如何调用父类的实例方法？

问：

我找到了一种方法，如下实例：

将实例方法更改为类方法以达到我想要的结果。

class MyClassA:
    name = 'MyClassA'

    def __init__(self):
        self.name = 'instance name'
        self.print_name()
        pass

    @classmethod
    def print_name(cls):
        name = cls.name
        print(name)

    @classmethod
    def init(cls):
        cls.name = 'class name'


class MyClassB(MyClassA):
    pass


MyClassB.init()
c1 = MyClassB()

我想设置并获取.MyClassB.name='class name'MyClassB.name

如何修改代码？

class MyClassA:
    name = 'MyClassA'

    def __init__(self):
        self.name = 'instance name'
        self.print_name()
        pass

    def print_name(self):
        name = super().name
        print(name)

    @classmethod
    def init(cls):
        cls.name = 'class name'


class MyClassB(MyClassA):
    pass


MyClassB.init()
c1 = MyClassB()

我想调用子类中父类实例的方法。c1.print_name()

如何修改代码以获取输出：'class name'

我的代码如下：

class MyClassA:
    def __init__(self):
        self.print_name()
        pass

    def print_name(self):
        name = super().name
        print(name)

    @classmethod
    def init(cls):
        cls.name = 'class name'


class MyClassB(MyClassA):
    pass


MyClassB.init()
c1 = MyClassB()

错误如下：

Traceback (most recent call last):
  File "D:\Anaconda3\lib\site-packages\IPython\core\interactiveshell.py", line 3437, in run_code
    exec(code_obj, self.user_global_ns, self.user_ns)
  File "<ipython-input-3-0a688d5bfaa6>", line 20, in <module>
    c1 = MyClassB()
  File "<ipython-input-3-0a688d5bfaa6>", line 3, in __init__
    self.print_name()
  File "<ipython-input-3-0a688d5bfaa6>", line 7, in print_name
    name = super().name
AttributeError: 'super' object has no attribute 'name'