTML($string);
$xpath = new DOMXPath($dom);
$result = [];
foreach ($xpath->query("//span[starts-with(@class, 'email_') or contains(@class, ' email_')]") as $span) {
$result[] = [
'mail' => $span->nodeValue,
'class' => preg_replace(
'~.*\b(email_\S*).*~',
'$1',
$span->getAttribute('class')
)
];
}
var_export($result);
输出:
array (
0 =>
array (
'mail' => '[email protected]',
'class' => 'email_p_14',
),
1 =>
array (
'mail' => '[email protected]',
'class' => 'email_p_22',
),
2 =>
array (
'mail' => '[email protected]',
'class' => 'email_',
),
3 =>
array (
'mail' => '[email protected]',
'class' => 'email_',
),
)
评论
1赞
Sepp Hofer
8/11/2021
多谢!这是按要求工作的。我认为这个答案最能涵盖这个问题。也非常紧凑,清晰和优雅。
0赞
The fourth bird
8/12/2021
不错的解决方案,值得更多赞誉。++
评论