提问人:Learning 提问时间:10/16/2021 更新时间:10/16/2021 访问量:240
如何读取映射文件(0和1)并将其存储到C++中的数组中?
How to read a map file(0s and 1s) and store it into array in C++?
问:
我想读取一个名为 maze 的文件.txt其中包含 0 和 1(指示是否被阻止),并将文件中的每个元素存储到名为 maze[17][17] 的二维数组中。
迷宫.txt就像:
11111111111111111
10000000000101001
10100111111001101
10101100001010101
10111010100000001
10000011011111001
11111000010001001
10110010000100101
10110100101110111
10000111000100001
10110011000100101
10110010000011101
10111001111110101
10110010000010001
10010111110101111
10010000000000001
11111111111111111
我搜索过的最接近的答案是使用加号(请参阅:从 c++ 中的文件读取到行尾?getline()
istringstream()
)
但是,上述解决方案仅适用于我在它们之间放置空格时,例如:
1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1
1 0 0 0 0 0 0 0 0 0 0 1 0 1 0 0 1
1 0 1 0 0 1 1 1 1 1 1 0 0 1 1 0 1
1 0 1 0 1 1 0 0 0 0 1 0 1 0 1 0 1
1 0 1 1 1 0 1 0 1 0 0 0 0 0 0 0 1
1 0 0 0 0 0 1 1 0 1 1 1 1 1 0 0 1
1 1 1 1 1 0 0 0 0 1 0 0 0 1 0 0 1
1 0 1 1 0 0 1 0 0 0 0 1 0 0 1 0 1
1 0 1 1 0 1 0 0 1 0 1 1 1 0 1 1 1
1 0 0 0 0 1 1 1 0 0 0 1 0 0 0 0 1
1 0 1 1 0 0 1 1 0 0 0 1 0 0 1 0 1
1 0 1 1 0 0 1 0 0 0 0 0 1 1 1 0 1
1 0 1 1 1 0 0 1 1 1 1 1 1 0 1 0 1
1 0 1 1 0 0 1 0 0 0 0 0 1 0 0 0 1
1 0 0 1 0 1 1 1 1 1 0 1 0 1 1 1 1
1 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 1
1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1
我的代码:
void read_maze(int map[17][17]) {
ifstream read_file("D:/maze.txt", ios::in);
if (read_file.good()){
string str;
int i = 0;
while (getline(read_file, str) {
int j = 0;
istringstream ss(str);
int num;
while (ss >> num)
{
map[i][j] = num;
j++;
}
i++;
}
}
for (int i = 0; i < 17; i++)
{
for (int j = 0; j < 17; j++)
{
cout << map[i][j];
}
cout << endl;
}
read_file.close();
}
输出就像原始迷宫.txt
那么,我应该怎么做才能在不修改其内容的情况下将迷宫 .txt 中的每个元素存储到数组中?
我相信可能有一些更简单的解决方案,但由于我是C++的新手,我找不到任何像我这样的类似情况。
希望有人能根据上面的代码提供详细的代码。 多谢!
答:
0赞
Pepijn Kramer
10/16/2021
#1
你可以这样做:
#include <array>
#include <iostream>
#include <string>
#include <sstream>
std::istringstream file{
"11111111111111111\n"
"10000000000101001\n"
"10100111111001101\n"
"10101100001010101\n"
"10111010100000001\n"
"10000011011111001\n"
"11111000010001001\n"
"10110010000100101\n"
"10110100101110111\n"
"10000111000100001\n"
"10110011000100101\n"
"10110010000011101\n"
"10111001111110101\n"
"10110010000010001\n"
"10010111110101111\n"
"10010000000000001\n"
"11111111111111111\n"
};
auto load(std::istream& is)
{
// use std::array, you can actually return that from functions
// and avoids the pain of having to work with double pointers
// and manual memory managment.
std::array<std::array<char, 17>, 17> map{};
// loop over all rows in the map
for (auto& row : map)
{
// loop over all the values in a row
for (auto& value : row)
{
// read one value from the file
is >> value;
}
// newlines will be skipped.
}
// and return your map (2d array)
return map;
}
int main()
{
// file is a stringstream now but
// is easily replaced by a filestream
// (stringstream just makes testing more easy)
auto map = load(file);
// just another range based for loop
// to display the map we read from file.
for (const auto& row : map)
{
for (const auto& value : row)
{
std::cout << value;
}
std::cout << "\n";
}
}
评论
0赞
Learning
10/16/2021
感谢@Pepijn克莱默的回答,但对于像我这样的新手来说,这似乎仍然很困难!
0赞
Tianshi 25
10/16/2021
#2
您的代码只需稍作修改即可工作。喜欢这个:
#include <fstream>
#include <iostream>
#include <sstream>
using namespace std;
void read_maze(int map[17][17]) {
ifstream read_file("maze.txt", ios::in);
if (read_file.good()){
string str;
int i = 0;
while (getline(read_file, str)) {
// read line and process each digit
for (int j=0; j < str.size(); j++) {
map[i][j] = str[j] - '0';
}
i++;
}
}
for (int i = 0; i < 17; i++)
{
for (int j = 0; j < 17; j++)
{
cout << map[i][j] << " ";
}
cout << endl;
}
read_file.close();
}
int main() {
int map[17][17] = {};
read_maze(map);
}
评论
0赞
hivert
10/17/2021
最好解释出了什么问题并显示更正,而不是仅仅丢弃一大堆更正的代码。
评论
read_file >> c;
num = c - '0';