将整数（纪元时间（以毫秒为单位）转换为 PrimitiveDateTime-解网

问：

我一直在尝试，但这很困难，因为类型不完全匹配。

我目前的尝试：

use ::time::{PrimitiveDateTime, OffsetDateTime};
use std::time::{UNIX_EPOCH, Duration};
use chrono::{DateTime, Utc, NaiveDateTime};


fn my_func() {
    let timestamp:u64 = 1696443084 // {integer from http request, representing timestamp in ms since epoch}
    let d:SystemTime = UNIX_EPOCH + Duration::from_secs(timestamp/1000);
    let datetime:DateTime<Utc> = DateTime::<Utc>::from(d); // ideally want to replace this line with one where I get a DateTime (and not DateTime<Utc>) from the integer.
    let created_at:PrimitiveDateTime = PrimitiveDateTime::new(datetime.date_naive(), datetime.time());
}

我的错误消息（编译）如下：

106 | ... = PrimitiveDateTime::new(datetime.date_naive(), datetime.time(...
    |       ^^^^^^^^^^^^^^^^^^^^^^ ---------------------  --------------- expected `Time`, found `NaiveTime`
    |                              |
    |                              expected `Date`, found `NaiveDate`
    |
note: associated function defined here
   --> /.../time-0.3.23/src/primitive_date_time.rs:92:18
    |
92  |     pub const fn new(date: ...
    |                  ^^^

我需要使用 PrimitiveDateTime，因为这是时间戳在 psql 数据库中的存储方式。

PostgreSQL 日期 Rust 时间戳

经过大量研究，我发现有一种方法可以将它们转换为：from_unix_timestamp_nanos（）（只有秒和纳秒的方法，毫秒没有方法）。但是没有方法可以将转换为，但似乎有效。OffsetDateTimeOffsetDateTimePrimitiveDateTimePrimitiveDateTime::new(dt.date(), dt.time())

所以：

use time::{OffsetDateTime, PrimitiveDateTime};

fn main() {
    let timestamp: u64 = 1696443084; // {integer from http request, representing timestamp in ms since epoch}
    let created_at =
        OffsetDateTime::from_unix_timestamp_nanos(i128::from(timestamp) * 1_000_000).unwrap();
    let created_at = PrimitiveDateTime::new(created_at.date(), created_at.time());
    dbg!(created_at);
}

将整数（纪元时间（以毫秒为单位）转换为 PrimitiveDateTime

Convert integer (epoch time in ms) to PrimitiveDateTime

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