提问人：JJH 提问时间：10/9/2022 最后编辑：HedgeHogJJH 更新时间：10/9/2022 访问量：1015
如何解析HTML元素？
How to parse HTML elements?
问：
我正在寻找从 Github 网页列表中提取“类别”下列出的项目。
在示例代码中，我能够识别需要解析的文本块，但是当我解析文本时，输出如下所示：
['\n\n\n \n\n \n\n \n\n \n\n \n\n \n\n \n\n \n\n \n\n \n\n \n\n ', '\n\n Continuous integration\n\n\n Security\n\n']
我正在寻找的输出是：
[Continuous integration, Security]
如何更改代码行以获得最终结果？get_text()
from bs4 import BeautifulSoup
import requests
websites = ['https://github.com/marketplace/actions/yq-portable-yaml-processor','https://github.com/marketplace/actions/TruffleHog-OSS']
for links in websites:
URL = requests.get(links)
detailsoup = BeautifulSoup(URL.content, "html.parser")
categories = detailsoup.findAll('div', {'class': 'ml-n1 clearfix'})
print(categories)
categoriesList = [categories.get_text() for categories in categories]
print(categoriesList)
# keep only 1st element & maintain type as list
categoriesList = categoriesList[1:2]
if not categoriesList:
categoriesList.insert(0, 'Error')
答：
1赞
HedgeHog
10/9/2022
#1
只需添加参数：strip=True
categoriesList = [categories.get_text(strip=True) for category in categories]
此外，请尝试更具体地选择您的元素：
categories = detailsoup.find_all('a', {'class': 'topic-tag'})
在较新的代码中，避免使用旧的语法 findAll（），而是使用 find_all（） 或 select（） 和 css 选择器 - 欲了解更多信息，请花一分钟时间检查文档
例
from bs4 import BeautifulSoup
import requests
websites = ['https://github.com/marketplace/actions/yq-portable-yaml-processor','https://github.com/marketplace/actions/TruffleHog-OSS']
for links in websites:
URL = requests.get(links)
detailsoup = BeautifulSoup(URL.content, "html.parser")
categories = detailsoup.find_all('a', {'class': 'topic-tag'})
categoriesList = [categories.get_text(strip=True) for category in categories]
print(categoriesList)
评论
get_text()has - 但您始终可以将 -loop 与（和其他函数）一起使用来修改列表。strip=Truefor.strip()