提问人：Paul Pulcini 提问时间：11/17/2018 更新时间：11/17/2018 访问量：40
文本文件问题 （Visual C++）
Text file Issues (Visual C++)
问：
我正在尝试使程序提示用户输入文件的名称，然后提示他们输入要删除的单词。 有没有办法在不使 main 之外的任何功能的情况下做到这一点？ （提前致谢！ 这是我到目前为止的代码：
ofstream outFile;
string in;
char in2[800];
char fileName = ' ';
while (in != "XXXX") {
cout << "What do you want to name the file? Enter a name or enter XXXX to quit.\n";
cin >> in;
for (int i = 0; i < in.length(); i++)
{
fileName += in[i];
}
outFile.open(in + ".txt");
if (outFile.fail())
{
outFile << "Can't do it.";
}
else
{
cout << "What do you want in it?\n";
cin >> in2;
cin.getline(in2, sizeof(in2));
outFile << in2;
}
outFile.close();
ifstream reader;
string oneLine;
reader.open(in + ".txt");
if (reader.fail())
{
cout << "Could not read file.\n";
return 0;
}
else
{
reader.clear();
reader.seekg(60L, ios::beg);
getline(reader, oneLine);
cout << "Is there something you'd like to remove from " << in << ".txt?\n";
cin >> in2;
ofstream write("tmp.txt");
while (getline(reader, oneLine)) {
if (oneLine != in2)
write << oneLine << endl;
}
reader.close();
write.close();
remove(fileName + ".txt");
rename("tmp.txt", fileName + ".txt");
return 0;
}
return 0;
}
答：
0赞
Barmak Shemirani
11/17/2018
#1
while (in != "XXXX") { cout << "What do you want to name the file? Enter a name or enter XXXX to quit.\n"; ... }
如果你进入循环，就不会退出。它将尝试处理其余的代码。XXXX
char fileName = ' ';声明单个字符。您需要一个字符数组。更好的是，将其声明为std::string fileName;
remove(fileName + ".txt");不会编译，因为是 C 函数。C 不支持类，也不知道如何处理 .你想提供一个 C 字符串，你可以用 以下是一些建议：removestd::stringfileName.c_str()
int main()
{
ofstream outFile;
string fileName;
string text;
for(;;)
{
cout << "What do you want to name the file?\n";
cout << "Enter a name or enter 999 to quit.\n";
cin >> fileName;
if(fileName == "999")
break;
fileName += ".txt";
outFile.open(fileName);
if(outFile.fail())
{
cout << "Can't do it.";
continue;
}
else
{
for(;;)
{
cout << "What do you want in it?\n";
cout << "Enter a name or enter 999 to stop.\n";
cin >> text;
if(text == "999")
break;
outFile << text << endl;
}
}
outFile.close();
ifstream reader;
reader.open(fileName);
if(reader.fail())
{
cout << "Could not read file.\n";
}
else
{
cout << "Is there something you'd like to remove from " << fileName << "?\n";
cin >> text;
string oneLine;
ofstream write("tmp.txt");
while(getline(reader, oneLine))
{
if(oneLine != text)
write << oneLine << endl;
}
reader.close();
write.close();
remove(fileName.c_str());
rename("tmp.txt", fileName.c_str());
break;
}
}
}
评论
0赞
Paul Pulcini
11/19/2018
谢谢Barmak！这完全符合我的意愿。
评论
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