如何从小时范围之间的日期数组中删除元素 Rails？

How to remove elements from array of dates between hours ranges Rails?

提问人：Codrin 提问时间：2/25/2023 最后编辑：BijendraCodrin 更新时间：2/26/2023 访问量：62

问：

我的数组是由

   start_date = (Date.today + 10.hours + 30.minutes).to_datetime       
   end_date = (Date.today + 1.day + 18.hours).to_datetime
   period = 0.5/24 
   array = start_date.step(end_date, period).to_a

这是结果（但此结果最多将涵盖 62 天）

array = 
  [Sat, 25 Feb 2023 10:30:00 +0000, Sat, 25 Feb 2023 11:00:00 +0000, Sat, 25 Feb 2023 11:30:00 +0000, 
  Sat, 25 Feb 2023 12:00:00 +0000, Sat, 25 Feb 2023 12:30:00 +0000, Sat, 25 Feb 2023 13:00:00 +0000,
  Sat, 25 Feb 2023 13:30:00 +0000, Sat, 25 Feb 2023 14:00:00 +0000, Sat, 25 Feb 2023 14:30:00 +0000, 
  Sat, 25 Feb 2023 15:00:00 +0000, Sat, 25 Feb 2023 15:30:00 +0000, Sat, 25 Feb 2023 16:00:00 +0000, 
  Sat, 25 Feb 2023 16:30:00 +0000, Sat, 25 Feb 2023 17:00:00 +0000, Sat, 25 Feb 2023 17:30:00 +0000, 
  Sat, 25 Feb 2023 18:00:00 +0000, Sat, 25 Feb 2023 18:30:00 +0000, Sat, 25 Feb 2023 19:00:00 +0000, 
  Sat, 25 Feb 2023 19:30:00 +0000, Sat, 25 Feb 2023 20:00:00 +0000, Sat, 25 Feb 2023 20:30:00 +0000, 
  Sat, 25 Feb 2023 21:00:00 +0000, Sat, 25 Feb 2023 21:30:00 +0000, Sat, 25 Feb 2023 22:00:00 +0000, 
  Sat, 25 Feb 2023 22:30:00 +0000, Sat, 25 Feb 2023 23:00:00 +0000, Sat, 25 Feb 2023 23:30:00 +0000, 
  Sun, 26 Feb 2023 00:00:00 +0000, Sun, 26 Feb 2023 00:30:00 +0000, Sun, 26 Feb 2023 01:00:00 +0000, 
  Sun, 26 Feb 2023 01:30:00 +0000, Sun, 26 Feb 2023 02:00:00 +0000, Sun, 26 Feb 2023 02:30:00 +0000, 
  Sun, 26 Feb 2023 03:00:00 +0000, Sun, 26 Feb 2023 03:30:00 +0000, Sun, 26 Feb 2023 04:00:00 +0000, 
  Sun, 26 Feb 2023 04:30:00 +0000, Sun, 26 Feb 2023 05:00:00 +0000, Sun, 26 Feb 2023 05:30:00 +0000, 
  Sun, 26 Feb 2023 06:00:00 +0000, Sun, 26 Feb 2023 06:30:00 +0000, Sun, 26 Feb 2023 07:00:00 +0000, 
  Sun, 26 Feb 2023 07:30:00 +0000, Sun, 26 Feb 2023 08:00:00 +0000, Sun, 26 Feb 2023 08:30:00 +0000, 
  Sun, 26 Feb 2023 09:00:00 +0000, Sun, 26 Feb 2023 09:30:00 +0000, Sun, 26 Feb 2023 10:00:00 +0000, 
  Sun, 26 Feb 2023 10:30:00 +0000, Sun, 26 Feb 2023 11:00:00 +0000, Sun, 26 Feb 2023 11:30:00 +0000, 
  Sun, 26 Feb 2023 12:00:00 +0000, Sun, 26 Feb 2023 12:30:00 +0000, Sun, 26 Feb 2023 13:00:00 +0000, 
  Sun, 26 Feb 2023 13:30:00 +0000, Sun, 26 Feb 2023 14:00:00 +0000, Sun, 26 Feb 2023 14:30:00 +0000, 
  Sun, 26 Feb 2023 15:00:00 +0000, Sun, 26 Feb 2023 15:30:00 +0000, Sun, 26 Feb 2023 16:00:00 +0000, 
  Sun, 26 Feb 2023 16:30:00 +0000, Sun, 26 Feb 2023 17:00:00 +0000, Sun, 26 Feb 2023 17:30:00 +0000, 
  Sun, 26 Feb 2023 18:00:00 +0000]

从这个数组中，我想删除从每天开始到 10：29 点到每天 18：00 之后到一天结束之间的所有日期时间。

期望结果：

array = 
  [Sat, 25 Feb 2023 10:30:00 +0000, Sat, 25 Feb 2023 11:00:00 +0000, ....... Sat, 25 Feb 2023 18:00:00 +0000,
  Sun, 26 Feb 2023 10:30:00 +0000, Sun, 26 Feb 2023 11:00:00 +0000, ....... Sun, 26 Feb 2023 18:00:00 +0000]

我试过了

 w_start_time = (start_date + 8.hours + 1.minute).strftime('%k:%M:%S')
 w_end_time = (start_date - 1.minute).strftime('%k:%M:%S')
        
 hours = array_of_datestimes.reject! { |n| n.strftime('%k:%M:%S').between?(w_start_time, w_end_time) }

这将返回 nil

有人可以帮我吗？

谢谢

ruby-on-rails 日期 时间

评论

答：

0赞 Vit Ruve 2/25/2023 #1

也许你应该试试这个：

array = array.reject { |date| 
  (date.hour < 10 || (date.hour == 10 && date.min < 30)) || 
  (date.hour >= 18) 
}

评论

0赞 Codrin 2/25/2023
谢谢你，这几乎可以工作，问题是它也在删除，我想保留Sat, 25 Feb 2023 18:00:00 +0000Sun, 26 Feb 2023 18:00:00 +0000
0赞 maya_nk99 2/25/2023 #2

这对我有用

 w_start_time = (start_date - 1.minute).strftime('%k:%M:%S')
 w_end_time = (start_date + 8.hours - 1.minute).strftime('%k:%M:%S')

 hours = array.filter { |n| n.strftime('%k:%M:%S').between?(w_start_time, w_end_time) }
2赞 Cary Swoveland 2/26/2023 #3

这里有两种方法。

转换为分钟。

array.accept! { |date| (630..1080).cover?(60*date.hour + date.min) }

其中和 .参见 Range#cover？，它只使用范围端点，因此非常高效。630 = 60*10+301080 = 60*18

计数以确定要保留的元素

我们看到，在第一天，我们希望保留第一个

(18.0 - 10.5)/0.5 + 1 = 16

元素。由于每天有 48 个 30 分钟的间隔，我们希望删除下一个

48 - 16 = 32

元素。因此，我们可以创建一个枚举器，它生成 16 次，然后是 32 次，然后重复，如果枚举器的相应值等于 .我们可以使用 Array#cycle 来创建这个枚举器。falsetruearraytrue

reject = ([false]*16 + [true]*32).cycle
  #=> #<Enumerator: [false, false, false, false, false, false, false,
  #     false, false, false, false, false, false, false, false, false,
  #     true, true, true, true, true, true, true, true, true, true,
  #     true, true, true, true, true, true, true, true, true, true,
  #     true, true, true, true, true, true, true, true, true, true,
  #     true, true]:cycle>

然后我们简单地写

array.reject! { reject.next }

为了说明此计算，假设持有一个与给定数组的元素相对应的字符串数组。arrayDateTime

array = [
  "Sat, 25 Feb 2023 10:30:00 +0000", "Sat, 25 Feb 2023 11:00:00 +0000", 
  "Sat, 25 Feb 2023 11:30:00 +0000", "Sat, 25 Feb 2023 12:00:00 +0000", 
  "Sat, 25 Feb 2023 12:30:00 +0000", "Sat, 25 Feb 2023 13:00:00 +0000",
  "Sat, 25 Feb 2023 13:30:00 +0000", "Sat, 25 Feb 2023 14:00:00 +0000",
  "Sat, 25 Feb 2023 14:30:00 +0000", "Sat, 25 Feb 2023 15:00:00 +0000",
  "Sat, 25 Feb 2023 15:30:00 +0000", "Sat, 25 Feb 2023 16:00:00 +0000", 
  "Sat, 25 Feb 2023 16:30:00 +0000", "Sat, 25 Feb 2023 17:00:00 +0000",
  "Sat, 25 Feb 2023 17:30:00 +0000", "Sat, 25 Feb 2023 18:00:00 +0000",
  "Sat, 25 Feb 2023 18:30:00 +0000", "Sat, 25 Feb 2023 19:00:00 +0000",
  "Sat, 25 Feb 2023 19:30:00 +0000", "Sat, 25 Feb 2023 20:00:00 +0000",
  "Sat, 25 Feb 2023 20:30:00 +0000", "Sat, 25 Feb 2023 21:00:00 +0000",
  "Sat, 25 Feb 2023 21:30:00 +0000", "Sat, 25 Feb 2023 22:00:00 +0000",
  "Sat, 25 Feb 2023 22:30:00 +0000", "Sat, 25 Feb 2023 23:00:00 +0000",
  "Sat, 25 Feb 2023 23:30:00 +0000", "Sun, 26 Feb 2023 00:00:00 +0000",
  "Sun, 26 Feb 2023 00:30:00 +0000", "Sun, 26 Feb 2023 01:00:00 +0000",
  "Sun, 26 Feb 2023 01:30:00 +0000", "Sun, 26 Feb 2023 02:00:00 +0000",
  "Sun, 26 Feb 2023 02:30:00 +0000", "Sun, 26 Feb 2023 03:00:00 +0000",
  "Sun, 26 Feb 2023 03:30:00 +0000", "Sun, 26 Feb 2023 04:00:00 +0000",
  "Sun, 26 Feb 2023 04:30:00 +0000", "Sun, 26 Feb 2023 05:00:00 +0000",
  "Sun, 26 Feb 2023 05:30:00 +0000", "Sun, 26 Feb 2023 06:00:00 +0000",
  "Sun, 26 Feb 2023 06:30:00 +0000", "Sun, 26 Feb 2023 07:00:00 +0000",
  "Sun, 26 Feb 2023 07:30:00 +0000", "Sun, 26 Feb 2023 08:00:00 +0000",
  "Sun, 26 Feb 2023 08:30:00 +0000", "Sun, 26 Feb 2023 09:00:00 +0000",
  "Sun, 26 Feb 2023 09:30:00 +0000", "Sun, 26 Feb 2023 10:00:00 +0000",
  "Sun, 26 Feb 2023 10:30:00 +0000", "Sun, 26 Feb 2023 11:00:00 +0000",
  "Sun, 26 Feb 2023 11:30:00 +0000", "Sun, 26 Feb 2023 12:00:00 +0000",
  "Sun, 26 Feb 2023 12:30:00 +0000", "Sun, 26 Feb 2023 13:00:00 +0000",
  "Sun, 26 Feb 2023 13:30:00 +0000", "Sun, 26 Feb 2023 14:00:00 +0000",
  "Sun, 26 Feb 2023 14:30:00 +0000", "Sun, 26 Feb 2023 15:00:00 +0000",
  "Sun, 26 Feb 2023 15:30:00 +0000", "Sun, 26 Feb 2023 16:00:00 +0000", 
  "Sun, 26 Feb 2023 16:30:00 +0000", "Sun, 26 Feb 2023 17:00:00 +0000",
  "Sun, 26 Feb 2023 17:30:00 +0000", "Sun, 26 Feb 2023 18:00:00 +0000"
]

然后

array.reject! { reject.next }
  #=> ["Sat, 25 Feb 2023 10:30:00 +0000", "Sat, 25 Feb 2023 11:00:00 +0000",
  #    "Sat, 25 Feb 2023 11:30:00 +0000", "Sat, 25 Feb 2023 12:00:00 +0000",
  #    "Sat, 25 Feb 2023 12:30:00 +0000", "Sat, 25 Feb 2023 13:00:00 +0000",
  #    "Sat, 25 Feb 2023 13:30:00 +0000", "Sat, 25 Feb 2023 14:00:00 +0000",
  #    "Sat, 25 Feb 2023 14:30:00 +0000", "Sat, 25 Feb 2023 15:00:00 +0000",
  #    "Sat, 25 Feb 2023 15:30:00 +0000", "Sat, 25 Feb 2023 16:00:00 +0000",
  #    "Sat, 25 Feb 2023 16:30:00 +0000", "Sat, 25 Feb 2023 17:00:00 +0000",
  #    "Sat, 25 Feb 2023 17:30:00 +0000", "Sat, 25 Feb 2023 18:00:00 +0000",
  #    "Sun, 26 Feb 2023 10:30:00 +0000", "Sun, 26 Feb 2023 11:00:00 +0000",
  #    "Sun, 26 Feb 2023 11:30:00 +0000", "Sun, 26 Feb 2023 12:00:00 +0000",
  #    "Sun, 26 Feb 2023 12:30:00 +0000", "Sun, 26 Feb 2023 13:00:00 +0000",
  #    "Sun, 26 Feb 2023 13:30:00 +0000", "Sun, 26 Feb 2023 14:00:00 +0000",
  #    "Sun, 26 Feb 2023 14:30:00 +0000", "Sun, 26 Feb 2023 15:00:00 +0000",
  #    "Sun, 26 Feb 2023 15:30:00 +0000", "Sun, 26 Feb 2023 16:00:00 +0000",
  #    "Sun, 26 Feb 2023 16:30:00 +0000", "Sun, 26 Feb 2023 17:00:00 +0000",
  #    "Sun, 26 Feb 2023 17:30:00 +0000", "Sun, 26 Feb 2023 18:00:00 +0000"]

这显然适用于任何天数，前提是数组的第一个元素对应于第一天。与数组的最后一个元素关联的时间不需要是 。10:3018:00

这种计算将相对较快，因为它确实需要将每个元素分解为小时和分钟。DateTime

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